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This deck focuses on Defining Convergent And Divergent Infinite Series, giving you a quick way to review the definitions, rules, and examples that matter most for AP Calculus BC.
Study Defining Convergent And Divergent Infinite Series in AP Calculus BC with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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What is the Limit Comparison Test?
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A test comparing limits of two series to determine convergence. Compares behavior of two series at infinity.
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This deck focuses on Defining Convergent And Divergent Infinite Series, giving you a quick way to review the definitions, rules, and examples that matter most for AP Calculus BC.
Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
Answer: A test comparing limits of two series to determine convergence. Compares behavior of two series at infinity.
Answer: Convergent. It is an alternating series. Terms decrease and approach zero, satisfying AST.
Answer: Sn=1+21+31+...+n1. Sum of first n terms of the harmonic series.
Answer: Comparison Test or Limit Comparison Test. Best suited for rational function series.
Answer: If limn→∞n∣an∣<1. Limit less than 1 indicates series convergence.
Answer: A series where intermediate terms cancel out. Partial fractions create canceling patterns.
Answer: A test to determine convergence of series with alternating signs. Applies to series of form ∑(−1)nan.
Answer: The common ratio ∣r∣<1. This ensures each term becomes smaller than the previous.
Answer: When it converges, but its absolute value does not. Converges but not absolutely convergent.
Answer: The series 1+21+31+41+.... Famous divergent series despite terms approaching zero.
Answer: Convergent. It is an alternating harmonic series. Alternating signs with decreasing terms ensure convergence.
Answer: If limn→∞∣anan+1∣<1. Limit less than 1 guarantees series convergence.
Answer: The common ratio ∣r∣<1. This ensures each term becomes smaller than the previous.
Answer: Convergent. It is an alternating harmonic series. Alternating signs with decreasing terms ensure convergence.
Answer: Convergent. It is a geometric series with r=21. Since ∣21∣<1, the series converges.
Answer: A test used on series of form np1 to determine convergence. Determines convergence for power series forms.
Answer: Convergent. It satisfies the Alternating Series Test. Terms decrease in magnitude and approach zero.
Answer: A series ∑an is absolutely convergent if ∑∣an∣ converges. Stronger condition than simple convergence.
Answer: The series does not approach a finite limit. Partial sums fail to approach any finite value.
Answer: Convergent. It satisfies the Alternating Series Test. Terms decrease in magnitude and approach zero.
Answer: Convergent. It is a telescoping series. Partial fraction telescopes to finite sum.
Answer: Sn=1+21+31+...+n1. Sum of first n terms of the harmonic series.
Answer: Convergent. It is a p-series with p=1.5>1. P-series converges when exponent exceeds 1.
Answer: Divergent. Proven fact about this important series.
Answer: Geometric series with first term 1 and ratio x. Standard form with first term a=1 and ratio r=x.
Answer: If limn→∞bnan=c>0, both series converge or diverge. Finite positive limit links convergence behavior.
Answer: A series that does not approach a finite limit. Partial sums either grow without bound or oscillate.
Answer: The series does not approach a finite limit. Partial sums fail to approach any finite value.
Answer: A test used on series of form np1 to determine convergence. Determines convergence for power series forms.
Answer: Convergent. It is a geometric series with r=21. Since ∣21∣<1, the series converges.
Answer: The sum of the first n terms of a series. Building block for determining series convergence.
Answer: Comparison Test or Limit Comparison Test. Best suited for rational function series.
Answer: A test to determine convergence of series with alternating signs. Applies to series of form ∑(−1)nan.
Answer: The terms decrease in absolute value and approach zero. Both conditions must hold for convergence.
Answer: If ∫f(x)dx converges, then ∑an converges. Same convergence behavior as corresponding integral.
Answer: The sum of the first n terms of a series. Building block for determining series convergence.
Answer: A test using integrals to determine series convergence. Relates series convergence to improper integrals.
Answer: If \text{∫} f(x)dx converges, then \text{∑} a_n converges. Same convergence behavior as corresponding integral.
Answer: If limn→∞bnan=c>0, both series converge or diverge. Finite positive limit links convergence behavior.
Answer: A series that approaches a finite limit as more terms are added. Partial sums approach a specific value as n→∞.
Answer: Convergent. It is a telescoping series. Partial fraction telescopes to finite sum.
Answer: S=1−ra, where ∣r∣<1. Formula derived from infinite geometric series convergence.
Answer: A test using limn→∞n∣an∣. Uses n-th root of terms for convergence analysis.
Answer: A series ∑an is absolutely convergent if ∑∣an∣ converges. Stronger condition than simple convergence.
Answer: A test using anan+1 to determine convergence. Uses consecutive term ratios to test convergence.
Answer: A series that does not approach a finite limit. Partial sums either grow without bound or oscillate.
Answer: If limn→∞n∣an∣<1. Limit less than 1 indicates series convergence.
Answer: Converges if p>1. Critical threshold separating convergence from divergence.
Answer: When it converges, but its absolute value does not. Converges but not absolutely convergent.
Answer: Divergent. It is known as the harmonic series. Classic example of divergence despite decreasing terms.
Answer: If limn→∞∣anan+1∣<1. Limit less than 1 guarantees series convergence.
Answer: The series 1+21+31+41+.... Famous divergent series despite terms approaching zero.
Answer: S=1−ra, where ∣r∣<1. Formula derived from infinite geometric series convergence.
Answer: A sum of infinitely many terms, expressed as a1+a2+a3+.... The notation shows an endless sum of terms.
Answer: Divergent. Proven fact about this important series.
Answer: Convergent. It is an alternating series. Terms decrease and approach zero, satisfying AST.
Answer: Convergent. It is the exponential series. Factorial growth ensures rapid convergence.
Answer: Conditional convergence: series converges, but absolute value does not. Absolute convergence implies regular convergence.
Answer: The finite value the series approaches. This limit exists and is finite for convergent series.
Answer: Convergent. It is the exponential series. Factorial growth ensures rapid convergence.
Answer: 1. It is a geometric series with a=21, r=21. Using S=1−ra=1−1/21/2=1.