### All AP Statistics Resources

## Example Questions

### Example Question #1 : Estimation

What is , or the expected value of for any distribution?

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**Correct answer:**

is , or the mean, of the population. This makes sense since literally means the expected value of . The mean is the expected value of .

### Example Question #1 : How To Estimate Population Parameters

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**Correct answer:**

### Example Question #1 : How To Estimate Margins Of Errors

The next local election is predicted to have a split in votes for the top two candidates. How many people should be polled to obtain a margin of error of 3% at the 95% confidence level?

**Possible Answers:**

**Correct answer:**

If you remember the required formula, this problem is rather simple. Plug in the given numbers and simplify:

If you don't remember the formula, this problem is more challenging. Your best bet in this case is to construct the confidence interval and rearrange to solve for the required sample size.

### Example Question #2 : How To Estimate Margins Of Errors

When dealing with confidence intervals, the margin of error gets smaller when z* gets ________ and n gets _________.

**Possible Answers:**

smaller . . . larger

smaller . . . smaller

larger . . . smaller

There is no way to affect the margin of error in confidence intervals

larger . . . larger

**Correct answer:**

smaller . . . larger

For confidence intervals, a small margin of error is preferred, as it indicates that the parameter of interest has been narrowed down to a precise interval. Having a large sample population to work from as well as a small z* (z* gets smaller as the confidence level percent gets lower) can help obtain a small margin of error.

### Example Question #41 : Inference

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**Correct answer:**

### Example Question #1 : How To Find Point Estimators

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### Example Question #1 : How To Find Confidence Intervals For A Mean

Suppose you have a normally distributed variable with known variance. How many standard errors do you need to add and subtract from the sample mean so that you obtain 95% confidence intervals?

**Possible Answers:**

**Correct answer:**

To obtain 95% confidence intervals for a normal distribution with known variance, you take the mean and add/subtract . This is because 95% of the values drawn from a normally distributed sampling distribution lie within 1.96 standard errors from the sample mean.

### Example Question #1 : Estimation

An automotive engineer wants to estimate the cost of repairing a car that experiences a 25 MPH head-on collision. He crashes 24 cars, and the average repair is $11,000. The standard deviation of the 24-car sample is $2,500.

Provide a 98% confidence interval for the true mean cost of repair.

**Possible Answers:**

**Correct answer:**

Standard deviation for the samle mean:

Since n < 30, we must use the t-table (not the z-table).

The 98% t-value for n=24 is 2.5.

### Example Question #1 : Confidence Intervals

300 hundred eggs were randomly chosen from a gravid female salmon and individually weighed. The mean weight was 0.978 g with a standard deviation of 0.042. Find the 95% confidence interval for the mean weight of the salmon eggs (because it is a large n, use the standard normal distribution).

**Possible Answers:**

**Correct answer:**

Because we have such a large sample size, we are using the standard normal or z-distribution to calculate the confidence interval.

Formula:

We must find the appropriate z-value based on the given for 95% confidence:

Then, find the associated z-score using the z-table for

Now we fill in the formula with our values from the problem to find the 95% CI.

### Example Question #1 : Confidence Intervals And Mean

A sample of observations of 0_{2} consumption by adult western fence lizards gave the following statistics:

Find the confidence limit for the mean 0_{2} consumption by adult western fence lizards.

**Possible Answers:**

**Correct answer:**

Because we are only given the sample standard deviation we will use the t-distribution to calculate the confidence interval.

Appropriate Formula:

Now we must identify our variables:

We must find the appropriate t-value based on the given

t-value at 90% confidence:

Look up t-value for 0.05, 55 , so t-value= ~ 1.6735

90% CI becomes:

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