### All Algebra II Resources

## Example Questions

### Example Question #3 : How To Find A Solution Set

Solve this system of equations.

**Possible Answers:**

, ,

, ,

, ,

, ,

, ,

**Correct answer:**

, ,

Equation 1:

Equation 2:

Equation 3:

Adding the terms of the first and second equations together will yield .

Then, add that to the third equation so that the y and z terms are eliminated. You will get .

This tells us that x = 1. Plug this x = 1 back into the systems of equations.

Now, we can do the rest of the problem by using the substitution method. We'll take the third equation and use it to solve for y.

Plug this y-equation into the first equation (or second equation; it doesn't matter) to solve for z.

We can use this z value to find y

So the solution set is x = 1, y = 2, and z = –5/3.

### Example Question #5 : How To Find A Solution Set

Solve for :

**Possible Answers:**

**Correct answer:**

To solve this problem we can first add to each side of the equation yielding

Then we take the square root of both sides to get

Then we calculate the square root of which is .

### Example Question #1 : How To Subtract Trinomials

Solve this system of equations for :

**Possible Answers:**

**Correct answer:**

Multiply the top equation by 3 on both sides, then add the second equation to eliminate the terms:

### Example Question #5 : How To Factor A Variable

Solve for .

**Possible Answers:**

**Correct answer:**

Multiply both sides by 3:

Distribute:

Subtract from both sides:

Add the terms together, and subtract from both sides:

Divide both sides by :

Simplify:

### Example Question #4 : How To Find A Solution Set

Solve for :

**Possible Answers:**

**Correct answer:**

Distribute the x through the parentheses:

x^{2} –2x = x^{2} – 8

Subtract x^{2} from both sides:

–2x = –8

Divide both sides by –2:

x = 4

### Example Question #1 : Solving Equations

Solve for :.

**Possible Answers:**

**Correct answer:**

First factor the expression by pulling out :

Factor the expression in parentheses by recognizing that it is a difference of squares:

Set each term equal to 0 and solve for the x values:

### Example Question #2 : Solving Equations

Solve the system of equations.

**Possible Answers:**

None of the other answers are correct.

**Correct answer:**

Isolate in the first equation.

Plug into the second equation to solve for .

Plug into the first equation to solve for .

Now we have both the and values and can express them as a point: .

### Example Question #3 : Solving Equations

Solve for and .

**Possible Answers:**

Cannot be determined.

**Correct answer:**

1st equation:

2nd equation:

Subtract the 2nd equation from the 1st equation to eliminate the "2y" from both equations and get an answer for x:

Plug the value of into either equation and solve for :

### Example Question #4 : Solving Equations

What is a solution to this system of equations:

**Possible Answers:**

**Correct answer:**

**Step 1:** Multiply first equation by −2 and add the result to the second equation. The result is:

**Step 2:** Multiply first equation by −3 and add the result to the third equation. The result is:

**Step 3:** Multiply second equation by −23 and add the result to the third equation. The result is:

**Step 4:**solve for z.

**Step 5:**solve for y.

**Step 6:** solve for x by substituting y=2 and z=1 into the first equation.

### Example Question #1 : Solving Equations

**What is a solution to this system of equations?**

**Possible Answers:**

**Correct answer:**

Substitute equation 2. into equation 1.,

so,

Substitute into equation 2:

so, the solution is .

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