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Test: GMAT Math

1.	One of the diameters of a circle has endpoints (4, 5) and (10, 1). What is the equation of this circle?

$\small (x - 7)^{2} + (y - 3)^{2} = 13$

$\small 3x^{2} + 9y^{2} = 169$

$\small \small (x - 7)^{2} + (y - 3)^{2} = 169$

$\small \small \small \small (x - 3)^{2} + (y - 7)^{2} = 169$

$\small \small \small (x - 3)^{2} + (y - 7)^{2} = 13$

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