# A triangle has one of the inner angles of 30 degrees and one of the outer angles of 40 degrees.

**A triangle has one of the inner angles of 30 degrees and one of the outer angles of 40 degrees. find the rest of the interior corners.**

From the condition we know that a triangle has one of the inner angles equal to 30 °, and one of the outer angles is 40 °.

In order to find all the angles of a triangle, we must remember what is the sum of adjacent angles and the theorem on the sum of the angles of a triangle.

So, the sum of adjacent angles is 180 °. Now we can find the degree measure of the inner corner of the triangle adjacent to the outer one:

180 ° – 40 ° = 140 °.

We now know the two corners of the triangle. By the theorem on the sum of the angles of a triangle, the sum of the angles of a triangle is 180 °.

180 ° – (140 ° + 30 °) = 180 ° – 170 ° = 10 °.

Answer: 140 °; 10 °.