Exponential Operations

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GRE Quantitative Reasoning › Exponential Operations

Questions 1 - 10
1

If , then

Cannot be determined

Explanation

Start by simplifying the numerator and denominator separately. In the numerator, (c3)2 is equal to c6. In the denominator, c2 * c4 equals c6 as well. Dividing the numerator by the denominator, c6/c6, gives an answer of 1, because the numerator and the denominator are the equivalent.

2

Quantitative Comparison

Quantity A: 64 – 32

Quantity B: 52 – 42

Quantity A is greater.

Quantity B is greater.

The two quantities are equal.

The relationship cannot be determined from the information given.

Explanation

We can solve this without actually doing the math. Let's look at 64 vs 52. 64 is clearly bigger. Now let's look at 32 vs 42. 32 is clearly smaller. Then, bigger – smaller is greater than smaller – bigger, so Quantity A is bigger.

3

Quantity A:

(0.5)3(0.5)3

Quantity B:

(0.5)7

Quantity A is greater.

Quantity B is greater.

The two quantities are equal.

The relationship cannot be determined from the information given.

Explanation

When we have two identical numbers, each raised to an exponent, and multiplied together, we add the exponents together:

xaxb = xa+b

This means that (0.5)3(0.5)3 = (0.5)3+3 = (0.5)6

Because 0.5 is between 0 and 1, we know that when it is multipled by itself, it decreases in value. Example: 0.5 * 0.5 = 0.25. 0.5 * 0.5 * 0.5 = 0.125. Etc.

Thus, (0.5)6 > (0.5)7

4

If , then

Cannot be determined

Explanation

Start by simplifying the numerator and denominator separately. In the numerator, (c3)2 is equal to c6. In the denominator, c2 * c4 equals c6 as well. Dividing the numerator by the denominator, c6/c6, gives an answer of 1, because the numerator and the denominator are the equivalent.

5

Quantity A:

(0.5)3(0.5)3

Quantity B:

(0.5)7

Quantity A is greater.

Quantity B is greater.

The two quantities are equal.

The relationship cannot be determined from the information given.

Explanation

When we have two identical numbers, each raised to an exponent, and multiplied together, we add the exponents together:

xaxb = xa+b

This means that (0.5)3(0.5)3 = (0.5)3+3 = (0.5)6

Because 0.5 is between 0 and 1, we know that when it is multipled by itself, it decreases in value. Example: 0.5 * 0.5 = 0.25. 0.5 * 0.5 * 0.5 = 0.125. Etc.

Thus, (0.5)6 > (0.5)7

6

Quantitative Comparison

Quantity A: 64 – 32

Quantity B: 52 – 42

Quantity A is greater.

Quantity B is greater.

The two quantities are equal.

The relationship cannot be determined from the information given.

Explanation

We can solve this without actually doing the math. Let's look at 64 vs 52. 64 is clearly bigger. Now let's look at 32 vs 42. 32 is clearly smaller. Then, bigger – smaller is greater than smaller – bigger, so Quantity A is bigger.

7

If , what is the value of

Explanation

When dealing with exponenents, when multiplying two like bases together, add their exponents:

However, when an exponent appears outside of a parenthesis, or if the entire number itself is being raised by a power, multiply:

8

Indicate whether Quantity A or Quantity B is greater, or if they are equal, or if there is not enough information given to determine the relationship.

\dpi{100} \small n>0

Quantity A: \dpi{100} \small 16^{n+2}

Quantity B: \dpi{100} \small 2^{4}\times (8^{n+1})^{2}\div 4^{n}

Quantity B is greater.

Quantity A is greater.

The quantities are equal.

The relationship cannot be determined from the information given.

Explanation

By using exponent rules, we can simplify Quantity B.

\dpi{100} \small \dpi{100} \small 2^{4}\times (8^{n+1})^{2}\div 4^{n}

\dpi{100} \small \dpi{100} \small 2^{4}\times (8^{2n+2})\div 4^{n}

\dpi{100} \small \dpi{100} \small 2^{4}\times 2^{3(2n+2)}\div 4^{n}

\dpi{100} \small \dpi{100} \small 2^{4}\times 2^{6n+6}\div 4^{n}

\dpi{100} \small \dpi{100} \small 2^{6n+10}\div 4^{n}

\dpi{100} \small \dpi{100} \small 2^{6n+10}\div 2^{2n}

\dpi{100} \small 2^{4n+10}

Also, we can simplify Quantity A.

\dpi{100} \small 16^{n+2}

\dpi{100} \small =2^{4(n+2)}

\dpi{100} \small =2^{4n+8}

Since n is positive, \dpi{100} \small 4n+10>4n+8

9

Simplify

\dpi{100} \small \frac{20x^{4}y^{-3}z^{2}}{5z^{-1}y^{2}x^{2}}=

\dpi{100} \small \frac{4x^{2}z^{3}}{y^{5}}

\dpi{100} \small {4x^{5}y^{-2}}

\dpi{100} \small 15x^{2}y^{2}z^{2}

\dpi{100} \small 15x^{-2}y^{-2}z^{-2}

None

Explanation

Divide the coefficients and subtract the exponents.

10

(b * b4 * b7)1/2/(b3 * bx) = b5

If b is not negative then x = ?

–2

–1

7

1

Explanation

Simplifying the equation gives b6/(b3+x) = b5.

In order to satisfy this case, x must be equal to –2.

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