AP Calculus BC Flashcards: Harmonic Series And P Series

Study Harmonic Series And P Series in AP Calculus BC with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

AP Calculus BC

Harmonic Series And P Series

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QUESTION
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What type of series is n=11n0.3\sum_{n=1}^{\infty} \frac{1}{n^{0.3}}?

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ANSWER

p-series. Has form 1np\sum \frac{1}{n^p} with p=0.3p = 0.3.

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This deck focuses on Harmonic Series And P Series, giving you a quick way to review the definitions, rules, and examples that matter most for AP Calculus BC.

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Flashcard 1: What type of series is n=11n0.3\sum_{n=1}^{\infty} \frac{1}{n^{0.3}}?

Answer: p-series. Has form 1np\sum \frac{1}{n^p} with p=0.3p = 0.3.

Flashcard 2: What is the condition for the convergence of a harmonic series?

Answer: Always diverges. The harmonic series is famously always divergent.

Flashcard 3: Does the series n=11n\sum_{n=1}^{\infty} \frac{1}{n} converge or diverge?

Answer: Diverges. The harmonic series is the classic divergent series.

Flashcard 4: Identify the convergence of n=11n2\sum_{n=1}^{\infty} \frac{1}{n^2}.

Answer: Converges. Since p=2>1p = 2 > 1, this p-series converges.

Flashcard 5: Is n=11n0.5\sum_{n=1}^{\infty} \frac{1}{n^{0.5}} convergent or divergent?

Answer: Divergent. Since p=0.51p = 0.5 \leq 1, this p-series diverges.

Flashcard 6: What type of series is n=11n1.5\sum_{n=1}^{\infty} \frac{1}{n^{1.5}}?

Answer: p-series. Has the form 1np\sum \frac{1}{n^p} with p=1.5p = 1.5.

Flashcard 7: What is the nature of n=11n2.1\sum_{n=1}^{\infty} \frac{1}{n^{2.1}}?

Answer: Convergent. Since p=2.1>1p = 2.1 > 1, this p-series converges.

Flashcard 8: What is the fifth term of a harmonic series?

Answer: 15\frac{1}{5}. The fifth term in the harmonic series is 15\frac{1}{5}.

Flashcard 9: Does the series n=11n\sum_{n=1}^{\infty} \frac{1}{n} converge or diverge?

Answer: Diverges. The harmonic series is the classic divergent series.

Flashcard 10: Identify the series that converges: n=11n3\sum_{n=1}^{\infty} \frac{1}{n^3} or n=11n\sum_{n=1}^{\infty} \frac{1}{n}.

Answer: n=11n3\sum_{n=1}^{\infty} \frac{1}{n^3}. Since p=3>1p = 3 > 1, the first series converges.

Flashcard 11: Identify if n=11n1/2\sum_{n=1}^{\infty} \frac{1}{n^{1/2}} converges or diverges.

Answer: Diverges. Since p=0.5<1p = 0.5 < 1, this p-series diverges.

Flashcard 12: For which values of pp does n=11np\sum_{n=1}^{\infty} \frac{1}{n^p} diverge?

Answer: p1p \leq 1. P-series diverge when pp is at most 1.

Flashcard 13: What is the condition for the convergence of a harmonic series?

Answer: Always diverges. The harmonic series is famously always divergent.

Flashcard 14: What is the fourth term of a harmonic series?

Answer: 14\frac{1}{4}. The fourth term in the harmonic series is 14\frac{1}{4}.

Flashcard 15: Does the series n=11n3.5\sum_{n=1}^{\infty} \frac{1}{n^{3.5}} converge?

Answer: Converges. Since p=3.5>1p = 3.5 > 1, this p-series converges.

Flashcard 16: State the convergence of n=11n0.8\sum_{n=1}^{\infty} \frac{1}{n^{0.8}}.

Answer: Diverges. Since p=0.8<1p = 0.8 < 1, this p-series diverges.

Flashcard 17: Identify if the series n=11n0.6\sum_{n=1}^{\infty} \frac{1}{n^{0.6}} is convergent.

Answer: Diverges. Since p=0.6<1p = 0.6 < 1, this p-series diverges.

Flashcard 18: What condition makes a p-series converge?

Answer: Converges if p>1p > 1. When p>1p > 1, the terms decrease fast enough for convergence.

Flashcard 19: Identify the type of series: n=11n0.9\sum_{n=1}^{\infty} \frac{1}{n^{0.9}}.

Answer: p-series. Has form 1np\sum \frac{1}{n^p} with p=0.9p = 0.9.

Flashcard 20: What is the second term of a harmonic series?

Answer: 12\frac{1}{2}. The second term in the harmonic series is 12\frac{1}{2}.

Flashcard 21: For which pp is the series n=11np\sum_{n=1}^{\infty} \frac{1}{n^p} divergent?

Answer: p1p \leq 1. P-series diverge when pp is at most 1.

Flashcard 22: Does n=11n0.7\sum_{n=1}^{\infty} \frac{1}{n^{0.7}} converge or diverge?

Answer: Diverges. Since p=0.7<1p = 0.7 < 1, this p-series diverges.

Flashcard 23: Determine the convergence of n=11n4\sum_{n=1}^{\infty} \frac{1}{n^{4}}.

Answer: Converges. Since p=4>1p = 4 > 1, this p-series converges.

Flashcard 24: Identify if the series n=11n0.6\sum_{n=1}^{\infty} \frac{1}{n^{0.6}} is convergent.

Answer: Diverges. Since p=0.6<1p = 0.6 < 1, this p-series diverges.

Flashcard 25: Identify the series that converges: n=11n3\sum_{n=1}^{\infty} \frac{1}{n^3} or n=11n\sum_{n=1}^{\infty} \frac{1}{n}.

Answer: n=11n3\sum_{n=1}^{\infty} \frac{1}{n^3}. Since p=3>1p = 3 > 1, the first series converges.

Flashcard 26: Identify if the series n=11n1.5\sum_{n=1}^{\infty} \frac{1}{n^{1.5}} converges.

Answer: Converges. Since p=1.5>1p = 1.5 > 1, this p-series converges.

Flashcard 27: Identify if n=11n3/2\sum_{n=1}^{\infty} \frac{1}{n^{3/2}} converges or diverges.

Answer: Converges. Since p=1.5>1p = 1.5 > 1, this p-series converges.

Flashcard 28: What is the definition of a harmonic series?

Answer: The series n=11n\sum_{n=1}^{\infty} \frac{1}{n}. The classic divergent series with terms 1n\frac{1}{n}.

Flashcard 29: Identify if the series n=11n1.5\sum_{n=1}^{\infty} \frac{1}{n^{1.5}} converges.

Answer: Converges. Since p=1.5>1p = 1.5 > 1, this p-series converges.

Flashcard 30: Which series is divergent: n=11n\sum_{n=1}^{\infty} \frac{1}{n} or n=11n2\sum_{n=1}^{\infty} \frac{1}{n^2}?

Answer: n=11n\sum_{n=1}^{\infty} \frac{1}{n}. The harmonic series diverges while 1n2\sum \frac{1}{n^2} converges.

Flashcard 31: What is the third term of a harmonic series?

Answer: 13\frac{1}{3}. The third term in the harmonic series is 13\frac{1}{3}.

Flashcard 32: Identify the type of series: n=11n0.9\sum_{n=1}^{\infty} \frac{1}{n^{0.9}}.

Answer: p-series. Has form 1np\sum \frac{1}{n^p} with p=0.9p = 0.9.

Flashcard 33: What type of series is n=11n1.5\sum_{n=1}^{\infty} \frac{1}{n^{1.5}}?

Answer: p-series. Has the form 1np\sum \frac{1}{n^p} with p=1.5p = 1.5.

Flashcard 34: What condition makes a p-series diverge?

Answer: Diverges if p1p \leq 1. When p1p \leq 1, terms don't decrease fast enough.

Flashcard 35: What is the fourth term of a harmonic series?

Answer: 14\frac{1}{4}. The fourth term in the harmonic series is 14\frac{1}{4}.

Flashcard 36: State the formula for a p-series.

Answer: n=11np\sum_{n=1}^{\infty} \frac{1}{n^p}. General form where pp determines convergence behavior.

Flashcard 37: What is the definition of a harmonic series?

Answer: The series n=11n\sum_{n=1}^{\infty} \frac{1}{n}. The classic divergent series with terms 1n\frac{1}{n}.

Flashcard 38: What is the fifth term of a harmonic series?

Answer: 15\frac{1}{5}. The fifth term in the harmonic series is 15\frac{1}{5}.

Flashcard 39: For which values of pp does n=11np\sum_{n=1}^{\infty} \frac{1}{n^p} diverge?

Answer: p1p \leq 1. P-series diverge when pp is at most 1.

Flashcard 40: State the formula for a p-series.

Answer: n=11np\sum_{n=1}^{\infty} \frac{1}{n^p}. General form where pp determines convergence behavior.

Flashcard 41: For which pp is the series n=11np\sum_{n=1}^{\infty} \frac{1}{n^p} divergent?

Answer: p1p \leq 1. P-series diverge when pp is at most 1.

Flashcard 42: State whether n=11n2.5\sum_{n=1}^{\infty} \frac{1}{n^{2.5}} converges.

Answer: Converges. Since p=2.5>1p = 2.5 > 1, this p-series converges.

Flashcard 43: Which series is divergent: n=11n\sum_{n=1}^{\infty} \frac{1}{n} or n=11n2\sum_{n=1}^{\infty} \frac{1}{n^2}?

Answer: n=11n\sum_{n=1}^{\infty} \frac{1}{n}. The harmonic series diverges while 1n2\sum \frac{1}{n^2} converges.

Flashcard 44: What condition makes a p-series diverge?

Answer: Diverges if p1p \leq 1. When p1p \leq 1, terms don't decrease fast enough.

Flashcard 45: Identify the convergence of n=11n2\sum_{n=1}^{\infty} \frac{1}{n^2}.

Answer: Converges. Since p=2>1p = 2 > 1, this p-series converges.

Flashcard 46: Is n=11n0.5\sum_{n=1}^{\infty} \frac{1}{n^{0.5}} convergent or divergent?

Answer: Divergent. Since p=0.51p = 0.5 \leq 1, this p-series diverges.

Flashcard 47: What is the first term of a harmonic series?

Answer:

  1. The harmonic series starts with 11=1\frac{1}{1} = 1.

Flashcard 48: What type of series is n=11n0.3\sum_{n=1}^{\infty} \frac{1}{n^{0.3}}?

Answer: p-series. Has form 1np\sum \frac{1}{n^p} with p=0.3p = 0.3.

Flashcard 49: Determine the convergence of n=11n4\sum_{n=1}^{\infty} \frac{1}{n^{4}}.

Answer: Converges. Since p=4>1p = 4 > 1, this p-series converges.

Flashcard 50: What is the third term of a harmonic series?

Answer: 13\frac{1}{3}. The third term in the harmonic series is 13\frac{1}{3}.

Flashcard 51: Does the series n=11n3.5\sum_{n=1}^{\infty} \frac{1}{n^{3.5}} converge?

Answer: Converges. Since p=3.5>1p = 3.5 > 1, this p-series converges.

Flashcard 52: State the convergence of n=11n0.8\sum_{n=1}^{\infty} \frac{1}{n^{0.8}}.

Answer: Diverges. Since p=0.8<1p = 0.8 < 1, this p-series diverges.

Flashcard 53: What is the second term of a harmonic series?

Answer: 12\frac{1}{2}. The second term in the harmonic series is 12\frac{1}{2}.

Flashcard 54: State whether n=11n2.5\sum_{n=1}^{\infty} \frac{1}{n^{2.5}} converges.

Answer: Converges. Since p=2.5>1p = 2.5 > 1, this p-series converges.

Flashcard 55: What is the nature of n=11n2.1\sum_{n=1}^{\infty} \frac{1}{n^{2.1}}?

Answer: Convergent. Since p=2.1>1p = 2.1 > 1, this p-series converges.

Flashcard 56: Identify if n=11n1/2\sum_{n=1}^{\infty} \frac{1}{n^{1/2}} converges or diverges.

Answer: Diverges. Since p=0.5<1p = 0.5 < 1, this p-series diverges.

Flashcard 57: What is the first term of a harmonic series?

Answer:

  1. The harmonic series starts with 11=1\frac{1}{1} = 1.

Flashcard 58: Does n=11n0.7\sum_{n=1}^{\infty} \frac{1}{n^{0.7}} converge or diverge?

Answer: Diverges. Since p=0.7<1p = 0.7 < 1, this p-series diverges.

Flashcard 59: What condition makes a p-series converge?

Answer: Converges if p>1p > 1. When p>1p > 1, the terms decrease fast enough for convergence.