### All SAT Math Resources

## Example Questions

### Example Question #1 : Factoring Common Factors Of Squares And Square Roots

Solve for :

**Possible Answers:**

**Correct answer:**

Notice how all of the quantities in square roots are divisible by 9

Simplifying, this becomes

### Example Question #2 : Factoring Common Factors Of Squares And Square Roots

Solve for :

**Possible Answers:**

**Correct answer:**

Note that all of the square root terms share a common factor of 36, which itself is a square of 6:

Factoring from both terms on the left side of the equation:

### Example Question #1 : Factoring Common Factors Of Squares And Square Roots

Solve for :

**Possible Answers:**

**Correct answer:**

Note that both and have a common factor of and is a perfect square:

From here, we can factor out of both terms on the lefthand side

### Example Question #4 : Factoring Common Factors Of Squares And Square Roots

Solve for :

**Possible Answers:**

**Correct answer:**

In order to solve for , first note that all of the square root terms on the left side of the equation have a common factor of 9 and 9 is a perfect square:

Simplifying, this becomes:

### Example Question #21 : Arithmetic

Which of the following is equivalent to:

?

**Possible Answers:**

**Correct answer:**

To begin with, factor out the contents of the radicals. This will make answering much easier:

They both have a common factor . This means that you could rewrite your equation like this:

This is the same as:

These have a common . Therefore, factor that out:

### Example Question #1 : Factoring Common Factors Of Squares And Square Roots

Simplify:

**Possible Answers:**

**Correct answer:**

These three roots all have a in common; therefore, you can rewrite them:

Now, this could be rewritten:

Now, note that

Therefore, you can simplify again:

Now, that looks messy! Still, if you look carefully, you see that all of your factors have ; therefore, factor that out:

This is the same as:

### Example Question #71 : Arithmetic

Solve for :

**Possible Answers:**

**Correct answer:**

Examining the terms underneath the radicals, we find that and have a common factor of . itself is a perfect square, being the product of and . Hence, we recognize that the radicals can be re-written in the following manner:

, and .

The equation can then be expressed in terms of these factored radicals as shown:

Factoring the common term from the lefthand side of this equation yields

Divide both sides by the expression in the parentheses:

Divide both sides by to yield by itself on the lefthand side:

Simplify the fraction on the righthand side by dividing the numerator and denominator by :

This is the solution for the unknown variable that we have been required to find.

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