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  2. AP Calculus BC
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AP Calculus BC Flashcards: Taylor And Maclaurin Series

Study Taylor And Maclaurin Series in AP Calculus BC with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

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What this deck covers

This deck focuses on Taylor And Maclaurin Series, giving you a quick way to review the definitions, rules, and examples that matter most for AP Calculus BC.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

AP Calculus BC Flashcards: Taylor And Maclaurin Series

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QUESTION

Identify the interval of convergence for the Maclaurin series of exe^xex.

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ANSWER

(−∞,∞)(-\infty, \infty)(−∞,∞). Exponential function converges everywhere.

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Flashcard 1: Identify the interval of convergence for the Maclaurin series of exe^xex.

Answer: (−∞,∞)(-\infty, \infty)(−∞,∞). Exponential function converges everywhere.

Flashcard 2: State the formula for the nthn^{th}nth term of a Maclaurin series.

Answer: f(n)(0)xnn!\frac{f^{(n)}(0)x^n}{n!}n!f(n)(0)xn​. Maclaurin term with center at a=0a = 0a=0.

Flashcard 3: What is the Maclaurin series for exe^xex?

Answer: ex=1+x+x22!+x33!+...e^x = 1 + x + \frac{x^2}{2!} + \frac{x^3}{3!} + \text{...}ex=1+x+2!x2​+3!x3​+.... All derivatives of exe^xex equal exe^xex, so f(n)(0)=1f^{(n)}(0) = 1f(n)(0)=1.

Flashcard 4: What is the Maclaurin series for sin(x)\text{sin}(x)sin(x)?

Answer: sin(x)=x−x33!+x55!−x77!+...\text{sin}(x) = x - \frac{x^3}{3!} + \frac{x^5}{5!} - \frac{x^7}{7!} + \text{...}sin(x)=x−3!x3​+5!x5​−7!x7​+.... Alternating series with odd powers only.

Flashcard 5: Find f(2)(0)f^{(2)}(0)f(2)(0) for f(x)=x4f(x) = x^4f(x)=x4 in its Maclaurin series.

Answer: f(2)(0)=0f^{(2)}(0) = 0f(2)(0)=0. Second derivative of x4x^4x4 is 12x212x^212x2, so f′′(0)=0f''(0) = 0f′′(0)=0.

Flashcard 6: What is the Maclaurin series for tan−1(x)\text{tan}^{-1}(x)tan−1(x)?

Answer: tan−1(x)=x−x33+x55−...\text{tan}^{-1}(x) = x - \frac{x^3}{3} + \frac{x^5}{5} - \text{...}tan−1(x)=x−3x3​+5x5​−.... Same as arctan⁡(x)\arctan(x)arctan(x) series with alternating odd terms.

Flashcard 7: What is the Maclaurin series for cosh(x)\text{cosh}(x)cosh(x)?

Answer: cosh(x)=1+x22!+x44!+x66!+...\text{cosh}(x) = 1 + \frac{x^2}{2!} + \frac{x^4}{4!} + \frac{x^6}{6!} + \text{...}cosh(x)=1+2!x2​+4!x4​+6!x6​+.... Hyperbolic cosine has only even powers.

Flashcard 8: What is the general form of the Maclaurin series for a function f(x)f(x)f(x)?

Answer: f(x)=f(0)0!+f′(0)x1!+f′′(0)x22!+f′′′(0)x33!+...f(x) = \frac{f(0)}{0!} + \frac{f'(0)x}{1!} + \frac{f''(0)x^2}{2!} + \frac{f'''(0)x^3}{3!} + \text{...}f(x)=0!f(0)​+1!f′(0)x​+2!f′′(0)x2​+3!f′′′(0)x3​+.... Maclaurin series is Taylor series centered at a=0a = 0a=0.

Flashcard 9: Find the first derivative of f(x)=sin(x)f(x) = \text{sin}(x)f(x)=sin(x) for its Taylor series.

Answer: f′(x)=cos(x)f'(x) = \text{cos}(x)f′(x)=cos(x). First derivative of sin⁡(x)\sin(x)sin(x) is cos⁡(x)\cos(x)cos(x).

Flashcard 10: Find f(3)(0)f^{(3)}(0)f(3)(0) for f(x)=cos(x)f(x) = \text{cos}(x)f(x)=cos(x) in its Maclaurin series.

Answer: f(3)(0)=0f^{(3)}(0) = 0f(3)(0)=0. Third derivative of cos⁡(x)\cos(x)cos(x) is sin⁡(x)\sin(x)sin(x), so f(3)(0)=0f^{(3)}(0) = 0f(3)(0)=0.

Flashcard 11: State the Taylor polynomial of degree 2 for f(x)=sin(x)f(x) = \text{sin}(x)f(x)=sin(x) at a=0a = 0a=0.

Answer: x−x36x - \frac{x^3}{6}x−6x3​. First three terms of sine series (degree 2 has no x2x^2x2 term).

Flashcard 12: Find the third derivative f′′′(x)f'''(x)f′′′(x) for f(x)=x3f(x) = x^3f(x)=x3 in its Taylor series.

Answer: f′′′(x)=6f'''(x) = 6f′′′(x)=6. Third derivative of x3x^3x3 is constant 666.

Flashcard 13: What is f(2)(a)f^{(2)}(a)f(2)(a) for f(x)=x2f(x) = x^2f(x)=x2 in its Taylor series centered at a=3a = 3a=3?

Answer: f(2)(3)=2f^{(2)}(3) = 2f(2)(3)=2. Second derivative of x2x^2x2 is constant 222.

Flashcard 14: What is the Maclaurin series for sinh(x)\text{sinh}(x)sinh(x)?

Answer: sinh(x)=x+x33!+x55!+x77!+...\text{sinh}(x) = x + \frac{x^3}{3!} + \frac{x^5}{5!} + \frac{x^7}{7!} + \text{...}sinh(x)=x+3!x3​+5!x5​+7!x7​+.... Hyperbolic sine has only odd powers.

Flashcard 15: Find f′(0)f'(0)f′(0) for f(x)=arctan(x)f(x) = \text{arctan}(x)f(x)=arctan(x) in its Maclaurin series.

Answer: f′(0)=1f'(0) = 1f′(0)=1. First derivative of arctan⁡(x)\arctan(x)arctan(x) is 11+x2\frac{1}{1+x^2}1+x21​, so f′(0)=1f'(0) = 1f′(0)=1.

Flashcard 16: What is the radius of convergence for the series of f(x)=11−xf(x) = \frac{1}{1-x}f(x)=1−x1​?

Answer: R=1R = 1R=1. Geometric series converges when ∣x∣<1|x| < 1∣x∣<1.

Flashcard 17: Determine f(4)(0)f^{(4)}(0)f(4)(0) for f(x)=exf(x) = e^xf(x)=ex in its Maclaurin series.

Answer: f(4)(0)=1f^{(4)}(0) = 1f(4)(0)=1. All derivatives of exe^xex equal 111 at x=0x = 0x=0.

Flashcard 18: Find the second derivative of f(x)=exf(x) = e^xf(x)=ex for its Taylor series.

Answer: f′′(x)=exf''(x) = e^xf′′(x)=ex. All derivatives of exe^xex equal exe^xex.

Flashcard 19: Evaluate f(4)(0)f^{(4)}(0)f(4)(0) for f(x)=x4f(x) = x^4f(x)=x4 in its Maclaurin series.

Answer: f(4)(0)=24f^{(4)}(0) = 24f(4)(0)=24. Fourth derivative of x4x^4x4 is constant 242424.

Flashcard 20: What is the Maclaurin series for cos(x)\text{cos}(x)cos(x)?

Answer: cos(x)=1−x22!+x44!−x66!+...\text{cos}(x) = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{6!} + \text{...}cos(x)=1−2!x2​+4!x4​−6!x6​+.... Alternating series with even powers only.

Flashcard 21: What is the Maclaurin series for 11−x\frac{1}{1-x}1−x1​?

Answer: 11−x=1+x+x2+x3+...\frac{1}{1-x} = 1 + x + x^2 + x^3 + \text{...}1−x1​=1+x+x2+x3+.... Geometric series with first term 111 and ratio xxx.

Flashcard 22: State the formula for the nthn^{th}nth term of a Taylor series.

Answer: f(n)(a)(x−a)nn!\frac{f^{(n)}(a)(x-a)^n}{n!}n!f(n)(a)(x−a)n​. Standard form for any term in Taylor expansion.

Flashcard 23: Evaluate f′(0)f'(0)f′(0) for f(x)=cos(x)f(x) = \text{cos}(x)f(x)=cos(x) in its Maclaurin series.

Answer: f′(0)=0f'(0) = 0f′(0)=0. First derivative of cos⁡(x)\cos(x)cos(x) is −sin⁡(x)-\sin(x)−sin(x), so f′(0)=0f'(0) = 0f′(0)=0.

Flashcard 24: What is the Maclaurin series for ln(1+x)\text{ln}(1+x)ln(1+x)?

Answer: ln(1+x)=x−x22+x33−x44+...\text{ln}(1+x) = x - \frac{x^2}{2} + \frac{x^3}{3} - \frac{x^4}{4} + \text{...}ln(1+x)=x−2x2​+3x3​−4x4​+.... Alternating series with coefficients 1n\frac{1}{n}n1​.

Flashcard 25: Evaluate f(0)f(0)f(0) for f(x)=ln(1+x)f(x) = \text{ln}(1+x)f(x)=ln(1+x) in its Maclaurin series.

Answer: f(0)=0f(0) = 0f(0)=0. Natural log of 111 equals 000.

Flashcard 26: What is the Taylor polynomial of degree 3 for f(x)=ln(x)f(x) = \text{ln}(x)f(x)=ln(x) at a=1a = 1a=1?

Answer: 0+(x−1)−(x−1)22+(x−1)330 + (x-1) - \frac{(x-1)^2}{2} + \frac{(x-1)^3}{3}0+(x−1)−2(x−1)2​+3(x−1)3​. Taylor series for ln⁡(x)\ln(x)ln(x) using derivatives at x=1x = 1x=1.

Flashcard 27: What is the Maclaurin series for arctan(x)\text{arctan}(x)arctan(x)?

Answer: arctan(x)=x−x33+x55−x77+...\text{arctan}(x) = x - \frac{x^3}{3} + \frac{x^5}{5} - \frac{x^7}{7} + \text{...}arctan(x)=x−3x3​+5x5​−7x7​+.... Alternating series with odd powers and reciprocal coefficients.

Flashcard 28: Determine the interval of convergence for ln(1+x)\text{ln}(1+x)ln(1+x) Maclaurin series.

Answer: (−1,1](-1, 1](−1,1]. Series converges for −1<x≤1-1 < x \leq 1−1<x≤1.

Flashcard 29: What is the general form of the Taylor series for a function f(x)f(x)f(x) centered at aaa?

Answer: f(x)=f(a)0!+f′(a)(x−a)1!+f′′(a)(x−a)22!+f′′′(a)(x−a)33!+...f(x) = \frac{f(a)}{0!} + \frac{f'(a)(x-a)}{1!} + \frac{f''(a)(x-a)^2}{2!} + \frac{f'''(a)(x-a)^3}{3!} + \text{...}f(x)=0!f(a)​+1!f′(a)(x−a)​+2!f′′(a)(x−a)2​+3!f′′′(a)(x−a)3​+.... General Taylor series formula using derivatives at center aaa.

Flashcard 30: Calculate f(3)(a)f^{(3)}(a)f(3)(a) for f(x)=x3f(x) = x^3f(x)=x3 in its Taylor series at a=1a = 1a=1.

Answer: f(3)(1)=6f^{(3)}(1)= 6f(3)(1)=6. Third derivative of x3x^3x3 is constant 666.