Test: ACT Math

1.

If \tan A=\frac{b}{c}, where b>0\ and\ c>0 and \frac{\pi }{2}<A<\pi,

then what is cos\ A?

-\frac{c}{\sqrt{c^{2}+b^{2}}}

\frac{\sqrt{c^{2}+b^{2}}}{c}

\frac{b}{\sqrt{c^{2}+b^{2}}}

\frac{c}{\sqrt{c^{2}+b^{2}}}

-\frac{\sqrt{c^{2}+b^{2}}}{c}

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