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AP Calculus BC Flashcards: Comparison Tests For Convergence

Study Comparison Tests For Convergence in AP Calculus BC with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

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What this deck covers

This deck focuses on Comparison Tests For Convergence, giving you a quick way to review the definitions, rules, and examples that matter most for AP Calculus BC.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

AP Calculus BC Flashcards: Comparison Tests For Convergence

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QUESTION

Use Comparison: is 1n2+2n\frac{1}{n^2+2n}n2+2n1​ convergent?

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ANSWER

Converges; compare to 1n2\frac{1}{n^2}n21​ (convergent ppp-series). For large nnn, 1n2+2n∼1n2\frac{1}{n^2+2n} \sim \frac{1}{n^2}n2+2n1​∼n21​.

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Flashcard 1: Use Comparison: is 1n2+2n\frac{1}{n^2+2n}n2+2n1​ convergent?

Answer: Converges; compare to 1n2\frac{1}{n^2}n21​ (convergent ppp-series). For large nnn, 1n2+2n∼1n2\frac{1}{n^2+2n} \sim \frac{1}{n^2}n2+2n1​∼n21​.

Flashcard 2: Does 1n\frac{1}{n}n1​ converge? Use the Comparison Test.

Answer: Diverges; compare to 1n\frac{1}{n}n1​ (divergent ppp-series). 1n\frac{1}{n}n1​ is a divergent ppp-series with p=1p = 1p=1.

Flashcard 3: Identify a series to compare with 1n4+3n2\frac{1}{n^4+3n^2}n4+3n21​.

Answer: Compare with 1n4\frac{1}{n^4}n41​, a convergent ppp-series. For large nnn, 1n4+3n2∼1n4\frac{1}{n^4+3n^2} \sim \frac{1}{n^4}n4+3n21​∼n41​.

Flashcard 4: State the Limit Comparison Test.

Answer: If anbn→c>0\frac{a_n}{b_n} \to c > 0bn​an​​→c>0, both series converge or diverge. Both series share the same convergence behavior when the limit exists and is positive.

Flashcard 5: State the condition for the Limit Comparison Test to be valid.

Answer: If anbn→c>0\frac{a_n}{b_n} \to c > 0bn​an​​→c>0, it is valid. This ensures both series have the same convergence behavior.

Flashcard 6: In the Comparison Test, what do you compare ana_nan​ to?

Answer: Compare ana_nan​ to bnb_nbn​ where bnb_nbn​ is a known series. The known series bnb_nbn​ serves as the reference for comparison.

Flashcard 7: For Limit Comparison, what happens if c=0c = 0c=0 or c=infinityc = \text{infinity}c=infinity?

Answer: The test is inconclusive if c=0c = 0c=0 or c=infinityc = \text{infinity}c=infinity. These limit values don't provide definitive comparison information.

Flashcard 8: What is required for the Comparison Test to be applicable?

Answer: Series terms ana_nan​ and bnb_nbn​ must be positive for all nnn. Negative terms invalidate the comparison inequalities used in the test.

Flashcard 9: Use Comparison: is n2n3+1\frac{n^2}{n^3+1}n3+1n2​ convergent?

Answer: Diverges; compare to 1n\frac{1}{n}n1​ (divergent ppp-series). For large nnn, n2n3+1∼1n\frac{n^2}{n^3+1} \sim \frac{1}{n}n3+1n2​∼n1​.

Flashcard 10: When using the Comparison Test, what must be true of bnb_nbn​?

Answer: bnb_nbn​ must be a series with known convergence behavior. Without known behavior, no conclusion can be drawn.

Flashcard 11: Determine convergence of 1n2.5\frac{1}{n^{2.5}}n2.51​ using Comparison.

Answer: Converges; compare to 1n2.5\frac{1}{n^{2.5}}n2.51​ (convergent ppp-series). p=2.5>1p = 2.5 > 1p=2.5>1 makes this a convergent ppp-series.

Flashcard 12: Use Comparison: is 1ln(n)×n\frac{1}{\text{ln}(n) \times n}ln(n)×n1​ convergent?

Answer: Diverges; compare to 1n\frac{1}{n}n1​ (divergent ppp-series). Since ln⁡(n)\ln(n)ln(n) grows slower than any power, this behaves like 1n\frac{1}{n}n1​.

Flashcard 13: For Limit Comparison, what if ana_nan​ and bnb_nbn​ are non-positive?

Answer: Test is not applicable; terms must be positive. The test relies on positive term inequalities.

Flashcard 14: Use Limit Comparison: compare nn2+1\frac{n}{n^2+1}n2+1n​ with 1n\frac{1}{n}n1​.

Answer: Diverges; limit is finite and positive. lim⁡n→∞nn2+1⋅n1=1>0\lim_{n \to \infty} \frac{n}{n^2+1} \cdot \frac{n}{1} = 1 > 0limn→∞​n2+1n​⋅1n​=1>0.

Flashcard 15: Use Comparison: does n2+3n3+1\frac{n^2 + 3}{n^3 + 1}n3+1n2+3​ converge?

Answer: Diverges; compare to 1n\frac{1}{n}n1​ (divergent ppp-series). For large nnn, n2+3n3+1∼1n\frac{n^2+3}{n^3+1} \sim \frac{1}{n}n3+1n2+3​∼n1​.

Flashcard 16: Use Limit Comparison: compare 1n2+1\frac{1}{n^2+1}n2+11​ with 1n2\frac{1}{n^2}n21​.

Answer: Converges; limit is finite and positive. lim⁡n→∞1n2+1⋅n21=1>0\lim_{n \to \infty} \frac{1}{n^2+1} \cdot \frac{n^2}{1} = 1 > 0limn→∞​n2+11​⋅1n2​=1>0.

Flashcard 17: Use Limit Comparison: compare n2+1n4\frac{n^2+1}{n^4}n4n2+1​ with 1n2\frac{1}{n^2}n21​.

Answer: Converges; limit is finite and positive. lim⁡n→∞n2+1n4⋅n21=1>0\lim_{n \to \infty} \frac{n^2+1}{n^4} \cdot \frac{n^2}{1} = 1 > 0limn→∞​n4n2+1​⋅1n2​=1>0.

Flashcard 18: Identify a series to compare with 3n3+ln(n)\frac{3}{n^3 + \text{ln}(n)}n3+ln(n)3​.

Answer: Compare with 1n3\frac{1}{n^3}n31​, a convergent ppp-series. For large nnn, 3n3+ln⁡(n)∼3n3\frac{3}{n^3 + \ln(n)} \sim \frac{3}{n^3}n3+ln(n)3​∼n33​.

Flashcard 19: Does the Limit Comparison Test require non-negative terms?

Answer: Yes, terms ana_nan​ and bnb_nbn​ must be positive. Positivity is essential for meaningful ratio comparison.

Flashcard 20: What ppp-series can you use to compare when p>1p > 1p>1?

Answer: Use 1np\frac{1}{n^p}np1​, which converges for p>1p > 1p>1. ppp-series with p>1p > 1p>1 are standard convergent comparison series.

Flashcard 21: Can the Limit Comparison Test be used if c<0c < 0c<0?

Answer: No, ccc must be positive for the Limit Comparison Test. Negative limits don't maintain the required proportional relationship.

Flashcard 22: What is the relationship between ana_nan​ and bnb_nbn​ in Limit Comparison?

Answer: If anbn→c>0\frac{a_n}{b_n} \to c > 0bn​an​​→c>0, both series behave similarly. When c>0c > 0c>0, the series have proportional terms and same convergence.

Flashcard 23: Can the Comparison Test be used for alternating series?

Answer: No, the test requires positive terms. Alternating series have both positive and negative terms.

Flashcard 24: Is 1n1.5\frac{1}{n^{1.5}}n1.51​ convergent? Use Comparison.

Answer: Converges; compare to 1n1.5\frac{1}{n^{1.5}}n1.51​ (convergent ppp-series). p=1.5>1p = 1.5 > 1p=1.5>1 makes this a convergent ppp-series.

Flashcard 25: Identify if 1n3+n\frac{1}{n^3 + n}n3+n1​ is convergent using Comparison.

Answer: Converges; compare to 1n3\frac{1}{n^3}n31​ (convergent ppp-series). For large nnn, 1n3+n∼1n3\frac{1}{n^3 + n} \sim \frac{1}{n^3}n3+n1​∼n31​.

Flashcard 26: Identify a series to compare with 2n2+1n3+3\frac{2n^2+1}{n^3+3}n3+32n2+1​.

Answer: Compare with 1n\frac{1}{n}n1​, a divergent ppp-series. For large nnn, 2n2+1n3+3∼2n\frac{2n^2+1}{n^3+3} \sim \frac{2}{n}n3+32n2+1​∼n2​.

Flashcard 27: Identify if 1n2\frac{1}{n^2}n21​ converges using the Comparison Test.

Answer: Converges; compare to 1n2\frac{1}{n^2}n21​ (convergent ppp-series). 1n2\frac{1}{n^2}n21​ is itself a convergent ppp-series with p=2>1p = 2 > 1p=2>1.

Flashcard 28: What is the Comparison Test for convergence?

Answer: A test comparing a series to a known convergent or divergent series. Direct comparison determines convergence by relating to known series.

Flashcard 29: Use Comparison: does 1n1.1\frac{1}{n^{1.1}}n1.11​ converge?

Answer: Converges; compare to 1n1.1\frac{1}{n^{1.1}}n1.11​ (convergent ppp-series). p=1.1>1p = 1.1 > 1p=1.1>1 makes this a convergent ppp-series.

Flashcard 30: Which series should you choose for the Comparison Test?

Answer: Choose a series bnb_nbn​ that is similar in form to ana_nan​. Similar form makes the comparison meaningful and easier to evaluate.