### All LSAT Logic Games Resources

## Example Questions

### Example Question #11 : Linear Games

A gym teacher wants his 6 students to line up in height order, from shortest to tallest. Corrin and Theresa are girls. Ben, Jonathan, Will, and Dan are the boys.

- Will is not the tallest or the shortest.

- No girl is taller than Jonathan

- Dan is shorter than Corrin, but taller than Theresa.

- Ben is the tallest

Which of the following must be true about acceptable height orders?

**Possible Answers:**

Will is always between Theresa and Corrin.

Ben is always at the back of the line, and Theresa is always at the front.

Will is always between Ben and Jonathan.

Dan is always between Theresa and Will.

Dan is always between Corrin and Will.

**Correct answer:**

Ben is always at the back of the line, and Theresa is always at the front.

Theresa will always be at the front of the line, and Ben at the back. Theresa must be in front of Dan, Corrin, and Jonathan, and Will cannot be 1st.

Additionally, because of Will's interchangeability, there is no certainty that Dan will be between certain people or that Will is always between certain people. These answers are possibilities, but not certainties.

### Example Question #11 : Linear Games

A gym teacher wants his 6 students to line up in height order, from shortest to tallest. Corrin and Theresa are girls. Ben, Jonathan, Will, and Dan are the boys.

- Will is not the tallest or the shortest.

- No girl is taller than Jonathan

- Dan is shorter than Corrin, but taller than Theresa.

- Ben is the tallest

Which of the following is a complete list of people who cannot be third in line?

**Possible Answers:**

Jonathan, Theresa, Will

Ben, Theresa, Corrin

Ben, Theresa

Jonathan, Theresa, Dan

Ben, Jonathan, Theresa

**Correct answer:**

Ben, Jonathan, Theresa

Theresa has to be first, because she is shorter than Dan, Corrin, and Jonathan. Ben must always be 6th. Jonathan has to be either 4th or 5th, because he is after the girls, who surround Dan - which takes up 3 spots.

### Example Question #11 : Determining Sequence In Linear Games

A gym teacher wants his 6 students to line up in height order, from shortest to tallest. Corrin and Theresa are girls. Ben, Jonathan, Will, and Dan are the boys.

- Will is not the tallest.

- No girl is taller than Jonathan

- Dan is shorter than Corrin, but taller than Theresa.

- Ben is the tallest

If Will was the shortest in line, what must the order be?

**Possible Answers:**

Will, Theresa, Dan, Corrin, Ben, Jonathan

Theresa, Will, Dan, Corrin, Jonathan, Ben

Will, Theresa, Jonathan, Corrin, Dan, Ben

Will, Corrin, Dan, Theresa, Jonathan, Ben

Will, Theresa, Dan, Corrin, Jonathan, Ben

**Correct answer:**

Will, Theresa, Dan, Corrin, Jonathan, Ben

If Will is locked into the first position, all other positions are set and cannot be changed, according to the rest of the rules.

### Example Question #12 : Linear Games

- Will is not the tallest or the shortest.

- No girl is taller than Jonathan.

- Dan is shorter than Corrin, but taller than Theresa.

- Ben is the tallest.

Who are the only people that can be 5th in line?

**Possible Answers:**

Jonathan, Corrin, Will

Will, Dan

Jonathan and Will

Jonathan, Will, Theresa

Jonathan, Corrin, Ben

**Correct answer:**

Jonathan and Will

Ben has to be 6th always. Theresa has to always be first. Corrin must always be earlier in line than Jonathan, so she can not be 5th. Will is interchangeable between the 2nd-5th spots, so he and Jonathan are the only ones that can be 5th.

### Example Question #11 : Lsat Logic Games

- Will is not the tallest or the shortest.

- No girl is taller than Jonathan

- Dan is shorter than Corrin, but taller than Theresa.

- Ben is the tallest

Who must be first in line?

**Possible Answers:**

Dan

Will

Corrin

Jonathan

Theresa

**Correct answer:**

Theresa

Theresa must precede everyone. She has to be shorter than Dan and Corrin and Jonathan. Will cannot be shortest. Ben has to be the tallest. Thus, only Theresa can be 1st.

### Example Question #11 : Lsat Logic Games

- Will is not the tallest or the shortest.

- No girl is taller than Jonathan

- Dan is shorter than Corrin, but taller than Theresa.

- Ben is the tallest

What positions can Corrin fill?

**Possible Answers:**

4th, 5th

3rd, 4th

3rd, 4th, 5th

2nd, 3rd, 4th

1st, 2nd, 3rd, 4th

**Correct answer:**

3rd, 4th

Corrin must follow Theresa and Dan, thus she cannot be 1st or second. She must also come before Jonathan and Ben, so she cannot be 5th or 6th. Thus, Corrin can only be 3rd or 4th.

### Example Question #12 : Lsat Logic Games

A consultant has agreed to see each of his nine clients-- L, M, N, O, P, Q, R, S, T-- once in the next six days, from Monday through Saturday. He arranges his schedule so that he can see at least one of his clients each day, while maintaining the following conditions:

O is always scheduled on a day before R and M.

P is not scheduled for Saturday.

If T is scheduled on a day after O, then S is scheduled on a day after N.

If T is scheduled on a day before O, then R is scheduled on a day before L.

The consultant always sees less clients on Friday and Saturday combined than he sees on any other two days of the week combined.

If S must be scheduled for Saturday, which of the following must be true?

**Possible Answers:**

The consultant sees O no later than Wednesday.

Q must be scheduled on a day earlier than L.

There is no other client who can be scheduled on fewer days than M can be scheduled

If R is scheduled on the same day as another client, then M is scheduled alone.

If L and M are scheduled together, than Q and O are scheduled together.

**Correct answer:**

The consultant sees O no later than Wednesday.

**The consultant sees O no later than Wednesday.**

This must be true. If O is scheduled for Thursday, then there is not enough room to schedule both R and M. O must be scheduled before R and M, but no more than one client may be scheduled for each of Friday and Saturday.

**If R is scheduled on the same day as another client, then M is scheduled alone.**

This is a trick for those who saw that O is restricted, but who make the mistake that O somehow must be scheduled for Wednesday instead of just on or before Wednesday. This is true if O is on Wednesday thanks to the restrictions on seeing clients on Friday and Saturday.

**Q must be scheduled on a day earlier than L.**

There are a number of valid schedules where this is not true. For example:

Mon: T

Tues: O, P

Wed: N, R

Thur: L, M

Fri: Q

Sat: S

**If L and M are scheduled together, than Q and O are scheduled together.**

The previous diagram shows a schedule where this is not true.

**There is no other client who can be scheduled on fewer days than M can be scheduled**

R and M are restricted in that they cannot be placed on Monday, since O must come before both of them. This gives them each 4 possible days to be scheduled. O must be scheduled no later than Thursday, which gives it 3 possible days to be scheduled. No other client is restricted whatsoever, except by the fact that S already occupies Saturday. This can be easiliy seen by the fact that N will always come before S, which makes any configuration where O comes before T valid. This leaves virtually every spot open for every letter, since there are no further restrictions that come after O > T. The only restriction is that T cannot be on Monday if O > T, but you can easily make a T > O diagram that is legal as well to make up for that shortcoming.

### Example Question #11 : Lsat Logic Games

A consultant has agreed to see each of his nine clients-- L, M, N, O, P, Q, R, S, T-- once in the next six days, from Monday through Saturday. He arranges his schedule so that he can see at least one of his clients each day, while maintaining the following conditions:

O is always scheduled on a day before R and M.

P is not scheduled for Saturday.

If T is scheduled on a day after O, then S is scheduled on a day after N.

If T is scheduled on a day before O, then R is scheduled on a day before L.

The consultant always sees less clients on Friday and Saturday combined than he sees on any other two days of the week combined.

If there are exactly four days between the days that the consultant schedules P and T (not necessarily in that order), then what is the maximum number of days that can be between S and R?

**Possible Answers:**

2

1

4

0

3

**Correct answer:**

2

The easiest way to approach this question is to simply diagram what is being asked. Four days between P and T places them at Monday and Saturday. P cannot be placed on Saturday, so that means that the diagram so far is P_ _ _ _T.

If T is the last client to be seen, then O obviously comes before it, which means that N comes before S for this question. Lastly, O always comes before R and M.

That means that we have an NS block and and ORM block. Neither S nor R can appear earlier than Tuesday. Neither S nor R can appear later than Thursday (only one client can be on Saturday, and that's T). The number of days between Tuesday and Friday is 2.

Here is an example diagram:

Mon: O, P

Tues: R, M

Wed: L, Q

Thur: N

Fri: S

Sat: T

### Example Question #11 : Linear Games

A consultant has agreed to see each of his nine clients-- L, M, N, O, P, Q, R, S, T-- once in the next six days, from Monday through Saturday. He arranges his schedule so that he can see at least one of his clients each day, while maintaining the following conditions:

O is always scheduled on a day before R and M.

P is not scheduled for Saturday.

If T is scheduled on a day after O, then S is scheduled on a day after N.

If T is scheduled on a day before O, then R is scheduled on a day before L.

The consultant always sees less clients on Friday and Saturday combined than he sees on any other two days of the week combined.

If O is scheduled for Thursday, then for how many other clients do you know the precise day on which they are scheduled?

**Possible Answers:**

3

4

1

2

0

**Correct answer:**

1

If O is on Thursday, then Friday and Saturday must be some combination of R and M.

_ _ _ O R/M R/M

T cannot go after O, because Friday and Saturday can only have one client a piece. T cannot go before O either, because that would require L to come after R. There is no space to do that.

If T cannot go before OR after O, then it must be on the same day. There is no other option.

If T and O are on the same day, then the two conditional rules (If O before T and If T before O) do not apply. Thus, you could place any of L, N, P, Q, S in any combination or order in the first three days. R and M are interchangeable on Friday and Saturday. Thus, only the position of T is fixed by scheduling O on Thursday.

### Example Question #12 : Linear Games

A Halloween parade consists of six floats. The floats are of a goblin, a witch, a pumpkin, a skeleton, a mummy, and a piece of candy. The floats will look best when arranged in a certain order according to the following rules:

1. The goblin and the pumpkin must be consecutively ordered.

2. The piece of candy cannot be first.

3. The skeleton and mummy cannot be consecutively ordered.

4. If the pumpkin is second, the witch must not be fourth.

Which of the following is a possible order for the floats?

**Possible Answers:**

pumpkin, candy, skeleton, witch, goblin, mummy

goblin, pumpkin, skeleton, mummy, witch, candy

candy, pumpkin, goblin, skeleton, witch, mummy

pumpkin, goblin, skeleton, witch, candy, mummy

goblin, pumpkin, skeleton, witch, mummy, candy

**Correct answer:**

pumpkin, goblin, skeleton, witch, candy, mummy

This arrangement satisfies all of the conditions: the goblin and the pumpkin are consecutively ordered, the piece of candy isn't first, the skeleton and mummy are not consecutively ordered, and since the pumpkin isn't second the witch can be fourth.

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