Test: PSAT Math

1.

The endpoints of line segment AB are located at (5, –2) and (–3, 10). What is the equation of the line that is the perpendicular bisector of AB?

2x + 3y = 14

3x – 4y = –13

2x – 3y = –10

3x – 4y = –4

2x – 3y = –20

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