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  2. AP Calculus BC
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AP Calculus BC Flashcards: Defining Limits And Using Limit Notation

Study Defining Limits And Using Limit Notation in AP Calculus BC with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

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What this deck covers

This deck focuses on Defining Limits And Using Limit Notation, giving you a quick way to review the definitions, rules, and examples that matter most for AP Calculus BC.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

AP Calculus BC Flashcards: Defining Limits And Using Limit Notation

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QUESTION

What is the limit of a constant times a function: limx→c[k×f(x)]\text{lim}_{x \to c} [k \times f(x)]limx→c​[k×f(x)]?

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ANSWER

k×limx→cf(x)k \times \text{lim}_{x \to c} f(x)k×limx→c​f(x). Constants factor out of limits when the limit of the function exists.

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Flashcard 1: What is the limit of a constant times a function: limx→c[k×f(x)]\text{lim}_{x \to c} [k \times f(x)]limx→c​[k×f(x)]?

Answer: k×limx→cf(x)k \times \text{lim}_{x \to c} f(x)k×limx→c​f(x). Constants factor out of limits when the limit of the function exists.

Flashcard 2: What is the limit of x2x^2x2 as xxx approaches 3?

Answer:

  1. Direct substitution works since x2x^2x2 is continuous at x=3x = 3x=3.

Flashcard 3: What is the limit of cos(x)\text{cos}(x)cos(x) as xxx approaches 0?

Answer:

  1. Cosine is continuous at zero, so direct substitution gives cos⁡(0)=1\cos(0) = 1cos(0)=1.

Flashcard 4: What is the limit of x3x^3x3 as xxx approaches −2-2−2?

Answer: −8-8−8. Direct substitution: (−2)3=−8(-2)^3 = -8(−2)3=−8.

Flashcard 5: State the basic limit property: limx→c[f(x)×g(x)]\text{lim}_{x \to c} [f(x) \times g(x)]limx→c​[f(x)×g(x)].

Answer: limx→cf(x)×limx→cg(x)\text{lim}_{x \to c} f(x) \times \text{lim}_{x \to c} g(x)limx→c​f(x)×limx→c​g(x). The limit of a product equals the product of the limits when both limits exist.

Flashcard 6: What is the limit of 1x\frac{1}{x}x1​ as xxx approaches 0 from the left?

Answer: limx→0−1x=−inf\text{lim}_{x \to 0^-} \frac{1}{x} = -\text{inf}limx→0−​x1​=−inf. Approaching zero from negative values makes the fraction arbitrarily large and negative.

Flashcard 7: What does it mean for a limit to be infinite?

Answer: The function grows without bound as xxx approaches a value. The function increases or decreases without bound near the specified point.

Flashcard 8: What is the limit of e−xe^{-x}e−x as xxx approaches infinity?

Answer:

  1. Exponential decay functions approach zero as the exponent becomes large.

Flashcard 9: What is the limit of 1x\frac{1}{x}x1​ as xxx approaches 0 from the right?

Answer: limx→0+1x=+inf\text{lim}_{x \to 0^+} \frac{1}{x} = +\text{inf}limx→0+​x1​=+inf. Approaching zero from positive values makes the fraction arbitrarily large and positive.

Flashcard 10: What is the limit of x2x^2x2 as xxx approaches infinity?

Answer: Infinity. Quadratic functions grow without bound as xxx approaches infinity.

Flashcard 11: What is the limit of exe^xex as xxx approaches infinity?

Answer: Infinity. Exponential functions with base greater than 1 grow without bound as exponent increases.

Flashcard 12: State the limit of a sum of two functions: limx→c[f(x)+g(x)]\text{lim}_{x \to c} [f(x) + g(x)]limx→c​[f(x)+g(x)].

Answer: limx→cf(x)+limx→cg(x)\text{lim}_{x \to c} f(x) + \text{lim}_{x \to c} g(x)limx→c​f(x)+limx→c​g(x). The limit of a sum equals the sum of the limits when both limits exist.

Flashcard 13: What is the limit of xxx as xxx approaches 5?

Answer:

  1. Direct substitution works since f(x)=xf(x) = xf(x)=x is continuous everywhere.

Flashcard 14: What is the limit of ln(x)\text{ln}(x)ln(x) as xxx approaches 0 from the right?

Answer: −inf-\text{inf}−inf. The natural logarithm approaches negative infinity as its argument approaches zero.

Flashcard 15: What is the limit of x3x^3x3 as xxx approaches infinity?

Answer: Infinity. Cubic functions with positive leading coefficient grow without bound as x→∞x \to \inftyx→∞.

Flashcard 16: State the limit property for a function divided by a constant.

Answer: limx→cf(x)k\frac{\text{lim}_{x \to c} f(x)}{k}klimx→c​f(x)​. Dividing by a non-zero constant is equivalent to multiplying by 1k\frac{1}{k}k1​.

Flashcard 17: What is the limit of a constant function f(x)=kf(x) = kf(x)=k as xxx approaches ccc?

Answer: kkk. Constant functions have the same value everywhere, so the limit equals the constant.

Flashcard 18: State the limit of sin(x)x\frac{\text{sin}(x)}{x}xsin(x)​ as xxx approaches infinity.

Answer:

  1. The sine function oscillates between -1 and 1, so sin⁡(x)x→0\frac{\sin(x)}{x} \to 0xsin(x)​→0 as x→∞x \to \inftyx→∞.

Flashcard 19: State the Squeeze Theorem in limit notation.

Answer: If g(x)→Lg(x) \rightarrow Lg(x)→L and h(x)→Lh(x) \rightarrow Lh(x)→L, then f(x)→Lf(x) \rightarrow Lf(x)→L. If f(x)f(x)f(x) is squeezed between two functions with the same limit, f(x)f(x)f(x) has that limit.

Flashcard 20: What is the limit of 1/x1/x1/x as xxx approaches negative infinity?

Answer:

  1. As xxx becomes large and negative, 1x\frac{1}{x}x1​ approaches zero from below.

Flashcard 21: State the condition for the existence of a finite limit of f(x)f(x)f(x) as xxx approaches ccc.

Answer: The left-hand and right-hand limits must be equal. This ensures the limit is unique and well-defined.

Flashcard 22: Identify the notation used to denote the right-hand limit.

Answer: limx→c+f(x)\text{lim}_{x \to c^+} f(x)limx→c+​f(x). The plus sign indicates approaching from values greater than ccc.

Flashcard 23: Identify the notation used to denote the left-hand limit.

Answer: limx→c−f(x)\text{lim}_{x \to c^-} f(x)limx→c−​f(x). The minus sign indicates approaching from values less than ccc.

Flashcard 24: What is the limit of x4x^4x4 as xxx approaches 2?

Answer:

  1. Direct substitution: 24=162^4 = 1624=16.

Flashcard 25: What is the limit of x2+3x+2x^2 + 3x + 2x2+3x+2 as xxx approaches -1?

Answer:

  1. Direct substitution: (−1)2+3(−1)+2=1−3+2=0(-1)^2 + 3(-1) + 2 = 1 - 3 + 2 = 0(−1)2+3(−1)+2=1−3+2=0.

Flashcard 26: State the limit notation for f(x)f(x)f(x) as xxx approaches ccc.

Answer: limx→cf(x)\text{lim}_{x \to c} f(x)limx→c​f(x). Standard notation where xxx approaches ccc and we evaluate the limit of f(x)f(x)f(x).

Flashcard 27: What is the limit of x2−1x−1\frac{x^2 - 1}{x - 1}x−1x2−1​ as xxx approaches 1?

Answer:

  1. Factor and cancel: (x−1)(x+1)x−1=x+1\frac{(x-1)(x+1)}{x-1} = x+1x−1(x−1)(x+1)​=x+1, then substitute x=1x = 1x=1.

Flashcard 28: What is the definition of a limit of a function as x approaches a constant c?

Answer: The value that f(x)f(x)f(x) approaches as xxx approaches ccc. This describes how a function behaves near a point without requiring the function to be defined there.

Flashcard 29: What is the limit of tan(x)\text{tan}(x)tan(x) as xxx approaches 0?

Answer:

  1. Tangent is continuous at zero, so direct substitution gives tan⁡(0)=0\tan(0) = 0tan(0)=0.

Flashcard 30: State the basic limit property: limx→c[f(x)+g(x)]\text{lim}_{x \to c} [f(x) + g(x)]limx→c​[f(x)+g(x)].

Answer: limx→cf(x)+limx→cg(x)\text{lim}_{x \to c} f(x) + \text{lim}_{x \to c} g(x)limx→c​f(x)+limx→c​g(x). The limit of a sum equals the sum of the limits when both limits exist.