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Example Questions
Example Question #7 : Polynomials & Quadratics
If , which of the following is a potential value of
?
0
4
8
10
6
6
To solve this problem algebraically, first recognize that the term means you're dealing with a quadratic. To solve for a quadratic, perform the necessary algebra to set the equation equal to 0. Here that means subtracting 24 from each side to reach:
From here, remember that your goal when factoring a quadratic is to find terms that multiply to the last term (the numerical term) and sum to the middle term (the linear term). That should lead you to:
Then the last, very critical step, is to set each parentheses equal to zero to officially solve the problem. That means that:
yields a solution of
yields a solution of
Of those, only is an answer, so
is correct.
Example Question #8 : Polynomials & Quadratics
What is the sum of all unique values of that satisfy the equation above?
9
4
5
3
0
9
Whenever you're working with a quadratic, your goal should be to move all terms to one side of the equation so that you can set it equal to zero. Here that means adding to each side and subtracting
from each side to arrive at:
From there you can factor, looking for terms that sum to and that multiply to
. You should arrive at:
Then you have to set each parentheses equal to zero to finish solving. That will give you:
or
as possible solutions. Since the question asks for the sum, add those together to get the correct answer,
.
Example Question #9 : Polynomials & Quadratics
What is the sum of all unique values of that satisfy the equation above?
0
2
-2
7
5
5
Whenever you're facing a quadratic, your best move is to move all the terms to one side of the equation so you can set it to zero. Then you can factor (or apply the quadratic formula if needed). Here that means subtracting and
from both sides of the given equation to reach:
Now you can factor, looking for terms that multiply to and that sum to
. That should lead you to:
To finish the job, you need to set each parentheses equal to zero. That means that the solutions to this equation are:
and
Since the question asks for the sum of those solutions, add them together to get your answer, .
Example Question #10 : Polynomials & Quadratics
Which of the following is a value of that satisfies the equation above?
-8
8
0
-7
9
-7
Whenever you're working with a quadratic structure, you should look to move all terms to one side of the equation to set it to zero. This here means subtracting from each side of the equation to get:
You can then factor the equation, looking for values that multiply to and sum to
. You should arrive at:
From here, you need to set each parenthetical term to zero, meaning that your answers are:
Of those, only appears as an answer, so that answer is correct.
Example Question #1 : Simplifying Polynomials
Choose the answer which best simplifies the following expression:
To solve this problem simply remove the parentheses and add the like terms:
Example Question #2 : Simplifying Polynomials
Choose the answer which best simplifies the following expression:
To simplify, simply remove the parentheses and combine like terms:
Example Question #3 : Simplifying Polynomials
Choose the answer that best simplifies the following expression:
To simplify, remove parentheses and combine like terms:
Example Question #4 : Simplifying Polynomials
Choose the answer that best simplifies the following expression:
To simplify, remove parentheses and combine like terms, but make sure to distribute the negative across all terms in the second set of parentheses, changing the sign of each:
Then combine like terms:
Example Question #5 : Simplifying Polynomials
Choose the answer that best simplifies the following expression:
To simplify, remove parentheses and combine like terms, remembering the ever-important step of applying the negative sign to each term within the second set of parentheses:
Example Question #6 : Simplifying Polynomials
Choose the answer that best simplifies the following expression:
To simplify, remove parentheses and combine like terms, remember to distribute the negative (by changing each sign) for the terms in the second set of parentheses:
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