All flashcards
Flashcard 1: Find the volume of a solid with triangular cross sections, base =4, height =5, length =6.
Answer: Volume = 60. Apply volume formula: 21×4×5×6.
Flashcard 2: What is the volume of a solid with semicircular cross sections where the diameter is 10 and length is 3?
Answer: Volume = 37.5π. Radius 5, area 225π, times length 3.
Flashcard 3: If f(x)=x2 and g(x)=0, what is the radius of the semicircular cross section at x=3?
Answer: Radius = 4.5. Half the distance from 32=9 to 0 gives 9/2=4.5.
Flashcard 4: What is the role of the base function f(x) in determining cross sections?
Answer: f(x) provides the upper boundary. Defines the top edge of each cross-section.
Flashcard 5: If f(x)=x2 and g(x)=0, what is the base of the triangular cross section at x=2?
Answer: Base = 4. Distance from x2 to 0 at x=2 gives 4−0=4.
Flashcard 6: Find the volume of a solid with semicircular cross sections, radius =4, and length =5.
Answer: Volume = 40π. Semicircle area 2π×42=8π times length 5.
Flashcard 7: What is the volume of a solid with triangular cross sections where base and height are both constant at 5?
Answer: Volume = 12.5×Length. Triangle area 21×5×5=12.5 times length.
Flashcard 8: Find the volume of a solid with triangular cross sections, base =9, height =12, length =10.
Answer: Volume = 540. Apply formula: 21×9×12×10.
Flashcard 9: If f(x)=x3 and g(x)=x, find the base of the triangular cross section at x=1.
Answer: Base = 0. At x=1: 13−1=0, so base is 0.
Flashcard 10: Compute the volume for a solid with semicircular cross sections with radius r=2 and length l=6.
Answer: Volume = 12π. Semicircle area 2π×22=2π times length 6.
Flashcard 11: If f(x)=x3 and g(x)=0, what is the radius of the semicircular cross section at x=1?
Answer: Radius = 0.5. At x=1: 213−0=21=0.5.
Flashcard 12: Compute the volume of a solid with triangular cross sections, base =6, height =4, length =8.
Answer: Volume = 96. Apply formula: 21×6×4×8.
Flashcard 13: Calculate the volume of a solid with semicircular cross sections, diameter =6, length =4.
Answer: Volume = 18π. Using semicircle formula with radius 3 and length 4.
Flashcard 14: Given f(x)=ex and g(x)=0, find the height of the triangular cross section at x=0.
Answer: Height = 1. At x=0: e0−0=1, giving height 1.
Flashcard 15: What is the formula for the radius of a semicircle given diameter d?
Answer: Radius = 2d. Basic relationship between radius and diameter.
Flashcard 16: What is the volume of a solid with semicircular cross sections where the radius is constant at 3?
Answer: Volume = 9π×Length. Semicircle area 2πr2 with r=3 times length.
Flashcard 17: Given f(x)=x+1 and g(x)=x, find the height of the triangular cross section at x=1.
Answer: Height = 1. Distance between functions: (1+1)−(1)=1.
Flashcard 18: Given f(x)=x2+1 and g(x)=x, find the diameter of the semicircular cross section at x=2.
Answer: Diameter = 3. Distance between (22+1)=5 and 2 gives diameter 3.
Flashcard 19: What is the role of the base function g(x) in determining cross sections?
Answer: g(x) provides the lower boundary. Defines the bottom edge of each cross-section.
Flashcard 20: Find the volume of a solid with semicircular cross sections, diameter =8 and length =2.
Answer: Volume = 16π. Radius 4, area 8π, times length 2.
Flashcard 21: What is the formula for the area of a semicircle with diameter d?
Answer: Area = 2π×(d/2)2. Semicircle area using diameter instead of radius.
Flashcard 22: Calculate the volume of a solid with semicircular cross sections, radius =3, and length =7.
Answer: Volume = 31.5π. Semicircle area 29π times length 7.
Flashcard 23: What is the volume of a solid with triangular cross sections, base =7 and height =8?
Answer: Volume = 28×Length. Triangle area 21×7×8=28 times length.
Flashcard 24: What is the volume formula for a solid with equilateral triangular cross sections?
Answer: Volume = 4√3×side2×Length. Uses equilateral triangle area formula with side length.
Flashcard 25: Identify the radius for semicircular cross sections in the plane x=a.
Answer: Radius = 2f(a)−g(a). Half the distance between boundary functions.
Flashcard 26: What is the diameter for semicircular cross sections if base function f(x)=x+2 and g(x)=x?
Answer: Diameter = 2. Distance between functions (x+2)−x=2.
Flashcard 27: Given the function y=sin(x), find the base of triangle cross section at x=2π.
Answer: Base = 1. At x=2π, sin(2π)=1 gives base of 1.
Flashcard 28: Identify the base for triangular cross sections in the plane x=a.
Answer: Base = f(a)−g(a). Distance between upper and lower boundary functions.
Flashcard 29: Compute the volume of a solid with triangular cross sections, base =6, height =4, length =8.
Answer: Volume = 96. Apply formula: 21×6×4×8.
Flashcard 30: Given the function y=sin(x), find the base of triangle cross section at x=2π.
Answer: Base = 1. At x=2π, sin(2π)=1 gives base of 1.