### All SSAT Upper Level Math Resources

## Example Questions

### Example Question #50 : Fractions

Simplify.

**Possible Answers:**

**Correct answer:**

When multiplying fractions, find a way to reduce any of the fractions before multplying them out.

For example, since is a multiple of , you would cancel out the and that becomes a and the becomes a .

The same goes for and . The becomes and the goes to .

Overall, the fractions to multiply becomes

. Answer should be .

is not correct because it's not reduced.

### Example Question #1 : Complex Fractions

Simplify.

**Possible Answers:**

**Correct answer:**

We need to get rid of that denominator to solve this problem easily.

Multiply top and bottom by the reciprocal of the denominator or .

This should leave you with .

Now, find a way to reduce any of the fractions before multplying them out.

For example, since is a multiple of , you would cancel out the and that becomes a and the becomes a .

The same goes for and . The becomes and the goes to .

This leaves you with . Answer is .

is not simplified.

### Example Question #1 : How To Multiply Complex Fractions

Simplify.

**Possible Answers:**

Can't be reduced.

**Correct answer:**

This involves a lot of dividing exponents with same base. When dividing exponents of the same base, all you have to do is take the exponent from the numerator and subtract it with the denominator.

For example, with the same base, , the numerator has a and denominator is . Take the diference which is . Same applies and . Since their differences are negative, it means there were mor and in the denominators.

So far, the overall fraction is .

divides into , times.

Now with that simplification, answer is shown.

### Example Question #3 : Complex Fractions

Simplify.

**Possible Answers:**

**Correct answer:**

Always look to reduce fractions. The will cancel out from the denominator of left fraction with numerator of right fraction.

This leads to

.

Now, multiply numerator with numerator and denominator with denominator.

Remember the distribute the in the denominator which leads you to the answer.

### Example Question #4 : Complex Fractions

Simplify.

**Possible Answers:**

**Correct answer:**

Take care of the exponents first before solving the problem.

The numerator should be and denominator is .

Then the should cancel out leaving you with the right answer.

### Example Question #5 : Complex Fractions

Simplify.

**Possible Answers:**

**Correct answer:**

Don't try to multiply everything out. Try to factor all the quadratics out into simple binomials. Remember, we need two numbers who are factors of the c term must add up the value of the b term.

With that, the fraction now looks like:

.

The , , and all cancel leaving you with as the final answer.

### Example Question #6 : Complex Fractions

Simplify.

**Possible Answers:**

1

**Correct answer:**

First, let's take care of the exponents. When dividing exponents of the same base, all you have to do is take the exponent from the numerator and subtract it with the denominator. Now we have leftover in the numerator.

Let's take a look at the denominator of the left fraction. It may not be obvious but if you factor out , we are left with an expression: . We have a in the numerator so now they can cancel out.

Lastly, lets focus on the quadratic in the denominator. Does it look familiar? It is . The numerator in the right fraction has .

Same rule applies with dividing exponents.

This should leave you with just as the final answer.

### Example Question #111 : Number Concepts And Operations

Solve for .

**Possible Answers:**

Both and

**Correct answer:**

There are two methods in solving this problem.

Method 1:

Try to simplify the problem as best as you can before you cross-multiply. Remember when breaking down the quadratic, find two terms which are factors of the c term that are also the sum of the b term. The equation should be:

.

The cancel out and now we can cross-multiply. This new equation is now . Distribute the and have like-terms on one side of the equation and the rest on the otherside of the equation. Answer should be .

Method 2 (Not preferred):

If you don't know how to simplify the equation, that's ok. Lets just cross-multiply and create a quadratic equation.

We can plug into quadratic equation , or factor. Regardless, we should have: .

Solve individually:

WAIT, how come answer isn't Both and . The reason this method is not preferred is because many people forget we need to check if these answers are valid with the original question. We will use the factored equation from method 1: . Remember, if at any point a denominator is , the fraction is undefined. From the denominator, if was either or ( which are the roots to that quadratic), the fraction is undefined. Since we have an answer of and that's one of the values that makes the fraction undefined, we cross that out as a possible answer which leaves only as the only possible answer. If you plug in back into the question we get:

This answer is valid and correct.

### Example Question #8 : Complex Fractions

Solve for .

**Possible Answers:**

**Correct answer:**

Don't try to multiply both numerators and denominators and cross-multiply. It will be time-consuming and too much work. Instead, lets try to simplify. Lets factor the denominator of the left fraction by taking out a . We now have:

The and cancel out leaving a behind. If you don't believe it, just plug in any value for say . One answer gives you , another The relationship between these values is ratio is . With that simplification, lets cross-multiply:

Divide both sides by :

Take the square root of both sides and remember when doing that, you need to account for the negative value of the root. This should lead you to two possible answers. There is no answer of HOWEVER, to get the right answer, break the radical into:

and multiply top and bottom by to get the right answer, .

### Example Question #9 : Complex Fractions

Solve for .

**Possible Answers:**

Both and

**Correct answer:**

First, lets factor and reduce some terms. Remember, we need to find two terms that are factors of the c term that add up to the b term. This should look like this:

Remember, order of operations is crucial. *PEMDAS* Multiplication has priority over addition. So when cancelling, we should only have:

This should be simple with both fractions having the same denominator. We now have:

. Then cross-multiply.

Then subtract on both sides to get the answer.

Make sure this value doesn't violate any undefined fraction. As you check, this answer is still good and is the right answer.

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