Energy Diagrams
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AP Chemistry › Energy Diagrams
Two pathways for the same reaction are shown: Pathway 1 has two steps (two peaks), and Pathway 2 has one step (one peak). Both have the same reactants and products. Which statement is correct?
(Vertical axis: potential energy; horizontal axis: reaction coordinate.)
Pathway 1 has a different $\Delta H$ because it has an intermediate.
Pathway 2 must be faster because it is single-step.
Pathway 1 must be slower because it has more steps.
Whichever pathway has the lower highest peak has the lower overall $E_a$.
Both pathways have $\Delta H=0$ because they share endpoints.
Explanation
This question tests the skill of comparing activation energies and rates for alternative reaction pathways in energy diagrams. The overall Ea for each pathway is determined by the height of its highest peak relative to reactants, with the pathway having the lower highest peak expected to be faster, regardless of the number of steps. This is because the rate is limited by the largest barrier, and both pathways share the same ΔH since they have identical reactants and products. Thus, option C correctly states that whichever pathway has the lower highest peak has the lower overall Ea. A tempting distractor is option A, which claims Pathway 1 is slower because it has more steps, but this is incorrect due to the misconception that the number of steps directly determines rate, ignoring activation energy heights. To compare pathways, evaluate the maximum Ea for each, as the lowest maximum barrier indicates the kinetically favored route.
A reaction proceeds in two steps with an intermediate I, as shown.
Energy
| R______/____
| / \ ____
| / ____ ____ P
| I
+--------------------------------> Reaction coordinate
Which step has the larger activation energy?
Step 1 (R to I), because the first peak is higher above R than the second peak is above I.
Both steps, because the two peaks are at the same height above the baseline.
Step 2 (I to P), because the second peak is closer to P on the x-axis.
Step 2 (I to P), because products are lower than reactants.
Neither step, because activation energy is the energy difference between R and P.
Explanation
This question tests the skill of comparing activation energies in multi-step reactions using relative peak heights. Step 1 has the larger Ea because its peak is higher above R than the second peak is above I, where Ea is step-specific from starting energy to transition state. The diagram shows two peaks with the first taller from R, and overall P below R for exothermicity. This identifies the rate-determining step as the one with the highest barrier. A tempting distractor is choice D, which incorrectly says both steps have equal Ea due to similar peak heights, ignoring relative starting points. Calculate each step's Ea from its own baseline to peak for accurate comparisons.
Two pathways for the same reaction are shown in the energy diagram: Pathway 1 (uncatalyzed) and Pathway 2 (catalyzed). Which statement is consistent with the diagram?

Pathway 2 has a different $\Delta H$ because catalysts change product energy
Pathway 2 has a larger $E_a$ because it has more steps
Both pathways have the same $E_a$ because they start at the same reactant energy
Pathway 2 has the same $\Delta H$ as Pathway 1 but a smaller overall $E_a$
Pathway 1 has a smaller $E_a$ because its peak is lower than Pathway 2
Explanation
This question tests understanding of how catalysts affect reaction energy diagrams. A catalyst provides an alternative pathway with a lower activation energy but does not change the thermodynamics of the reaction, so ΔH remains the same for both pathways since they have the same starting and ending energy levels. Pathway 2 (catalyzed) shows multiple smaller peaks instead of one large peak, with the highest peak of Pathway 2 being lower than the single peak of Pathway 1, indicating a smaller overall activation energy. The overall activation energy is determined by the highest energy barrier that must be overcome, not the sum of all barriers. A common misconception (choice C) is that catalysts change the energy of products, but catalysts only affect kinetics, not thermodynamics. When comparing catalyzed and uncatalyzed pathways, verify that reactants and products are at the same energy levels in both diagrams, then identify the highest peak in each pathway to compare activation energies.
Two reactions, A and B, are shown on separate energy diagrams. Reaction A is exothermic with a high peak; Reaction B is endothermic with a lower peak. Which reaction is expected to be faster at the same temperature, based only on the diagrams?
(Vertical axis: potential energy; horizontal axis: reaction coordinate.)
Reaction A, because its products are lower in energy.
Reaction B, because $\Delta H>0$ increases the rate.
Reaction A, because exothermic reactions are always faster.
They must have the same rate because both are single-step.
Reaction B, because its activation energy barrier is lower.
Explanation
This question tests the skill of comparing reaction rates based on activation energies from energy diagrams. Reaction B has a lower peak, indicating a smaller activation energy barrier compared to Reaction A's high peak, even though Reaction A is exothermic and B is endothermic. According to transition state theory, the reaction rate is primarily determined by the height of the activation energy barrier, with lower Ea leading to faster rates at the same temperature. Therefore, option B correctly states that Reaction B is expected to be faster due to its lower activation energy. A tempting distractor is option A, which claims Reaction A is faster because exothermic reactions are always faster, but this is incorrect due to the misconception that thermodynamics (ΔH) directly dictate kinetics, whereas rate depends on Ea. When comparing reactions via energy diagrams, prioritize the activation energy height over the overall ΔH to predict relative rates.
Two energy diagrams represent two different reactions.
Reaction X:
Energy
| /\
| R___/ _____ P
+----------------->
Reaction Y:
Energy
| /\
| R_________/ _____ P
+----------------->
Which statement is supported by the diagrams?
Reaction Y has a smaller $E_a$ than Reaction X because its peak is higher.
Reaction X has a smaller $E_a$ than Reaction Y because its peak is closer to R.
Both reactions have the same $E_a$ because both are single-step.
Reaction X has a larger $E_a$ than Reaction Y because its products are lower.
Reaction X has a larger $E_a$ than Reaction Y because its peak is taller.
Explanation
This question tests the skill of comparing activation energies between different reactions using energy diagrams. Reaction X has a taller peak above its reactants compared to Reaction Y's shorter peak, indicating X has a larger Ea, as Ea is the vertical energy difference from R to the transition state. Both diagrams show P below R, suggesting exothermic reactions, but the key comparison is the barrier height. This demonstrates that reactions with similar thermodynamics can have different kinetics based on Ea. A tempting distractor is choice B, which wrongly claims X has smaller Ea due to peak proximity to R, based on the misconception that horizontal position affects energy barriers. When comparing diagrams, measure vertical heights from R to peaks for Ea, ignoring x-axis positioning.
Two different reactions, X and Y, have energy diagrams shown (each single-step). Reaction X has products much lower than reactants; reaction Y has products slightly lower than reactants. Which comparison is supported by the diagrams?
Reaction Y has a more negative $\Delta H$ than reaction X.
Reaction X must have a smaller reverse $E_a$ than reaction Y because products are lower.
Both reactions have the same $\Delta H$ because both are exothermic.
Reaction X has a more negative $\Delta H$ than reaction Y.
Reaction X has a larger forward $E_a$ than reaction Y because $\Delta H$ is more negative.
Explanation
This question tests the ability to compare thermodynamic properties between different reactions using energy diagrams. The enthalpy change (ΔH) is determined by the vertical distance between reactants and products - a larger drop means a more negative (more exothermic) ΔH. Since reaction X shows products much lower than reactants compared to reaction Y's slight drop, reaction X has a more negative ΔH. The activation energies and ΔH values are independent properties - a more negative ΔH does not automatically mean a larger Ea(forward). A common misconception is thinking all exothermic reactions have the same ΔH (choice E), but the magnitude of energy release varies with the specific vertical drop on the diagram. When comparing reactions, examine the relative positions of reactants and products separately from the transition state heights.
Two different uncatalyzed reactions, X and Y, are shown on separate energy diagrams. Reaction X has a higher peak above its reactants than reaction Y has above its reactants. Which conclusion is supported by the diagrams?

Reaction X is faster because its products are lower in energy
Reaction X has a larger forward $E_a$ than reaction Y
Reaction X has a smaller forward $E_a$ than reaction Y
Reaction X has a more negative $\Delta H$ than reaction Y
Reaction X has $\Delta H=0$ while reaction Y has $\Delta H\ne 0$
Explanation
This question tests the ability to compare activation energies between different reactions. The activation energy for a reaction is the vertical distance from reactants to the transition state peak. If reaction X has a higher peak above its reactants than reaction Y has above its reactants, then reaction X has a larger forward activation energy. The absolute height of the peaks or the energy levels of the products are irrelevant; only the vertical distance from each reaction's starting point to its peak matters. A common misconception (choice E) is thinking that lower product energy makes a reaction faster, but reaction rate depends on activation energy, not thermodynamics. When comparing activation energies between different reactions, measure the vertical distance from each reaction's reactants to its transition state, not absolute peak heights.
An energy diagram for a two-step reaction is shown with an intermediate. Which feature on the diagram corresponds to the activation energy for the second step (Step 2)?

The vertical difference between the second transition state and the intermediate
The horizontal distance from reactants to products
The vertical difference between the second transition state and the products
The vertical difference between the first transition state and the reactants
The vertical difference between reactants and products
Explanation
This question tests the ability to identify activation energies for individual steps in a multi-step reaction mechanism. The activation energy for any step is the vertical distance from the starting point of that step to its transition state peak. For Step 2, the reaction starts from the intermediate (the local minimum between the two peaks) and proceeds to the second transition state (the second peak). Therefore, the activation energy for Step 2 is the vertical difference between the intermediate and the second transition state. A common misconception (choice B) is thinking the activation energy for Step 2 starts from the reactants, but each step has its own starting point. To find the activation energy for any step in a multi-step reaction, identify where that step begins (reactants for Step 1, intermediate for Step 2) and measure vertically to its corresponding transition state peak.
For the single-step reaction shown in the energy diagram, which statement best describes the sign of $\Delta H$?

$\Delta H<0$ because the peak is above the reactants
$\Delta H>0$ because the activation energy is positive
$\Delta H>0$ because products are at higher potential energy than reactants
$\Delta H<0$ because products are at higher potential energy than reactants
$\Delta H=0$ because there is only one transition state
Explanation
This question tests the ability to determine the sign of ΔH from an energy diagram. The enthalpy change (ΔH) is determined by comparing the potential energy levels of reactants and products: if products are higher in energy than reactants, energy must be absorbed, making the reaction endothermic (ΔH > 0). The diagram shows products at a higher potential energy level than reactants, confirming that ΔH > 0. The presence of an activation energy peak is irrelevant to the sign of ΔH; all reactions have activation energy regardless of being endothermic or exothermic. A common misconception (choice E) is misreading the diagram and thinking ΔH < 0 when products are higher, which would violate energy conservation. When determining ΔH from an energy diagram, focus only on the vertical difference between reactant and product energy levels, ignoring transition states.
A catalyst is added to a reaction whose uncatalyzed energy diagram is shown. Which change would be expected for the catalyzed pathway, relative to the uncatalyzed pathway?

The horizontal distance between reactants and products decreases
Reactant energy decreases, making $\Delta H$ more negative
The peak increases because catalysts add energy to the reaction
Product energy increases, making $\Delta H$ more positive
The highest peak decreases while reactant and product energies stay the same
Explanation
This question tests understanding of how catalysts affect reaction energy diagrams. A catalyst provides an alternative reaction pathway with a lower activation energy, which appears on the diagram as a lower peak (or series of lower peaks) compared to the uncatalyzed reaction. Crucially, catalysts do not change the energy levels of reactants or products, so the starting and ending points remain the same, preserving the same ΔH for the reaction. The catalyst only affects the pathway between reactants and products, lowering the highest energy barrier that must be overcome. A common misconception (choice E) is thinking catalysts add energy to increase the peak, but catalysts actually lower activation energy by providing a more favorable pathway. When analyzing catalyzed reactions, verify that reactant and product energies remain unchanged while the transition state peak(s) decrease.