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Test: PSAT Math
1. | The endpoints of line segment AB are located at (5, –2) and (–3, 10). What is the equation of the line that is the perpendicular bisector of AB? |
2x + 3y = 14
3x – 4y = –13
2x – 3y = –10
3x – 4y = –4
2x – 3y = –20
Rene Solo
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University of the Philippines, Bachelor of Science, Mathematics. Prairie View A & M University, Master of Arts, Educational A...
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