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Try this at home! The can implodes because the atmospheric pressure is greater than the pressure inside the can. When the can was submerged in the water it caused the water vapor inside the can to rapidly cool. When a gas is cooled, its pressure goes down. This drop in pressure causes the pressure inside the can to be lower than the atmospheric pressure.
Note: Use less than 1 cm of water in this experiment (about 1/2 inch)
Elastic P.E.  work stored in a deformed spring
a) General Equation
PE_{s} = Fx F = Average Force needed to deform spring x = distance deformed
Ideal Spring
b) Hooke's Law  force needed to deform an ideal spring, a given amount is directly proportional to its displacement (deformation)
Graphic from LearningConnections Clipart
Robert Hooke
Ex) Ideal Spring
slope = F/x x = stretch
c) Spring Constant (k), Ideal Spring
 quantifies stiffness of a spring
What is the spring constant of the spring that produced the data? above?
k = 6.7 N/m
Which is the stiffer spring?
Spring A is the stiffer spring. More
force is required
Ex) Plots and K
Pick any point on the line
K = 50. N/m
31) A spring with k = 53 N/m hangs
vertically on a ruler. The end of the spring is next to the 15 cm mark
on the ruler.
k = F/x
53 N/m = 2.5kg[9.8m/s^{2}]/x
x = .46 m + .15 m ruler reading = .61 m
d) Elastic P.E. = area of triangle under F vs x graph
PE_{s} = (½)basexheight
PE_{s} = 6 Joules
Try this at home!
©Tony Mangiacapre.,
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