### All Calculus 2 Resources

## Example Questions

### Example Question #21 : Alternating Series

Determine how many terms need to be added to approximate the following series within

**Possible Answers:**

**Correct answer:**

This is an alternating series test.

In order to find the terms necessary to approximate the series within first see if the series is convergent using the alternating series test. If the series converges, find n such that

Step 1:

An alternating series can be identified because terms in the series will “alternate” between + and –, because of

Note: Alternating Series Test can only show convergence. It cannot show divergence.

If the following 2 tests are true, the alternating series converges.

- {} is a decreasing sequence, or in other words

Solution:

1.

2. {{b_{n}} is a decreasing sequence. A factorial always increases as n increases, so each term will decrease as n increases.

Since the 2 tests pass, this series is convergent.

Step 2:

Plug in n values until

4 terms need to be added to approximate the sum within .001

### Example Question #22 : Alternating Series

Determine whether the series converges or diverges:

**Possible Answers:**

The series may be absolutely convergent, conditionally convergent, or divergent

The series is (absolutely) convergent

The series is divergent

The series is conditionally convergent

**Correct answer:**

The series is (absolutely) convergent

To determine whether the given alternating series converges or diverges, we must perform the Alternating Series test, which states that for a given series

and or , for the series to converge, and must be decreasing.

To start, we must take the limit of as n approaches infinity:

because (the numerator goes to zero).

Next, we must see if is decreasing. Simply increasing to does not clearly show whether the function is decreasing because both the numerator and denominator increase. So, we must find the first derivative and see if it is negative:

,

and was found using the following rules:

,

The derivative is always negative from to , so the sequence is decreasing. The series is (absolutely) convergent because it passed both parts of the test.

### Example Question #21 : Alternating Series

Determine whether the series is convergent or divergent:

**Possible Answers:**

The series is conditionally convergent

The series may be conditionally convergent, (absolutely) convergent, or divergent

The series is (absolutely) convergent

The series is divergent

**Correct answer:**

The series is divergent

To determine whether the series is convergent or divergent, we must use the Alternating Series test, which states that for a given series , where or , if and is decreasing, then the series is convergent.

First, we must evaluate the limit of as approaches infinity:

Therefore, the test fails and series is divergent.

### Example Question #22 : Alternating Series

Determine whether the following series is convergent or divergent:

**Possible Answers:**

The series may be (absolutely) convergent, conditionally convergent, or divergent

The series is (absolutely) convergent

The series is conditionally convergent

The series is divergent

**Correct answer:**

The series is divergent

To determine whether the series is convergent or divergent, we must use the Alternating Series test, which states that for a given series , where or , if and is decreasing, then the series is convergent.

First, we must evaluate the limit of as approaches infinity:

The test fails and the series is therefore divergent.

### Example Question #21 : Alternating Series

Determine whether the series is convergent or divergent:

**Possible Answers:**

The series is divergent

The series is (absolutely) convergent

The series is conditionally convergent

The series may be (absolutely) convergent, conditionally convergent, or divergent

**Correct answer:**

The series is divergent

To determine whether the series is convergent or divergent, we must use the Alternating Series test, which states that for a given series , where or , if and is decreasing, then the series is convergent.

First, we must evaluate the limit of as approaches infinity:

The test fails and therefore the series is divergent.