All flashcards
Flashcard 1: Identify the interval of convergence for the Maclaurin series of ex.
Answer: (−∞,∞). Exponential function converges everywhere.
Flashcard 2: State the formula for the nth term of a Maclaurin series.
Answer: n!f(n)(0)xn. Maclaurin term with center at a=0.
Flashcard 3: What is the Maclaurin series for ex?
Answer: ex=1+x+2!x2+3!x3+.... All derivatives of ex equal ex, so f(n)(0)=1.
Flashcard 4: What is the Maclaurin series for sin(x)?
Answer: sin(x)=x−3!x3+5!x5−7!x7+.... Alternating series with odd powers only.
Flashcard 5: Find f(2)(0) for f(x)=x4 in its Maclaurin series.
Answer: f(2)(0)=0. Second derivative of x4 is 12x2, so f′′(0)=0.
Flashcard 6: What is the Maclaurin series for tan−1(x)?
Answer: tan−1(x)=x−3x3+5x5−.... Same as arctan(x) series with alternating odd terms.
Flashcard 7: What is the Maclaurin series for cosh(x)?
Answer: cosh(x)=1+2!x2+4!x4+6!x6+.... Hyperbolic cosine has only even powers.
Flashcard 8: What is the general form of the Maclaurin series for a function f(x)?
Answer: f(x)=0!f(0)+1!f′(0)x+2!f′′(0)x2+3!f′′′(0)x3+.... Maclaurin series is Taylor series centered at a=0.
Flashcard 9: Find the first derivative of f(x)=sin(x) for its Taylor series.
Answer: f′(x)=cos(x). First derivative of sin(x) is cos(x).
Flashcard 10: Find f(3)(0) for f(x)=cos(x) in its Maclaurin series.
Answer: f(3)(0)=0. Third derivative of cos(x) is sin(x), so f(3)(0)=0.
Flashcard 11: State the Taylor polynomial of degree 2 for f(x)=sin(x) at a=0.
Answer: x−6x3. First three terms of sine series (degree 2 has no x2 term).
Flashcard 12: Find the third derivative f′′′(x) for f(x)=x3 in its Taylor series.
Answer: f′′′(x)=6. Third derivative of x3 is constant 6.
Flashcard 13: What is f(2)(a) for f(x)=x2 in its Taylor series centered at a=3?
Answer: f(2)(3)=2. Second derivative of x2 is constant 2.
Flashcard 14: What is the Maclaurin series for sinh(x)?
Answer: sinh(x)=x+3!x3+5!x5+7!x7+.... Hyperbolic sine has only odd powers.
Flashcard 15: Find f′(0) for f(x)=arctan(x) in its Maclaurin series.
Answer: f′(0)=1. First derivative of arctan(x) is 1+x21, so f′(0)=1.
Flashcard 16: What is the radius of convergence for the series of f(x)=1−x1?
Answer: R=1. Geometric series converges when ∣x∣<1.
Flashcard 17: Determine f(4)(0) for f(x)=ex in its Maclaurin series.
Answer: f(4)(0)=1. All derivatives of ex equal 1 at x=0.
Flashcard 18: Find the second derivative of f(x)=ex for its Taylor series.
Answer: f′′(x)=ex. All derivatives of ex equal ex.
Flashcard 19: Evaluate f(4)(0) for f(x)=x4 in its Maclaurin series.
Answer: f(4)(0)=24. Fourth derivative of x4 is constant 24.
Flashcard 20: What is the Maclaurin series for cos(x)?
Answer: cos(x)=1−2!x2+4!x4−6!x6+.... Alternating series with even powers only.
Flashcard 21: What is the Maclaurin series for 1−x1?
Answer: 1−x1=1+x+x2+x3+.... Geometric series with first term 1 and ratio x.
Flashcard 22: State the formula for the nth term of a Taylor series.
Answer: n!f(n)(a)(x−a)n. Standard form for any term in Taylor expansion.
Flashcard 23: Evaluate f′(0) for f(x)=cos(x) in its Maclaurin series.
Answer: f′(0)=0. First derivative of cos(x) is −sin(x), so f′(0)=0.
Flashcard 24: What is the Maclaurin series for ln(1+x)?
Answer: ln(1+x)=x−2x2+3x3−4x4+.... Alternating series with coefficients n1.
Flashcard 25: Evaluate f(0) for f(x)=ln(1+x) in its Maclaurin series.
Answer: f(0)=0. Natural log of 1 equals 0.
Flashcard 26: What is the Taylor polynomial of degree 3 for f(x)=ln(x) at a=1?
Answer: 0+(x−1)−2(x−1)2+3(x−1)3. Taylor series for ln(x) using derivatives at x=1.
Flashcard 27: What is the Maclaurin series for arctan(x)?
Answer: arctan(x)=x−3x3+5x5−7x7+.... Alternating series with odd powers and reciprocal coefficients.
Flashcard 28: Determine the interval of convergence for ln(1+x) Maclaurin series.
Answer: (−1,1]. Series converges for −1<x≤1.
Flashcard 29: What is the general form of the Taylor series for a function f(x) centered at a?
Answer: f(x)=0!f(a)+1!f′(a)(x−a)+2!f′′(a)(x−a)2+3!f′′′(a)(x−a)3+.... General Taylor series formula using derivatives at center a.
Flashcard 30: Calculate f(3)(a) for f(x)=x3 in its Taylor series at a=1.
Answer: f(3)(1)=6. Third derivative of x3 is constant 6.