Study Derivative Notation in AP Calculus BC with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
All flashcards Flashcard 1: Find the derivative of f ( x ) = x 3 f(x) = \sqrt{x^3} f ( x ) = x 3 . Answer: f ′ ( x ) = 3 2 x 1 / 2 f'(x) = \frac{3}{2}x^{1/2} f ′ ( x ) = 2 3 x 1/2 . Rewrite x 3 = x 3 / 2 \sqrt{x^3} = x^{3/2} x 3 = x 3/2 and use power rule.
Flashcard 2: How is the derivative of f ( x ) f(x) f ( x ) denoted using Newton's notation? Answer: f ˙ ( x ) \dot{f}(x) f ˙ ( x ) . Dot notation represents time derivative in physics.
Flashcard 3: Find the derivative of f ( x ) = ln ( sin x ) f(x) = \ln(\sin x) f ( x ) = ln ( sin x ) . Answer: f ′ ( x ) = cot x f'(x) = \cot x f ′ ( x ) = cot x . Chain rule with ln ( sin x ) \ln(\sin x) ln ( sin x ) .
Flashcard 4: Find the derivative of f ( x ) = 3 x 2 + 2 x f(x) = 3x^2 + 2x f ( x ) = 3 x 2 + 2 x . Answer: f ′ ( x ) = 6 x + 2 f'(x) = 6x + 2 f ′ ( x ) = 6 x + 2 . Apply power rule to each term separately.
Flashcard 5: Find the derivative of f ( x ) = 1 3 x 3 f(x) = \frac{1}{3}x^3 f ( x ) = 3 1 x 3 . Answer: f ′ ( x ) = x 2 f'(x) = x^2 f ′ ( x ) = x 2 . Constant factor 1 3 \frac{1}{3} 3 1 remains, apply power rule.
Flashcard 6: How is the derivative of f ( x ) f(x) f ( x ) at x = a x = a x = a denoted using prime notation? Answer: f ′ ( a ) f'(a) f ′ ( a ) . Prime notation denotes derivative at specific point.
Flashcard 7: What is the derivative notation using Leibniz's notation for y = f ( x ) y = f(x) y = f ( x ) ? Answer: d y d x \frac{dy}{dx} d x d y . Leibniz notation shows derivative of y y y with respect to x x x .
Flashcard 8: Find the derivative of f ( x ) = 2 sec x f(x) = 2\sec x f ( x ) = 2 sec x . Answer: f ′ ( x ) = 2 sec x tan x f'(x) = 2\sec x \tan x f ′ ( x ) = 2 sec x tan x . Constant multiple of secant derivative.
Flashcard 9: Find the derivative of f ( x ) = 3 x 2 + 2 x f(x) = 3x^2 + 2x f ( x ) = 3 x 2 + 2 x . Answer: f ′ ( x ) = 6 x + 2 f'(x) = 6x + 2 f ′ ( x ) = 6 x + 2 . Apply power rule to each term separately.
Flashcard 10: Find the derivative of f ( x ) = 5 e x − 4 f(x) = 5e^x - 4 f ( x ) = 5 e x − 4 . Answer: f ′ ( x ) = 5 e x f'(x) = 5e^x f ′ ( x ) = 5 e x . Constant multiple rule with exponential derivative.
Flashcard 11: Find the derivative of f ( x ) = x cos x f(x) = x \cos x f ( x ) = x cos x . Answer: f ′ ( x ) = cos x − x sin x f'(x) = \cos x - x \sin x f ′ ( x ) = cos x − x sin x . Product rule with u = x u = x u = x and v = cos x v = \cos x v = cos x .
Flashcard 12: State the formula for the derivative of f ( x ) = x n f(x) = x^n f ( x ) = x n . Answer: f ′ ( x ) = n x n − 1 f'(x) = nx^{n-1} f ′ ( x ) = n x n − 1 . Power rule: bring down exponent, reduce power by 1.
Flashcard 13: State the formula for the derivative of f ( x ) = x n f(x) = x^n f ( x ) = x n . Answer: f ′ ( x ) = n x n − 1 f'(x) = nx^{n-1} f ′ ( x ) = n x n − 1 . Power rule: bring down exponent, reduce power by 1.
Flashcard 14: What is the derivative of f ( x ) = cot x f(x) = \cot x f ( x ) = cot x ? Answer: − csc 2 x -\csc^2 x − csc 2 x . Derivative of cotangent is negative cosecant squared.
Flashcard 15: Find the derivative of f ( x ) = 8 x − 1 / 2 f(x) = 8x^{-1/2} f ( x ) = 8 x − 1/2 . Answer: f ′ ( x ) = − 4 x − 3 / 2 f'(x) = -4x^{-3/2} f ′ ( x ) = − 4 x − 3/2 . Constant 8 times power rule on x − 1 / 2 x^{-1/2} x − 1/2 .
Flashcard 16: How is the derivative of f ( x ) f(x) f ( x ) at x = a x = a x = a denoted using prime notation? Answer: f ′ ( a ) f'(a) f ′ ( a ) . Prime notation denotes derivative at specific point.
Flashcard 17: Find the derivative of f ( x ) = x 2 sin x f(x) = x^2 \sin x f ( x ) = x 2 sin x . Answer: 2 x sin x + x 2 cos x 2x \sin x + x^2 \cos x 2 x sin x + x 2 cos x . Apply product rule: ( u v ) ′ = u ′ v + u v ′ (uv)' = u'v + uv' ( uv ) ′ = u ′ v + u v ′ .
Flashcard 18: Find the derivative of f ( x ) = x 4 − 3 x 2 + x f(x) = x^4 - 3x^2 + x f ( x ) = x 4 − 3 x 2 + x . Answer: f ′ ( x ) = 4 x 3 − 6 x + 1 f'(x) = 4x^3 - 6x + 1 f ′ ( x ) = 4 x 3 − 6 x + 1 . Apply power rule to each term.
Flashcard 19: Find the derivative of f ( x ) = x 4 − 3 x 2 + x f(x) = x^4 - 3x^2 + x f ( x ) = x 4 − 3 x 2 + x . Answer: f ′ ( x ) = 4 x 3 − 6 x + 1 f'(x) = 4x^3 - 6x + 1 f ′ ( x ) = 4 x 3 − 6 x + 1 . Apply power rule to each term.
Flashcard 20: Find the derivative of f ( x ) = x 3 − 5 x + 4 f(x) = x^3 - 5x + 4 f ( x ) = x 3 − 5 x + 4 . Answer: f ′ ( x ) = 3 x 2 − 5 f'(x) = 3x^2 - 5 f ′ ( x ) = 3 x 2 − 5 . Derivative of constant is 0, apply power rule to other terms.
Flashcard 21: Find the derivative of f ( x ) = x 3 − 5 x + 4 f(x) = x^3 - 5x + 4 f ( x ) = x 3 − 5 x + 4 . Answer: f ′ ( x ) = 3 x 2 − 5 f'(x) = 3x^2 - 5 f ′ ( x ) = 3 x 2 − 5 . Derivative of constant is 0, apply power rule to other terms.
Flashcard 22: What does the derivative represent geometrically? Answer: Slope of the tangent line. Derivative gives instantaneous rate of change.
Flashcard 23: What is the derivative of f ( x ) = cot x f(x) = \cot x f ( x ) = cot x ? Answer: − csc 2 x - \csc^2 x − csc 2 x . Derivative of cotangent is negative cosecant squared.
Flashcard 24: Find the derivative of f ( x ) = 5 e x − 4 f(x) = 5e^x - 4 f ( x ) = 5 e x − 4 . Answer: f ′ ( x ) = 5 e x f'(x) = 5e^x f ′ ( x ) = 5 e x . Constant multiple rule with exponential derivative.
Flashcard 25: What is the derivative of f ( x ) = a x f(x) = a^x f ( x ) = a x where a > 0 a > 0 a > 0 ? Answer: a x ln a a^x \ln a a x ln a . Exponential with base a a a requires ln a \ln a ln a factor.
Flashcard 26: What is the derivative of a constant function f ( x ) = c f(x) = c f ( x ) = c ? Answer:
Constants have zero rate of change.
Flashcard 27: Find the derivative of f ( x ) = 7 x 5 f(x) = 7x^5 f ( x ) = 7 x 5 . Answer: f ′ ( x ) = 35 x 4 f'(x) = 35x^4 f ′ ( x ) = 35 x 4 . Constant multiple of power rule.
Flashcard 28: What is the derivative of f ( x ) = e x f(x) = e^x f ( x ) = e x ? Answer: e x e^x e x . Exponential function e x e^x e x is its own derivative.
Flashcard 29: Find the derivative of f ( x ) = 1 x f(x) = \frac{1}{x} f ( x ) = x 1 Answer: f ′ ( x ) = − 1 x 2 f'(x) = -\frac{1}{x^2} f ′ ( x ) = − x 2 1 . Rewrite as x − 1 x^{-1} x − 1 and use power rule.
Flashcard 30: Find the derivative of f ( x ) = ln ( sin x ) f(x) = \ln(\sin x) f ( x ) = ln ( sin x ) . Answer: f ′ ( x ) = cot x f'(x) = \cot x f ′ ( x ) = cot x . Chain rule with ln ( sin x ) \ln(\sin x) ln ( sin x ) .
Flashcard 31: Find the derivative of f ( x ) = 1 2 x − 2 f(x) = \frac{1}{2}x^{-2} f ( x ) = 2 1 x − 2 . Answer: f ′ ( x ) = − x − 3 f'(x) = -x^{-3} f ′ ( x ) = − x − 3 . Constant 1 2 \frac{1}{2} 2 1 times power rule on x − 2 x^{-2} x − 2 .
Flashcard 32: Find the derivative of f ( x ) = x 2 + 1 x f(x) = \frac{x^2 + 1}{x} f ( x ) = x x 2 + 1 . Answer: f ′ ( x ) = x 2 − 1 x 2 f'(x) = \frac{x^2 - 1}{x^2} f ′ ( x ) = x 2 x 2 − 1 . Rewrite as x + x − 1 x + x^{-1} x + x − 1 and differentiate.
Flashcard 33: How is the derivative of f ( x ) f(x) f ( x ) denoted using Newton's notation? Answer: d o t f ( x ) \\dot{f}(x) d o t f ( x ) . Dot notation represents time derivative in physics.
Flashcard 34: Find the derivative of f ( x ) = x f(x) = \sqrt{x} f ( x ) = x . Answer: f ′ ( x ) = 1 2 x f'(x) = \frac{1}{2\sqrt{x}} f ′ ( x ) = 2 x 1 . Rewrite as x 1 / 2 x^{1/2} x 1/2 and apply power rule.
Flashcard 35: What is the derivative of f ( x ) = sin x f(x) = \sin x f ( x ) = sin x ? Answer: cos x \cos x cos x . Derivative of sine is cosine.
Flashcard 36: Find the derivative of f ( x ) = ln ( x 2 + 1 ) f(x) = \ln(x^2 + 1) f ( x ) = ln ( x 2 + 1 ) . Answer: 2 x x 2 + 1 \frac{2x}{x^2 + 1} x 2 + 1 2 x . Use chain rule with ln \ln ln and x 2 + 1 x^2 + 1 x 2 + 1 .
Flashcard 37: Find the derivative of f ( x ) = 1 x 3 f(x) = \frac{1}{x^3} f ( x ) = x 3 1 . Answer: f ′ ( x ) = − 3 x 4 f'(x) = -\frac{3}{x^4} f ′ ( x ) = − x 4 3 . Rewrite as x − 3 x^{-3} x − 3 and apply power rule.
Flashcard 38: Find the derivative of f ( x ) = 2 sec x f(x) = 2\sec x f ( x ) = 2 sec x . Answer: f ′ ( x ) = 2 sec x tan x f'(x) = 2\sec x \tan x f ′ ( x ) = 2 sec x tan x . Constant multiple of secant derivative.
Flashcard 39: What is the derivative of f ( x ) = cos x f(x) = \cos x f ( x ) = cos x ? Answer: − sin x -\sin x − sin x . Derivative of cosine is negative sine.
Flashcard 40: Find the derivative of f ( x ) = 7 x 5 f(x) = 7x^5 f ( x ) = 7 x 5 . Answer: f ′ ( x ) = 35 x 4 f'(x) = 35x^4 f ′ ( x ) = 35 x 4 . Constant multiple of power rule.
Flashcard 41: Find the derivative of f ( x ) = x cos x f(x) = x \cos x f ( x ) = x cos x . Answer: f ′ ( x ) = cos x − x sin x f'(x) = \cos x - x \sin x f ′ ( x ) = cos x − x sin x . Product rule with u = x u = x u = x and v = cos x v = \cos x v = cos x .
Flashcard 42: What is the derivative of f ( x ) = csc x f(x) = \csc x f ( x ) = csc x ? Answer: − csc x cot x - \csc x \cot x − csc x cot x . Derivative is negative product of cosecant and cotangent.
Flashcard 43: Find the derivative of f ( x ) = ln ( x 2 + 1 ) f(x) = \ln(x^2 + 1) f ( x ) = ln ( x 2 + 1 ) . Answer: 2 x x 2 + 1 \frac{2x}{x^2 + 1} x 2 + 1 2 x . Use chain rule with ln \ln ln and x 2 + 1 x^2 + 1 x 2 + 1 .
Flashcard 44: Find the derivative of f ( x ) = 1 x f(x) = \frac{1}{x} f ( x ) = x 1 . Answer: f ′ ( x ) = − 1 x 2 f'(x) = -\frac{1}{x^2} f ′ ( x ) = − x 2 1 . Rewrite as x − 1 x^{-1} x − 1 and use power rule.
Flashcard 45: Find the derivative of f ( x ) = x f(x) = \sqrt{x} f ( x ) = x . Answer: f ′ ( x ) = 1 2 x f'(x) = \frac{1}{2\sqrt{x}} f ′ ( x ) = 2 x 1 . Rewrite as x 1 / 2 x^{1/2} x 1/2 and apply power rule.
Flashcard 46: What is the derivative of f ( x ) = ln x f(x) = \ln x f ( x ) = ln x ? Answer: 1 x \frac{1}{x} x 1 . Natural log derivative is reciprocal function.
Flashcard 47: Find the derivative of f ( x ) = x 2 + 1 x f(x) = \frac{x^2 + 1}{x} f ( x ) = x x 2 + 1 . Answer: f ′ ( x ) = x 2 − 1 x 2 f'(x) = \frac{x^2 - 1}{x^2} f ′ ( x ) = x 2 x 2 − 1 . Rewrite as x + x − 1 x + x^{-1} x + x − 1 and differentiate.
Flashcard 48: Find the derivative of f ( x ) = sin 2 x f(x) = \sin^2 x f ( x ) = sin 2 x . Answer: f ′ ( x ) = 2 sin x cos x f'(x) = 2\sin x \cos x f ′ ( x ) = 2 sin x cos x . Use chain rule with sin 2 x = ( sin x ) 2 \sin^2 x = (\sin x)^2 sin 2 x = ( sin x ) 2 .
Flashcard 49: What is the derivative of f ( x ) = sec x f(x) = \sec x f ( x ) = sec x ? Answer: sec x tan x \sec x \tan x sec x tan x . Derivative involves product of secant and tangent.
Flashcard 50: What is the limit definition of the derivative of f ( x ) f(x) f ( x ) at x = a x = a x = a ? Answer: f ′ ( a ) = lim h → 0 f ( a + h ) − f ( a ) h f'(a) = \lim_{{h \to 0}} \frac{f(a+h) - f(a)}{h} f ′ ( a ) = lim h → 0 h f ( a + h ) − f ( a ) . Limit of difference quotient as h h h approaches 0.
Flashcard 51: What is the derivative of f ( x ) = cos x f(x) = \cos x f ( x ) = cos x ? Answer: − sin x -\sin x − sin x . Derivative of cosine is negative sine.
Flashcard 52: Find the derivative of f ( x ) = 1 x 3 f(x) = \frac{1}{x^3} f ( x ) = x 3 1 . Answer: f ′ ( x ) = − 3 x 4 f'(x) = -\frac{3}{x^4} f ′ ( x ) = − x 4 3 . Rewrite as x − 3 x^{-3} x − 3 and apply power rule.
Flashcard 53: What is the derivative of f ( x ) = csc x f(x) = \csc x f ( x ) = csc x ? Answer: − csc x cot x -\csc x \cot x − csc x cot x . Derivative is negative product of cosecant and cotangent.
Flashcard 54: What is the derivative of f ( x ) = tan x f(x) = \tan x f ( x ) = tan x ? Answer: sec 2 x \sec^2 x sec 2 x . Derivative of tangent is secant squared.
Flashcard 55: What is the derivative of f ( x ) = sec x f(x) = \sec x f ( x ) = sec x ? Answer: sec x tan x \sec x \tan x sec x tan x . Derivative involves product of secant and tangent.
Flashcard 56: Find the derivative of f ( x ) = tan ( x 2 ) f(x) = \tan(x^2) f ( x ) = tan ( x 2 ) . Answer: f ′ ( x ) = 2 x sec 2 ( x 2 ) f'(x) = 2x \sec^2(x^2) f ′ ( x ) = 2 x sec 2 ( x 2 ) . Chain rule: outer derivative times inner derivative.
Flashcard 57: What is the derivative of f ( x ) = ln x f(x) = \ln x f ( x ) = ln x ? Answer: 1 x \frac{1}{x} x 1 . Natural log derivative is reciprocal function.
Flashcard 58: Find the derivative of f ( x ) = 1 3 x 3 f(x) = \frac{1}{3}x^3 f ( x ) = 3 1 x 3 . Answer: f ′ ( x ) = x 2 f'(x) = x^2 f ′ ( x ) = x 2 . Constant factor 1 3 \frac{1}{3} 3 1 remains, apply power rule.
Flashcard 59: What is the derivative of f ( x ) = sin x f(x) = \sin x f ( x ) = sin x ? Answer: cos x \cos x cos x . Derivative of sine is cosine.
Flashcard 60: What is the limit definition of the derivative of f ( x ) f(x) f ( x ) at x = a x = a x = a ? Answer: f ′ ( a ) = lim h → 0 f ( a + h ) − f ( a ) h f'(a) = \lim_{{h \to 0}} \frac{f(a+h) - f(a)}{h} f ′ ( a ) = lim h → 0 h f ( a + h ) − f ( a ) . Limit of difference quotient as h h h approaches 0.
Flashcard 61: Find the derivative of f ( x ) = x 3 f(x) = \sqrt{x^3} f ( x ) = x 3 . Answer: f ′ ( x ) = 3 2 x 1 / 2 f'(x) = \frac{3}{2}x^{1/2} f ′ ( x ) = 2 3 x 1/2 . Rewrite x 3 = x 3 / 2 \sqrt{x^3} = x^{3/2} x 3 = x 3/2 and use power rule.
Flashcard 62: Find the derivative of f ( x ) = sin 2 x f(x) = \sin^2 x f ( x ) = sin 2 x . Answer: f ′ ( x ) = 2 sin x cos x f'(x) = 2\sin x \cos x f ′ ( x ) = 2 sin x cos x . Use chain rule with sin 2 x = ( sin x ) 2 \sin^2 x = (\sin x)^2 sin 2 x = ( sin x ) 2 .
Flashcard 63: Find the derivative of f ( x ) = tan ( x 2 ) f(x) = \tan(x^2) f ( x ) = tan ( x 2 ) . Answer: f ′ ( x ) = 2 x sec 2 ( x 2 ) f'(x) = 2x \sec^2(x^2) f ′ ( x ) = 2 x sec 2 ( x 2 ) . Chain rule: outer derivative times inner derivative.
Flashcard 64: What is the derivative of f ( x ) = a x f(x) = a^x f ( x ) = a x where a > 0 a > 0 a > 0 ? Answer: a x ln a a^x \ln a a x ln a . Exponential with base a a a requires ln a \ln a ln a factor.
Flashcard 65: Find the derivative of f ( x ) = x 2 sin x f(x) = x^2 \sin x f ( x ) = x 2 sin x . Answer: 2 x sin x + x 2 cos x 2x \sin x + x^2 \cos x 2 x sin x + x 2 cos x . Apply product rule: ( u v ) ′ = u ′ v + u v ′ (uv)' = u'v + uv' ( uv ) ′ = u ′ v + u v ′ .
Flashcard 66: What is the derivative of f ( x ) = tan x f(x) = \tan x f ( x ) = tan x ? Answer: sec 2 x \sec^2 x sec 2 x . Derivative of tangent is secant squared.
Flashcard 67: Find the derivative of f ( x ) = 8 x − 1 / 2 f(x) = 8x^{-1/2} f ( x ) = 8 x − 1/2 . Answer: f ′ ( x ) = − 4 x − 3 / 2 f'(x) = -4x^{-3/2} f ′ ( x ) = − 4 x − 3/2 . Constant 8 times power rule on x − 1 / 2 x^{-1/2} x − 1/2 .
Flashcard 68: What is the derivative notation using Leibniz's notation for y = f ( x ) y = f(x) y = f ( x ) ? Answer: d y d x \frac{dy}{dx} d x d y . Leibniz notation shows derivative of y y y with respect to x x x .