Test: AP Calculus BC

1.

Let f(x)=\ln (1-x^2). Which of the following is equal to f'(x)?

 

f'(x)=\frac{\ln x}{1-x^2}

f'(x)=x^2\ln x-\ln x

f'(x)=\frac{1}{1-x^2}

f'(x)=2x\ln (1-x^2)

f'(x)=\frac{2x}{x^2-1}

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