Power Series: Radius, Interval of Convergence - AP Calculus BC

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Question

Determine the interval of convergence for $\textstyle\bigsum_{n=0}^{\text{∞}} \frac{(x-3)^n}{2^n}$.

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Answer

$(1, 5)$. Series $\sum \frac{(x-3)^n}{2^n}$ has center 3, radius 2; endpoints diverge.

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