All flashcards
Flashcard 1: Calculate L2 for f(x)=x3 on [1,3] with n=2.
Answer: L2=9. △x=1; sum f(1)+f(2)=1+8=9.
Flashcard 2: State the formula for the midpoint Riemann sum.
Answer: Mn=sum of f(mi)×width, using midpoints. Each rectangle height uses function value at interval's center.
Flashcard 3: What is the effect of increasing n on Riemann sums?
Answer: Increases accuracy of the approximation. More rectangles provide finer approximation of curved area.
Flashcard 4: Calculate L4 for f(x)=x on [0,4] with n=4.
Answer: L4=6. △x=1; sum f(0)+f(1)+f(2)+f(3)=0+1+2+3=6.
Flashcard 5: State the formula for the left Riemann sum.
Answer: Ln=sum of f(xi∗)×width, using left endpoints. Each rectangle height uses function value at left edge of interval.
Flashcard 6: What is the role of n in a Riemann sum?
Answer: Number of subintervals for the partition. Controls precision by determining how many subintervals are used.
Flashcard 7: What is the trapezoidal rule?
Answer: An approximation method using trapezoids to estimate area. Connects consecutive points with straight lines to form trapezoids.
Flashcard 8: Identify the type of Riemann sum that tends to underestimate.
Answer: Left Riemann sum (if f(x) is increasing). Left endpoints sample lower function values on increasing functions.
Flashcard 9: Calculate M4 for f(x)=x on [0,4] with n=4.
Answer: M4=8. △x=1; sum f(0.5)+f(1.5)+f(2.5)+f(3.5)=0.5+1.5+2.5+3.5=8.
Flashcard 10: Which Riemann sum uses midpoints of intervals?
Answer: Midpoint Riemann sum. Uses center point of each subinterval for height calculation.
Flashcard 11: Identify the partition width for n=4 on [1,5].
Answer: △x=1. (5−1)/4=1 for the given interval and partitions.
Flashcard 12: What is the effect of decreasing n on approximation?
Answer: Decreases accuracy of the approximation. Fewer rectangles provide coarser approximation of area.
Flashcard 13: How is a Riemann sum related to the definite integral?
Answer: It approximates the integral as n→infinity. Riemann sum approaches integral value as partition size approaches zero.
Flashcard 14: State the formula for the right Riemann sum.
Answer: Rn=sum of f(xi∗)×width, using right endpoints. Each rectangle height uses function value at right edge of interval.
Flashcard 15: Identify the midpoint for the interval [3,5].
Answer: m=4. Average of interval endpoints: (3+5)/2=4.
Flashcard 16: How does a left Riemann sum differ from a right Riemann sum?
Answer: Uses left vs. right endpoints of subintervals. Different sampling points within each subinterval affect approximation.
Flashcard 17: What is the general form of a Riemann sum?
Answer: sum of f(xi∗)×△x. Standard notation for all Riemann sum variations.
Flashcard 18: What is the primary use of Riemann sums?
Answer: To approximate the integral of a function. Estimates area under curves when exact integration is difficult.
Flashcard 19: What is necessary for a Riemann sum to equal the exact area?
Answer: n→infinity and f(x) continuous. Infinite partitions with continuous functions guarantee convergence to exact area.
Flashcard 20: Calculate M2 for f(x)=x2 on [0,2] with n=2.
Answer: M2=2.5. △x=1; midpoints 0.5,1.5 give (0.5)2+(1.5)2=2.5.
Flashcard 21: What does △x represent in Riemann sums?
Answer: Width of each subinterval. Size of each rectangular subdivision in the partition.
Flashcard 22: What is the midpoint of the interval [2,6]?
Answer: m=4. Average of interval endpoints: (2+6)/2=4.
Flashcard 23: Identify the type of Riemann sum that tends to overestimate.
Answer: Right Riemann sum (if f(x) is increasing). Right endpoints sample higher function values on increasing functions.
Flashcard 24: How does the trapezoidal rule improve accuracy?
Answer: Uses trapezoids instead of rectangles. Trapezoids better approximate curved regions than rectangles.
Flashcard 25: Find △x for n=4 on [0,8].
Answer: △x=2. (8−0)/4=2 for the given interval and partitions.
Flashcard 26: Calculate △x for n=5 on [2,12].
Answer: △x=2. (12−2)/5=2 for the given interval and partitions.
Flashcard 27: How is the partition width △x calculated?
Answer: △x=nb−a, where [a,b] is the interval. Interval length divided by number of subintervals.
Flashcard 28: State the formula for the trapezoidal rule.
Answer: Tn=2nb−a[f(x0)+2sum of f(xi)+f(xn)]. Averages left and right endpoints, summing trapezoid areas.
Flashcard 29: What is a Riemann sum?
Answer: A method for approximating the total area under a curve. Divides interval into rectangles to estimate area under curve.
Flashcard 30: Calculate R4 for f(x)=x on [0,4] with n=4.
Answer: R4=10. △x=1; sum f(1)+f(2)+f(3)+f(4)=1+2+3+4=10.