All flashcards
Flashcard 1: Calculate the derivative: f(x)=5x4.
Answer: f′(x)=20x3. Power rule: 4×5x4−1=20x3.
Flashcard 2: State the method to solve optimization problems with constraints.
Answer: Use Lagrange multipliers. Technique for handling equality constraints.
Flashcard 3: What is the derivative of f(x)=e2x?
Answer: f′(x)=2e2x. Chain rule applied to exponential with coefficient.
Flashcard 4: Identify the constraint in maximizing the volume of a box.
Answer: Surface area or material limits. Material availability restricts the design space.
Flashcard 5: Calculate the derivative: f(x)=tan(x).
Answer: f′(x)=sec2(x). Standard derivative of tangent function.
Flashcard 6: Find the derivative of g(x)=x1.
Answer: g′(x)=−x21. Rewrite as x−1 and apply power rule.
Flashcard 7: What step follows finding the critical points in optimization?
Answer: Evaluate the objective function at critical points. Determines which critical point gives optimal value.
Flashcard 8: Identify the formula for the derivative of f(x)=x2+3x.
Answer: f′(x)=2x+3. Power rule applied: bring down exponent, reduce by 1.
Flashcard 9: State the condition for a relative maximum using f′′(x).
Answer: f′′(x)<0 at critical point. Negative second derivative indicates downward concavity.
Flashcard 10: Determine the derivative: f(x)=x3−3x2+2.
Answer: f′(x)=3x2−6x. Power rule applied to each term separately.
Flashcard 11: Determine the derivative: f(x)=3x−2.
Answer: f′(x)=−6x−3. Power rule: 3×(−2)x−3=−6x−3.
Flashcard 12: State the condition for a relative minimum using f′′(x).
Answer: f′′(x)>0 at critical point. Positive second derivative indicates upward concavity.
Flashcard 13: Identify the derivative of f(x)=x21.
Answer: f′(x)=21x−21. Power rule with fractional exponent: 21x−1/2.
Flashcard 14: State the critical points condition for f′(x)=0.
Answer: Critical points occur where f′(x)=0 or is undefined. These are potential locations for extrema.
Flashcard 15: What does f′(x)=0 imply about f(x)?
Answer: Possible extremum or inflection point. Zero slope indicates potential maximum or minimum.
Flashcard 16: Calculate the derivative: f(x)=ex.
Answer: f′(x)=ex. Exponential function is its own derivative.
Flashcard 17: What is the derivative of f(x)=ln(x)?
Answer: f′(x)=x1. Standard derivative of natural logarithm function.
Flashcard 18: Find the derivative of f(x)=arcsin(x).
Answer: f′(x)=√(1−x2)1. Standard derivative of inverse sine function.
Flashcard 19: What is the derivative of f(x)=loga(x)?
Answer: f′(x)=xln(a)1. General formula for logarithm base a derivative.
Flashcard 20: State the chain rule for derivatives.
Answer: If y=g(f(x)), then dy/dx=g′(f(x))f′(x). Rule for differentiating composite functions.
Flashcard 21: What is the condition for an inflection point?
Answer: f′′(x)=0 and f′′(x) changes sign. Point where concavity changes direction.
Flashcard 22: Calculate the derivative: f(x)=cos(x).
Answer: f′(x)=−sin(x). Derivative of cosine is negative sine.
Flashcard 23: Find the derivative of f(x)=2x2.
Answer: f′(x)=x. Coefficient 21 remains, power rule on x2.
Flashcard 24: What is the purpose of Lagrange multipliers?
Answer: To find extrema of functions subject to constraints. Method for optimization with equality constraints.
Flashcard 25: Find the critical points of h(x)=x2−4x+4.
Answer: x=2. Set h′(x)=2x−4=0, solve for x.
Flashcard 26: What is the derivative of a constant function f(x)=c?
Answer: f′(x)=0. Constants have zero rate of change.
Flashcard 27: What is the derivative of f(x)=sin(x)?
Answer: f′(x)=cos(x). Standard trigonometric derivative rule.
Flashcard 28: Find the critical points of h(x)=x2−4x+4.
Answer: x=2. Set h′(x)=2x−4=0, solve for x.
Flashcard 29: Calculate the derivative: f(x)=5x4.
Answer: f′(x)=20x3. Power rule: 4×5x4−1=20x3.
Flashcard 30: What is the derivative of f(x)=sin(x)?
Answer: f′(x)=cos(x). Standard trigonometric derivative rule.