All flashcards
Flashcard 1: Define a linear differential equation.
Answer: An equation where the dependent variable and derivatives appear linearly. Dependent variable appears to first power only.
Flashcard 2: Write the differential equation for exponential growth.
Answer: dtdy=ky. Rate proportional to current amount.
Flashcard 3: What is the integrating factor for dy/dx+2y=ex?
Answer: e2x. Exponential of integral of coefficient: e∫2dx.
Flashcard 4: What is a particular solution?
Answer: A solution satisfying both the differential equation and initial conditions. Specific solution meeting initial conditions.
Flashcard 5: Identify the dependent variable in dz/dt=z2+t2.
Answer: The dependent variable is z. Function being differentiated (z depends on t).
Flashcard 6: Identify the dependent variable in dy/dx=x2+y2.
Answer: The dependent variable is y. Variable being differentiated (y depends on x).
Flashcard 7: What is the integrating factor for y′+p(x)y=g(x)?
Answer: e∫p(x)dx. Multiplier that makes equation exact.
Flashcard 8: State a real-world example of a first-order differential equation.
Answer: Newton's Law of Cooling. Temperature change proportional to difference.
Flashcard 9: What is the general solution to y′′+4y=0?
Answer: y=C1cos(2x)+C2sin(2x). Characteristic equation r2+4=0 gives r=±2i.
Flashcard 10: What method is used to solve y′=ky?
Answer: Separation of variables. Rearrange to separate y and x terms.
Flashcard 11: What is the general solution to y′′+9y=0?
Answer: y=C1cos(3x)+C2sin(3x). Characteristic equation r2+9=0 gives r=±3i.
Flashcard 12: What does it mean for a function to be a solution to a differential equation?
Answer: Substituting it into the equation yields a true statement. The function satisfies the equation identically.
Flashcard 13: What is the characteristic equation of y′′+2y′+5y=0?
Answer: r2+2r+5=0. Substitute y′′=r2, y′=r into equation.
Flashcard 14: Define a non-homogeneous differential equation.
Answer: An equation with non-zero terms not involving the dependent variable. Contains terms independent of dependent variable.
Flashcard 15: Identify the homogeneous part of y′′+5y′+6y=ex.
Answer: y′′+5y′+6y. Left side when right side equals zero.
Flashcard 16: Solve y′=x1 for y.
Answer: y=ln∣x∣+C. Antiderivative of x1 is ln∣x∣.
Flashcard 17: What function solves y′−2y=0?
Answer: y=Ce2x. Exponential solution with coefficient k=2.
Flashcard 18: What is the solution to y′′−y=0?
Answer: y=C1ex+C2e−x. Characteristic equation r2−1=0 gives r=±1.
Flashcard 19: Identify the linear part of y′′+4y′+4y=5x.
Answer: y′′+4y′+4y. Terms involving y and its derivatives.
Flashcard 20: What is the solution for dy/dx=y using separation of variables?
Answer: y=Cex. Separate variables: ydy=dx, integrate.
Flashcard 21: What is the characteristic equation of y′′+4y′+4y=0?
Answer: r2+4r+4=0. Replace y′′ with r2, y′ with r.
Flashcard 22: State the general solution form for y′=ky.
Answer: y=Cekt, where C is a constant. Exponential growth/decay model solution.
Flashcard 23: Define a separable differential equation.
Answer: An equation where variables can be separated on opposite sides. Variables can be moved to opposite sides.
Flashcard 24: What is a homogeneous differential equation?
Answer: An equation where 0 is a solution when all terms set to 0. All terms involve the dependent variable.
Flashcard 25: Identify the type of differential equation: y′′+y=tan(x).
Answer: Second-order non-homogeneous differential equation. Second-order with non-zero right side.
Flashcard 26: Solve for y in the differential equation dxdy=0.
Answer: y=C, where C is a constant. Zero derivative means constant function.
Flashcard 27: What is the order of d2y/dx2+3y′+4y=x2?
Answer: Order is 2. Highest derivative is second order.
Flashcard 28: Identify the independent variable in dy/dx=x2+y2.
Answer: The independent variable is x. Variable with respect to which we differentiate.
Flashcard 29: What type of differential equation is y′+p(x)y=g(x)?
Answer: First-order linear differential equation. Standard form with y and y′ terms only.
Flashcard 30: Find the derivative of y=Cekt.
Answer: y′=kCekt. Apply chain rule: dtd(Cekt)=kCekt.