Derivative Defined as Limit of Difference Quotient - AP Calculus BC
Card 1 of 190

Evaluate
.
Evaluate .
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To find
, substitute
and use the chain rule:








So 
and



To find , substitute
and use the chain rule:
So
and
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What is the equation of the line tangent to the graph of the function

at the point
?
What is the equation of the line tangent to the graph of the function
at the point ?
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The slope of the line tangent to the graph of
at
is
, which can be evaluated as follows:




The equation of the line with slope
through
is:




The slope of the line tangent to the graph of at
is
, which can be evaluated as follows:
The equation of the line with slope through
is:
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What is the equation of the line tangent to the graph of the function

at the point
?
What is the equation of the line tangent to the graph of the function
at the point ?
Tap to reveal answer
The slope of the line tangent to the graph of
at
is
, which can be evaluated as follows:




, the slope of the line.
The equation of the line with slope
through
is:




The slope of the line tangent to the graph of at
is
, which can be evaluated as follows:
, the slope of the line.
The equation of the line with slope through
is:
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What is the equation of the line tangent to the graph of the function

at
?
What is the equation of the line tangent to the graph of the function
at ?
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The slope of the line tangent to the graph of
at
is
, which can be evaluated as follows:



, the slope of the line.
The equation of the line with slope
through
is:

![y - (-4) = -2 [x- (-2)]](https://vt-vtwa-assets.varsitytutors.com/vt-vtwa/uploads/formula_image/image/181223/gif.latex)



The slope of the line tangent to the graph of at
is
, which can be evaluated as follows:
, the slope of the line.
The equation of the line with slope through
is:
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What is the equation of the line tangent to the graph of the function

at the point
?
What is the equation of the line tangent to the graph of the function
at the point ?
Tap to reveal answer
The slope of the line tangent to the graph of
at the point
is
, which can be evaluated as follows:







The line with this slope through
has equation:





The slope of the line tangent to the graph of at the point
is
, which can be evaluated as follows:
The line with this slope through has equation:
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What is the equation of the line tangent to the graph of the function

at the point
?
What is the equation of the line tangent to the graph of the function
at the point ?
Tap to reveal answer
The slope of the line tangent to the graph of
at the point
is
, which can be evaluated as follows:




The line with slope 28 through
has equation:





The slope of the line tangent to the graph of at the point
is
, which can be evaluated as follows:
The line with slope 28 through has equation:
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Given the function
, find the slope of the point
.
Given the function , find the slope of the point
.
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To find the slope at a point of a function, take the derivative of the function.

The derivative of
is
.
Therefore the derivative becomes,
since
.
Now we substitute the given point to find the slope at that point.

To find the slope at a point of a function, take the derivative of the function.
The derivative of is
.
Therefore the derivative becomes,
since
.
Now we substitute the given point to find the slope at that point.
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Find the value of the following derivative at the point
:

Find the value of the following derivative at the point :
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To solve this problem, first we need to take the derivative of the function. It will be easier to rewrite the equation as
from here we can take the derivative and simplify to get

From here we need to evaluate at the given point
. In this case, only the x value is important, so we evaluate our derivative at x=2 to get
.
To solve this problem, first we need to take the derivative of the function. It will be easier to rewrite the equation as from here we can take the derivative and simplify to get
From here we need to evaluate at the given point . In this case, only the x value is important, so we evaluate our derivative at x=2 to get
.
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Evaluate the value of the derivative of the given function at the point
:

Evaluate the value of the derivative of the given function at the point :
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To solve this problem, first we need to take the derivative of the function.

From here we need to evaluate at the given point
. In this case, only the x value is important, so we evaluate our derivative at x=1 to get
.
To solve this problem, first we need to take the derivative of the function.
From here we need to evaluate at the given point . In this case, only the x value is important, so we evaluate our derivative at x=1 to get
.
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Given
, find the value of
at the point
.
Given , find the value of
at the point
.
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Given the function
, we can use the Power Rule
for all
to find its derivative:
.
Plugging in the
-value of the point
into
, we get
.
Given the function , we can use the Power Rule
for all
to find its derivative:
.
Plugging in the -value of the point
into
, we get
.
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Given
, find the value of
at the point
.
Given , find the value of
at the point
.
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Given the function
, we can use the Power Rule
for all
to find its derivative:
.
Plugging in the
-value of the point
into
, we get
.
Given the function , we can use the Power Rule
for all
to find its derivative:
.
Plugging in the -value of the point
into
, we get
.
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Find the derivative of
at point
.
Find the derivative of at point
.
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Use either the FOIL method to simplify before taking the derivative or use the product rule to find the derivative of the function.
The product rule will be used for simplicity.

Substitute
.

Use either the FOIL method to simplify before taking the derivative or use the product rule to find the derivative of the function.
The product rule will be used for simplicity.
Substitute .
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Find the derivative of the following function at
:

Find the derivative of the following function at :
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The derivative of the function is given by the product rule:
, 
Simply find the derivative of each function:


The derivatives were found using the following rules:
, 
Simply evaluate each derivative and the original functions at the point given, using the above product rule.
The derivative of the function is given by the product rule:
,
Simply find the derivative of each function:
The derivatives were found using the following rules:
,
Simply evaluate each derivative and the original functions at the point given, using the above product rule.
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What is the slope of a function
at the point
?
What is the slope of a function at the point
?
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Slope is defined as the first derivative of a given function.
Since
, we can use the Power Rule
for all
to determine that
.
Since we're given a point
, we can use the x-coordinate
to solve for the slope at that point.
Thus,

Slope is defined as the first derivative of a given function.
Since , we can use the Power Rule
for all
to determine that
.
Since we're given a point , we can use the x-coordinate
to solve for the slope at that point.
Thus,
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What is the slope of the tangent line to the function

when 
What is the slope of the tangent line to the function
when
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The slope of the tangent line to a function at a point is the value of the derivative at that point. To calculate the derivative in this problem, the product rule is necessary. Recall that the product rule states that:
.
In this example, 
Therefore,
, and

At x = 1, this dervative has the value
.
The slope of the tangent line to a function at a point is the value of the derivative at that point. To calculate the derivative in this problem, the product rule is necessary. Recall that the product rule states that:
.
In this example,
Therefore,
, and
At x = 1, this dervative has the value
.
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Find the second derivative of the following function at
:

Find the second derivative of the following function at :
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To find the second derivative of the function, we first must find the first derivative of the function:

The derivative was found using the following rules:
,
,
,
, 
The second derivative is simply the derivative of the first derivative function, and is equal to:

One more rule used in combination with some of the ones above is:

To finish the problem, plug in x=0 into the above function to get an answer of
.
To find the second derivative of the function, we first must find the first derivative of the function:
The derivative was found using the following rules:
,
,
,
,
The second derivative is simply the derivative of the first derivative function, and is equal to:
One more rule used in combination with some of the ones above is:
To finish the problem, plug in x=0 into the above function to get an answer of .
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Find
for

Find for
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In order to find the derivative, we need to find
. We can find this by remembering the product rule and knowing the derivative of natural log.
Product Rule:
.
Derivative of natural log:


Now lets apply this to our problem.



In order to find the derivative, we need to find . We can find this by remembering the product rule and knowing the derivative of natural log.
Product Rule:
.
Derivative of natural log:
Now lets apply this to our problem.
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Calculate the derivative of
at the point
.
Calculate the derivative of at the point
.
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There are 2 steps to solving this problem.
First, take the derivative of 
Then, replace the value of x with the given point and evaluate
For example, if
, then we are looking for the value of
, or the derivative of
at
.

Calculate 
Derivative rules that will be needed here:
- Derivative of a constant is 0. For example,

- Taking a derivative on a term, or using the power rule, can be done by doing the following:


Then, plug in the value of x and evaluate

There are 2 steps to solving this problem.
First, take the derivative of
Then, replace the value of x with the given point and evaluate
For example, if , then we are looking for the value of
, or the derivative of
at
.
Calculate
Derivative rules that will be needed here:
- Derivative of a constant is 0. For example,
- Taking a derivative on a term, or using the power rule, can be done by doing the following:
Then, plug in the value of x and evaluate
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If
, which of the following limits equals
?
If , which of the following limits equals
?
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The equation for the derivative at a point is given by
.
By substituting
,
, we obtain

The equation for the derivative at a point is given by
.
By substituting ,
, we obtain
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Evaluate
.
Evaluate .
Tap to reveal answer
To find
, substitute
and use the chain rule:








So 
and



To find , substitute
and use the chain rule:
So
and
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