### All High School Math Resources

## Example Questions

### Example Question #31 : Quadrilaterals

A rectangle has a width of 2*x*. If the length is five more than 150% of the width, what is the perimeter of the rectangle?

**Possible Answers:**

10(*x* + 1)

6*x*^{2} + 5

5*x* + 5

6*x*^{2} + 10*x*

5*x* + 10

**Correct answer:**

10(*x* + 1)

Given that *w* = 2*x* and *l* = 1.5*w* + 5, a substitution will show that *l* = 1.5(2*x*) + 5 = 3*x* + 5.

*P* = 2*w* + 2*l* = 2(2*x*) + 2(3*x* + 5) = 4*x* + 6*x* + 10 = 10*x* + 10 = 10(*x* + 1)

### Example Question #1 : How To Find The Perimeter Of A Rectangle

What is the perimeter of the below rectangle in simplest radical form?

**Possible Answers:**

5√3

10√3

4√3 + 2√27

7√27

**Correct answer:**

10√3

The perimeter of a figure is the sum of the lengths of all of its sides. The perimeter of this figure is √27 + 2√3 + √27 + 2√3. But, √27 = √9√3 = 3√3 . Now all of the sides have the same number underneath of the radical symbol (i.e. the same radicand) and so the coefficients of each radical can be added together. The result is that the perimeter is equal to 10√3.

### Example Question #1 : How To Find The Perimeter Of A Rectangle

A rectangle has an area of 56 square feet, and a width of 4 feet. What is the perimeter, in feet, of the rectangle?

**Possible Answers:**

**Correct answer:**36

Divide the area of the rectangle by the width in order to find the length of 14 feet. The perimeter is the sum of the side lengths, which in this case is 14 feet + 4 feet +14 feet + 4 feet, or 36 feet.

### Example Question #38 : Quadrilaterals

The length of a rectangle is 3 more inches than its width. The area of the rectangle is 40 in^{2}. What is the perimeter of the rectangle?

**Possible Answers:**

18 in.

26 in.

None of the answers are correct

34 in.

40 in.

**Correct answer:**

26 in.

Area of rectangle: A = lw

Perimeter of rectangle: P = 2l + 2w

w = width and l = w + 3

So A = w(w + 3) = 40 therefore w^{2} + 3w – 40 = 0

Factor the quadratic equation and set each factor to 0 and solve.

w^{2} + 3w – 40 = (w – 5)(w + 8) = 0 so w = 5 or w = -8.

The only answer that makes sense is 5. You cannot have a negative value for a length.

Therefore, w = 5 and l = 8, so P = 2l + 2w = 2(8) + 2(5) = 26 in.

### Example Question #39 : Quadrilaterals

The length of a rectangle is and the width is . What is its perimeter?

**Possible Answers:**

Not enough information to solve

**Correct answer:**

Perimeter of a quadrilateral is found by adding up the lengths of its sides. The formula for the perimeter of a rectangle is .

### Example Question #191 : Geometry

Kayla took 25 minutes to walk around a rectangular city block. If the block's width is 1/4 the size of the length, how long would it take to walk along one length?

**Possible Answers:**

10 minutes

8 minutes

7 minutes

2.5 minutes

**Correct answer:**

10 minutes

Leaving the width to be *x*, the length is 4*x*. The total perimeter is 4*x* + 4*x* + *x* + *x *= 10x.

We divide 25 by 10 to get 2.5, the time required to walk the width. Therefore the time required to walk the length is (4)(2.5) = 10.

### Example Question #2 : How To Find The Perimeter Of A Rectangle

Robert is designing a rectangular garden. He wants the area of the garden to be 9 square meters. If the length of the lot is going to be three meters less than twice the width, what will the perimeter of the lot be in meters?

**Possible Answers:**

1.5

12

3

10

6

**Correct answer:**

12

Let l be the length of the garden and w be the width.

By the specifications of the problem, l = 2w-3.

Plug this in for length in the area formula:

A = l x w = (2w - 3) x w = 9

Solve for the width:

2w²- 3w - 9 =0

(2w + 3)(w - 3) = 0

w is either 3 or -3/2, but we can't have a negative width, so w = 3.

If w = 3, then length = 2(3) - 3 = 3.

Now plug the width and length into the formula for perimeter:

P = 2 l + 2w = 2(3) + 2(3) = 12

### Example Question #1 : How To Find The Perimeter Of A Rectangle

A rectangular garden has an area of . Its length is meters longer than its width. How much fencing is needed to enclose the garden?

**Possible Answers:**

**Correct answer:**

We define the variables as and .

We substitute these values into the equation for the area of a rectangle and get .

or

Lengths cannot be negative, so the only correct answer is . If , then .

Therefore, .

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