### All MCAT Physical Resources

## Example Questions

### Example Question #17 : Forces

Two objects with masses of M and m, sit r distance apart. What will be the effect on the gravitational force between them if the masses are changed to 2M and 3m?

- It will increase 36-fold.
- It will increase 6-fold.
- It will increase 3-fold.
- It will not change unless r is changed.
- None of the above.

**Possible Answers:**

4

5

3

1

2

**Correct answer:**

2

Choice 2 is correct. The formula for gravitational force, G, is , where k is a constant. The effect of doubling one mass and trebling the other is multiplicative, , so the answer is six-fold. The question attempts to confuse the respondent by forcing them to recall that the element of the equation which is squared is distance between objects.

### Example Question #18 : Forces

An object has a mass of 50kg and a weight of 500N when it is resting on the surface of the Earth. If it is moved to a height equal to three times the Earth’s radius, what is the object’s new weight?

**Possible Answers:**

130N

300N

30N

60N

**Correct answer:**

30N

You should be familiar with the following equation for the force of gravity.

To solve this problem, recognize that weight (F_{g}) is proportional to the inverse square of the radius. When the object was a distance of **r** (Earth’s radius) it had a weight of 500N. Now, the object is at a distance of **4r** (radius of Earth plus the 3r distance that the object is moved to). With the proportion described above, we can see that the force is decreased by a factor of **(4) ^{2}.**

### Example Question #19 : Forces

The moon's distance from the center of the Earth was decreased by a multiple of three. How would this affect the gravitational force of the Earth on the moon?

**Possible Answers:**

It would increase by a factor of nine

It would decrease by a factor of nine

It would increase by a factor of three

The gravitational force would not be affected, because the moon's mass is the same

**Correct answer:**

It would increase by a factor of nine

The law of gravitation is written as , with G being equal to .

Since the radius of the two masses acting on each other is squared, and is found in the denominator, a decrease in the radius by a multiple of three will cause a nine-fold increase in the gravitational force.

### Example Question #20 : Forces

A body with mass is situated meters from a second body with a mass of . What will be the effect on gravitational attraction of moving one body so that it is only meters from the other body?

**Possible Answers:**

It will increase by a factor of

It will decrease by a factor of

It will increase by a factor of

It will decrease by a factor of

It will increase by a factor of

**Correct answer:**

It will increase by a factor of

Gravity is essentially a property of mass, and the force of gravitational attraction between two bodies is given by the formula:

In our scenario, the masses remain the same, and of course is a constant, so the only thing that changes is the denominator.

### Example Question #1 : Universal Gravitation

Using Newton's Law of Universal Gravitation equation, which of the following expressions is equal to the local gravitational acceleration on Earth?

**Possible Answers:**

**Correct answer:**

On earth, .

The law of universal gravitation is equal to .

We can set these equations equal to one another and isolate by dividing both sides by , the mass of an object on Earth.

Using the mass of the Earth, the radius of the Earth, and the gravitational constant, , we get a value of approximately if we solve for .

### Example Question #22 : Forces

Which of the following must be true for a block to be considered weightless?

**Possible Answers:**

The block is being constantly accelerated downward at

The object can never be considered weightless

The block is being constantly accelerated upward at

The block is being constantly accelerated downward at

The block is being constantly accelerated downward at

**Correct answer:**

The block is being constantly accelerated downward at

One way an object can be considered "weightless," is if it is accelerating downward at the same rate that it would be if it were free falling. This is why objects in an elevator whose cable had been cut would be "weightless." Therefore the answer is just for the block to be accelerating in the same magnitude and direction as the acceleration due to gravity, which is

### Example Question #23 : Forces

Which of the following changes would increase a satellite's orbital speed?

**Possible Answers:**

Decrease the mass of the Earth

Decrease orbital radius

Increase the mass of the satellite

Decrease the mass of the satellite

Increase orbital radius

**Correct answer:**

Decrease orbital radius

We know , and the force of gravity is:

Also, the equation for uniform circular motion, such as a satellite in orbit is:

Set and substitute the acceleration due to circular motion into the equation. Solve for velocity.

This indicates that the only variables that affect the orbital speed are orbital radius and the mass of the Earth.