All GRE Math Resources
Example Questions
Example Question #11 : Evaluating Expressions
Let be a positive integer such that one less than three-eighths of is the third prime integer. What is the value of ?
The third prime integer is 5, since 1 is not considered a prime number.
Working backwards,
Example Question #12 : Evaluating Expressions
Quantity A Quantity B
35
Quantity A is greater.
The two quantities are equal.
Quantity B is greater.
The relationship cannot be determined from the information given.
The two quantities are equal.
You don't actually need to solve for the values of x and y. You just want to know the sum of x and y. Adding the two equations together you get
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Example Question #13 : Evaluating Expressions
In a four-digit positive interger , the thousand's digit is three times the units digit.
Quantitiy A Quantitiy B
Unit's digit of 4
Quantity B is greater.
The relationship cannot be determined from the information given.
The two quantities are equal.
Quantity A is greater.
Quantity B is greater.
If we set the quantities equal, and the units digit of is 4, then the thousands digit which is three times the units digit would be 12, which doesnt make sense at all because a digit must be one of the integers 0 through 9. So 4 is too big to be the units digit of . Therefore Quantity B is greater.
Example Question #14 : Evaluating Expressions
The arithmetic mean of is 6. What is the value of ?
The arithmetic mean is the sum of all numbers in a series divided by the number of items in the series. There are 5 items in the series, so they must sum to.
If we subtract from , you are left with so therefore must sum to .
Example Question #14 : Evaluating Expressions
If , and , what is the value of ?
If you add all three equations together you get
Example Question #16 : Evaluating Expressions
Apoorwa has $117 in $1, $5, and $20 bills. She has twice as many $20's as $1's and the number of $20's times the number of $1's is one more than then number of $5's. How many $5's does Apoorwa have?
7
2
5
4
6
7
The answer is 7.
First we know we have three variables so we need three different equations. Let x represent $1 bills, y represent $5 bills, and z represent $20 bills. Looking at the word problem we know that our equations are:
1) 1x + 5y + 20z = 117
2) 2x = z
3) xz – 1 = y
Plug equation 2 into equation 3 to get y = x(2x) – 1. Now plug this new equation 3 and equation 2 into equation 1 giving us
so
but we know this isn't the answer becuase we can't have negative dollar bills and we also can't have 0.1 parts of a dollar bill.
and
thus we know we have two $1 bills
this is the number of $5 bills
Example Question #14 : Evaluating Expressions
Given these equations, what is the value of ?
If you divide the second equation by 2, you can cancel out the terms, which would allow you to solve for , which is 3. Plugging in into either equation will allow you to find , which is 8.
Therefore, .
Example Question #15 : Evaluating Expressions
If , what is one possible value for ?
When you plug in into , you get , which equals 900.
Example Question #16 : Evaluating Expressions
Quantity A:
Quantity B:
The relationship cannot be determined from the information given
The two quantities are equal
Quantity A is greater
Quantity B is greater
The relationship cannot be determined from the information given
We only know that is greater than 0 (positive). If is 2, then quantity A is greater. If is less than 1, then quantity B is greater. Since we don't know if is greater or less than 1, we can't definititvely conclude which quantity is larger.
Example Question #20 : Evaluating Expressions
Arthur has 10 more dollars than Joan. If Arthur gives three of his dollars to Joan, he will have twice as many dollars as Joan. How many dollars does Arthur currently have?
Set this up as two equations: and . Substituting the first equation into the second, you get . Solving for this equation gives you . Since Arthur has 10 more dollars than Joan, he currently has 11 dollars.