### All Algebra II Resources

## Example Questions

### Example Question #632 : Intermediate Single Variable Algebra

What is the slant asymptote of ?

**Possible Answers:**

**Correct answer:**

To find the slant asymptote, we have to divide the numerator by the denominator and see the equation of the line that we get.

Our long division problem ends up looking like this:

(We can ignore the remainder because it doesn't sufficiently impact the equation of the asymptote, especially as approaches infinity.)

Thus, the equation of the slant asymptote is .

### Example Question #1 : Multiplying And Dividing Rational Expressions

Which is a simplified form of ?

**Possible Answers:**

**Correct answer:**

### Example Question #2 : Multiplying And Dividing Rational Expressions

Simplify the following expression:

**Possible Answers:**

**Correct answer:**

Our first step in this problem would be to distribute the exponent on the second term, which makes the expression become:

We then multiply like terms, remembering that multiplying like terms with exponents means we will add the exponent, so the expression becomes:

### Example Question #61 : Solving Rational Expressions

Simplify.

**Possible Answers:**

This expression cannot be simplified.

**Correct answer:**

a. Like when dividing fractions, change the division sign to multiplication and use the reciprocal of the divisor.

b. Factor the trinomials in the numerator of both terms.

c. Cancel any common factors between the numerators and denominators.

This will leave:

d. Multiply to simplify.

### Example Question #1 : Multiplying And Dividing Rational Expressions

Expand:

**Possible Answers:**

**Correct answer:**

This problem will involve using the FOIL method to combine the first two parenthetical terms and then the distributive property to combine what is left. However, we can save time if we recognize that the first two parentheses are in form , with and . We can therefore combine these two parentheses in form , and therefore:

Now we can use FOIL to find that:

which gives us a final answer of

### Example Question #63 : Solving Rational Expressions

Expand:

**Possible Answers:**

**Correct answer:**

To evaluate the expression, we will need to conduct the FOIL method on the first two polynomials and then use the distributive property to reach a final answer. Therefore:

which equals

Using the distributive property, we obtain:

which equals

### Example Question #64 : Solving Rational Expressions

Evaluate the following expression:

**Possible Answers:**

**Correct answer:**

To divide monomials, we subtract the exponents of the like terms. Therefore:

and

Therefore:

### Example Question #65 : Solving Rational Expressions

Simplify:

**Possible Answers:**

**Correct answer:**

In order to solve this equation, we must first simplify it so that we can cancel common factors between the numerator and the denominator.

In the above equation, we can first factor a from . This gives us:

This is easier for us to factor. In order to factor this, we need to see which factors of have a sum of . This turns out to be and . Therefore, we can simplify this expression into:

Next, we need to simplify .

This is a difference of perfect squares. Therefore, its factors are .

Now we need to simplify .

This is a perfect square trinomial. Therefore, this simplifies in the form . Note that this is negative since in order for the middle term to be negative, the sign of must be negative as well.

Finally, we have to simplify .

To factor this, we need to see what multiples of (the first term, , multiplied by the third term, ) have a sum of positive . This turns out to be positive plus a negative . Since our first term is , we need to determine which of our factors is a multiple of . We can see that this is only , which means that our factors will be positive and negative . Therefore, when we simplify our expression, we get a result of

Now our expression looks like

The in the numerator cancels with the in the denominator, the in the numerator cancels with the in the denominator, and one of the factors in the numerator cancels with the in the denominator. This gives us our solution of:

### Example Question #641 : Intermediate Single Variable Algebra

Find the remainder after dividing by this binomial.

**Possible Answers:**

**Correct answer:**

Either using synthetic division by 2 or using x=2 in the remainder theorem are 2 short-cuts to performing the long division of this polynomial.

### Example Question #1 : How To Find The Solution Of A Rational Equation With A Binomial Denominator

Simplify the expression.

**Possible Answers:**

**Correct answer:**

First, factor the numerator. We need factors that multiply to and add to .

We can plug the factored terms into the original expression.

Note that appears in both the numerator and the denominator. This allows us to cancel the terms.

This is our final answer.

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