### All High School Math Resources

## Example Questions

### Example Question #1 : How To Find The Perimeter Of A Right Triangle

What is the perimeter of a triangle with side lengths of 5, 12, and 13?

**Possible Answers:**

**Correct answer:**

To find the perimeter of a triangle you must add all of the side lengths together.

In this case our equation would look like

Add the numbers together to get the answer .

### Example Question #2 : How To Find The Perimeter Of A Right Triangle

Three points in the xy-coordinate system form a triangle.

The points are .

What is the perimeter of the triangle?

**Possible Answers:**

**Correct answer:**

Drawing points gives sides of a right triangle of 4, 5, and an unknown hypotenuse.

Using the pythagorean theorem we find that the hypotenuse is .

### Example Question #3 : How To Find The Perimeter Of A Right Triangle

Find the perimeter of the following triangle:

**Possible Answers:**

**Correct answer:**

The formula for the perimeter of a right triangle is:

where is the length of a side.

Use the formulas for a a triangle to find the length of the base. The formula for a triangle is .

Our triangle is:

Plugging in our values, we get:

### Example Question #4 : How To Find The Perimeter Of A Right Triangle

Find the perimeter of the following right triangle:

**Possible Answers:**

**Correct answer:**

The formula for the perimeter of a right triangle is:

where is the length of a side.

Use the formulas for a triangle to find the length of the base and height. The formula for a triangle is

Our triangle is:

Plugging in our values, we get:

### Example Question #5 : How To Find The Perimeter Of A Right Triangle

Based on the information given above, what is the perimeter of triangle ABC?

**Possible Answers:**

**Correct answer:**

Consult the diagram above while reading the solution. Because of what we know about supplementary angles, we can fill in the inner values of the triangle. Angles A and B can be found by the following reductions:

A + 120 = 180; A = 60

B + 150 = 180; B = 30

Since we know A + B + C = 180 and have the values of A and B, we know:

60 + 30 + C = 180; C = 90

This gives us a 30:60:90 triangle. Now, since 17.5 is across from the 30° angle, we know that the other two sides will have to be √3 and 2 times 17.5; therefore, our perimeter will be as follows: