### All PSAT Math Resources

## Example Questions

### Example Question #21 : Quadratic Equations

The expression is equal to 0 when and

**Possible Answers:**

**Correct answer:**

Factor the expression and set each factor equal to 0:

### Example Question #2061 : Act Math

Two positive consecutive multiples of four have a product of 96. What is the sum of the two numbers?

**Possible Answers:**

**Correct answer:**

Let = the first number and = the second number.

So the equation to solve becomes . This quadratic equation needs to be multiplied out and set equal to zero before factoring. Then set each factor equal to zero and solve. Only positive numbers are correct, so the answer is .

### Example Question #31 : Quadratic Equations

Two consecutive positive odd numbers have a product of 35. What is the sum of the two numbers?

**Possible Answers:**

**Correct answer:**

Let = first positive number and = second positive number.

The equation to solve becomes

We multiply out this quadratic equation and set it equal to 0, then factor.

### Example Question #41 : Quadratic Equations

The product of two consecutive positive multiples of four is 192. What is the sum of the two numbers?

**Possible Answers:**

**Correct answer:**

Let = the first positive number and = the second positive number

The equation to solve becomes

We solve this quadratic equation by multiplying it out and setting it equal to 0. The next step is to factor.

### Example Question #22 : Quadratic Equations

Two consecutive positive multiples of three have a product of 504. What is the sum of the two numbers?

**Possible Answers:**

**Correct answer:**

Let = the first positive number and = the second positive number.

So the equation to solve is

We multiply out the equation and set it equal to zero before factoring.

thus the two numbers are 21 and 24 for a sum of 45.

### Example Question #21 : Quadratic Equations

Two consecutive positive numbers have a product of 420. What is the sum of the two numbers?

**Possible Answers:**

**Correct answer:**

Let = first positive number and = second positive number

So the equation to solve becomes

Using the distributive property, multiply out the equation and then set it equal to 0. Next factor to solve the quadratic.

### Example Question #23 : Quadratic Equations

A rectangle has a perimeter of and an area of What is the difference between the length and width?

**Possible Answers:**

**Correct answer:**

For a rectangle, and where = width and = length.

So we get two equations with two unknowns:

Making a substitution we get

Solving the quadratic equation we get or .

The difference is .

### Example Question #11 : How To Find The Solution To A Quadratic Equation

If then which of the following is a possible value for ?

**Possible Answers:**

**Correct answer:**

Since , .

Thus

Of these two, only 4 is a possible answer.

### Example Question #41 : Quadratic Equations

Find all real solutions to the equation.

**Possible Answers:**

**Correct answer:**

To solve by factoring, we need two numbers that add to and multiply to .

In order for the equation to equal zero, one of the terms must be equal to zero.

OR

Our final answer is that .

### Example Question #24 : Quadratic Equations

How many real solutions are there for the following equation?

**Possible Answers:**

**Correct answer:**

The first thing to notice is that you have powers with a regular sequence. This means you can simply treat it like a quadratic equation. You are then able to factor it as follows:

The factoring can quickly be done by noticing that the 14 must be either or . Because it is negative, one constant will be negative and the other positive. Finally, since the difference between 14 and 1 cannot be 5, it must be 7 and 2.

Alternatively, one could use the quadratic formula.

The end result is that you have:

The latter of these two gives only complex answers, so there are two real answers.