All flashcards
Flashcard 1: What test helps confirm if a critical point is an extremum?
Answer: The First Derivative Test. Distinguishes between maxima, minima, and inflection points.
Flashcard 2: What test helps confirm if a critical point is an extremum?
Answer: The First Derivative Test. Distinguishes between maxima, minima, and inflection points.
Flashcard 3: State the condition for a critical point.
Answer: f′(x)=0 or f′(x) is undefined. Necessary condition for potential extrema to exist.
Flashcard 4: Which test determines where a function is increasing or decreasing?
Answer: The First Derivative Test. Sign of f′(x) determines increasing/decreasing intervals.
Flashcard 5: What indicates a relative minimum using the First Derivative Test?
Answer: Derivative changes from negative to positive. Sign change from − to + creates a valley in the graph.
Flashcard 6: What indicates a relative maximum using the First Derivative Test?
Answer: Derivative changes from positive to negative. Sign change from + to − creates a peak in the graph.
Flashcard 7: What is a relative extremum?
Answer: A point where f(x) changes from increasing to decreasing or vice versa. Local maximum or minimum where function direction reverses.
Flashcard 8: What is the derivative of f(x)=31x3−x?
Answer: f′(x)=x2−1. Apply power rule to each term separately.
Flashcard 9: Identify the relative extrema: f(x)=x3−3x2.
Answer: Relative maximum at x=0; relative minimum at x=2. f′(x)=3x2−6x; sign changes at x=0 and x=2.
Flashcard 10: What does f′(x)>0 indicate about f(x)?
Answer: f(x) is increasing. Positive derivative means function values are rising.
Flashcard 11: Describe the behavior if f′(x) changes from negative to positive.
Answer: There's a relative minimum. Function reaches a valley; slope changes from downward to upward.
Flashcard 12: What is the derivative of f(x)=x5−5x3?
Answer: f′(x)=5x4−15x2. Power rule applied to polynomial with multiple terms.
Flashcard 13: Find the derivative of f(x)=x3−3x2+2x.
Answer: f′(x)=3x2−6x+2. Apply power rule term by term to the polynomial.
Flashcard 14: Find the derivative: f(x)=x4−4x3.
Answer: f′(x)=4x3−12x2. Apply power rule: multiply by exponent, reduce exponent by 1.
Flashcard 15: Determine if there is a minimum at x=0 for f(x)=x2.
Answer: Yes, minimum at x=0. f′(x)=2x changes from negative to positive at origin.
Flashcard 16: Find f′(x) for f(x)=x3−9x2+27x.
Answer: f′(x)=3x2−18x+27. Apply power rule to each term in the polynomial.
Flashcard 17: Evaluate f′(x) at x=0 for f(x)=31x3−x.
Answer: f′(0)=−1. Substitute x=0 into f′(x)=x2−1.
Flashcard 18: Determine relative extrema for f(x)=x3−3x+1 using the test.
Answer: No relative extrema. f′(x)=3x2−3=0 at x=±1; no sign changes.
Flashcard 19: Describe the behavior if f′(x) changes from positive to negative.
Answer: There's a relative maximum. Function reaches a peak; slope changes from upward to downward.
Flashcard 20: Determine if there is an extremum at x=1 for f(x)=2x3−3x2.
Answer: No extremum at x=1. f′(x)=6x2−6x; no sign change at x=1.
Flashcard 21: Determine extrema for f(x)=x2−4x+3 using the test.
Answer: Minimum at x=2. f′(x)=2x−4=0 at x=2; sign changes from − to +.
Flashcard 22: What is the next step after finding critical points in the test?
Answer: Evaluate f′(x) around critical points. Check sign changes of f′(x) on intervals around each critical point.
Flashcard 23: What must be true for a critical point to be a local extremum?
Answer: The derivative must change signs. Sign change of f′(x) distinguishes extrema from inflection points.
Flashcard 24: Identify extrema for f(x)=x2−2x+1 using the test.
Answer: Minimum at x=1. f′(x)=2x−2=0 at x=1; sign changes from − to +.
Flashcard 25: Determine if there is a maximum at x=0 for f(x)=−x2.
Answer: Yes, maximum at x=0. f′(x)=−2x changes from positive to negative at origin.
Flashcard 26: What is the derivative of f(x)=x2−4x?
Answer: f′(x)=2x−4. Basic power rule: derivative of x2 is 2x.
Flashcard 27: Find f′(x): f(x)=2x5−5x4.
Answer: f′(x)=10x4−20x3. Apply power rule: bring down exponent, reduce power by 1.
Flashcard 28: Evaluate f′(x) at x=2 for f(x)=x3−3x2.
Answer: f′(2)=0. Substitute x=2 into f′(x)=3x2−6x.
Flashcard 29: Find f′(x): f(x)=3x3−x.
Answer: f′(x)=x2−1. Standard power rule application with fractional coefficient.
Flashcard 30: Determine relative extrema for f(x)=x2 using the test.
Answer: Minimum at x=0. f′(x)=2x; changes from − to + at x=0.