AP Calculus BC Flashcards: The Nth Term Test For Divergence
Study The Nth Term Test For Divergence in AP Calculus BC with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
This deck focuses on The Nth Term Test For Divergence, giving you a quick way to review the definitions, rules, and examples that matter most for AP Calculus BC.
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AP Calculus BC Flashcards: The Nth Term Test For Divergence
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QUESTION
Evaluate limn→∞n+33n. Divergent?
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ANSWER
Limit is 3; series diverges. Leading terms give ratio 13=3=0.
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Flashcard 1: Evaluate limn→∞n+33n. Divergent?
Answer: Limit is 3; series diverges. Leading terms give ratio 13=3=0.
Flashcard 2: Evaluate limn→∞n2. Divergent?
Answer: Limit is 0; test inconclusive. Constant multiple of n1 still gives limit 0.
Flashcard 3: Assess limn→∞n2n+1. Divergent?
Answer: Limit is 2; series diverges. Dividing gives 2+n1, limit 2.
Flashcard 4: What if limn→∞an=0?
Answer: Series ∑an diverges. Non-zero limit always implies divergence by the test.
Flashcard 5: Find limn→∞n3+1n2.
Answer: Limit is 0; test inconclusive. Highest degree terms show limit is 0, test inconclusive.
Flashcard 6: Determine divergence: limn→∞(−1)n.
Answer: Does not exist; series diverges. Oscillating sequence has no limit, so series diverges.
Flashcard 7: Evaluate limn→∞n31. Divergent?
Answer: Limit is 0; test inconclusive. Higher power in denominator gives limit 0.
Flashcard 8: Assess divergence: limn→∞n+2n+1.
Answer: Limit is 1; series diverges. Both numerator and denominator approach ∞, limit is 1.
Flashcard 9: Evaluate limn→∞n+1n for divergence.
Answer: Limit is 1; series diverges. Since limit equals 1=0, the test proves divergence.
Flashcard 10: Evaluate divergence: limn→∞3n5n
Answer: Limit is 35; series diverges. Coefficients cancel to give limit 35=0
Flashcard 11: What is the nth term test for divergence?
Answer: If limn→∞an=0, then ∑an diverges. The fundamental condition for proving a series diverges.
Flashcard 12: What does limn→∞an=L=0 imply?
Answer: Series ∑an diverges. Any non-zero limit guarantees series divergence.
Flashcard 13: Does limn→∞an=0 guarantee convergence?
Answer: No, it does not guarantee convergence. Zero limit is necessary but not sufficient for convergence.
Flashcard 14: What conclusion if limn→∞an=0?
Answer: Test is inconclusive. Zero limit cannot determine convergence or divergence.
Flashcard 15: Does limn→∞an=d=0 infer divergence?
Answer: Yes, series ∑an diverges. Any non-zero constant limit proves divergence.
Flashcard 16: Determine limn→∞nn+5. Divergent?
Answer: Limit is 1; series diverges. Adding constant to numerator gives limit 1.
Flashcard 17: Determine divergence: limn→∞n.
Answer: Limit is ∞; series diverges. Square root grows without bound to infinity.
Flashcard 18: What does limn→∞an=0 indicate?
Answer: Test is inconclusive. Zero limit cannot prove convergence or divergence alone.
Flashcard 19: Identify limn→∞2n34n3. Divergent?
Answer: Limit is 2; series diverges. Coefficients simplify to 24=2=0.
Flashcard 20: Evaluate divergence: an=sin(n).
Answer: limn→∞an does not exist; series diverges. Sine function oscillates, so limit doesn't exist.