Test: SAT Math

6.

The endpoints of line segment AB are located at (5, –2) and (–3, 10). What is the equation of the line that is the perpendicular bisector of AB?

2x – 3y = –10

3x – 4y = –4

2x + 3y = 14

3x – 4y = –13

2x – 3y = –20

6/10 questions

50%
Learning Tools by Varsity Tutors