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Test: AP Calculus AB
Find the derivative.
1. | y = sec (5x3)
|
y' = –csc(5x3)cot(5x3)(15x2)
y' = –csc(5x3)cot(5x3)
y' = –sec(5x3)tan(5x3)(15x2)
y' = sec(5x3)tan(5x3)(15x2)
y' = sec(5x3)tan(5x3)
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