Test: AP Calculus AB

Find the derivative. 

1.

y = sec (5x3)

 

 

y' = –csc(5x3)cot(5x3)(15x2)

y' = –sec(5x3)tan(5x3)(15x2)

y' = sec(5x3)tan(5x3)

y' = sec(5x3)tan(5x3)(15x2)

y' = –csc(5x3)cot(5x3)

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