Geometry - How to find the height of a right triangle

Prblem 8 basic geometry

Find the missing length in triangle ABC.

$4\ in$

$3\ in$

$5/4\ in$

$5\ in$

$2\ in$

Explanation

To find the missing length, use the Pythagorean Theorem.

Where "a" and "b" are the legs, and "c" is the hypotenuse.

a=3 inches

b=???

c= 5 inches

Plug in the values

Now, get the variable by itself.

Take the square root of both sides.

$\sqrt{b^2}=\sqrt{16}$

If the area of a right triangle is , and the base of the triangle is , what is the height of the triangle?

Explanation

Recall how to find the area of a right triangle:

$\text{Area}=\frac{1}{2}(\text{base}\times\text{height})$

Now, we are going to manipulate the equation to solve for height.

$2(\text{Area})=\text{base}\times\text{height}$

$\text{Height}=\frac{2(\text{Area})}{\text{base}}$

Now, plug in the information given by the question about the values of the area and base of the triangle to find the height.

$\text{Height}=\frac{2(3)}{3}=\frac{6}{3}=2$

If the area of a right triangle is , and the base of the triangle is , what is the height of the triangle?

Explanation

Recall how to find the area of a right triangle:

$\text{Area}=\frac{1}{2}(\text{base}\times\text{height})$

Now, we are going to manipulate the equation to solve for height.

$2(\text{Area})=\text{base}\times\text{height}$

$\text{Height}=\frac{2(\text{Area})}{\text{base}}$

Now, plug in the information given by the question about the values of the area and base of the triangle to find the height.

$\text{Height}=\frac{2(60)}{40}=\frac{120}{40}=3$

If the area of a right triangle is , and the base of the triangle is , what is the height of the triangle?

Explanation

Recall how to find the area of a right triangle:

$\text{Area}=\frac{1}{2}(\text{base}\times\text{height})$

Now, we are going to manipulate the equation to solve for height.

$2(\text{Area})=\text{base}\times\text{height}$

$\text{Height}=\frac{2(\text{Area})}{\text{base}}$

Now, plug in the information given by the question about the values of the area and base of the triangle to find the height.

$\text{Height}=\frac{2(20)}{1}=\frac{40}{1}=40$

If the area of a right triangle is , and the base of the triangle is , what is the height of the triangle?

Explanation

Recall how to find the area of a right triangle:

$\text{Area}=\frac{1}{2}(\text{base}\times\text{height})$

Now, we are going to manipulate the equation to solve for height.

$2(\text{Area})=\text{base}\times\text{height}$

$\text{Height}=\frac{2(\text{Area})}{\text{base}}$

Now, plug in the information given by the question about the values of the area and base of the triangle to find the height.

$\text{Height}=\frac{2(18)}{2}=\frac{36}{2}=18$

Screen_shot_2015-02-27_at_6.56.15_pm

If c is not the base of the triangle, which of the following is the height?

None of the other answers

Explanation

If is not the base, that makes either or the base. If either or is the base, the right angle is on the bottom, so or respectively will be perpendicular. The height of a triangle is the distance from the base to the highest point, and in a right triangle that will be found by the side adjoining the base at a right angle. So if the base is , then and vise versa.

If the area of a right triangle is , and the base of the triangle is , what is the height of the triangle?

Explanation

Recall how to find the area of a right triangle:

$\text{Area}=\frac{1}{2}(\text{base}\times\text{height})$

Now, we are going to manipulate the equation to solve for height.

$2(\text{Area})=\text{base}\times\text{height}$

$\text{Height}=\frac{2(\text{Area})}{\text{base}}$

Now, plug in the information given by the question about the values of the area and base of the triangle to find the height.

$\text{Height}=\frac{2(15)}{10}=\frac{30}{10}=3$

The area of a right triangle is 28. If one leg has a length of 7, what is the length of the other leg?

Explanation

We begin with the formula for the area of a triangle.

$A=\frac{1}{2}bh$

We further realize that the two legs of the triangle are the base and height; therefore, substituting what we know we get

$28=\frac{1}{2}(7)h$

$28=\frac{7}{2}h$

We can then solve by simply dividing.

We have found our height and thus the second leg of our triangle.

If the area of a right triangle is , and the base of the triangle is , what is the height of the triangle?

Explanation

Recall how to find the area of a right triangle:

$\text{Area}=\frac{1}{2}(\text{base}\times\text{height})$

Now, we are going to manipulate the equation to solve for height.

$2(\text{Area})=\text{base}\times\text{height}$

$\text{Height}=\frac{2(\text{Area})}{\text{base}}$

Now, plug in the information given by the question about the values of the area and base of the triangle to find the height.

$\text{Height}=\frac{2(10)}{5}=\frac{20}{5}=4$

If the area of a right triangle is , and the base of the right triangle is , what is the height of the right triangle?

Explanation

Recall how to find the area of a right triangle:

$\text{Area}=\frac{1}{2}(\text{base}\times\text{height})$

Now, we are going to manipulate the equation to solve for height.

$2(\text{Area})=\text{base}\times\text{height}$

$\text{Height}=\frac{2(\text{Area})}{\text{base}}$

Now, plug in the information given by the question about the values of the area and base of the triangle to find the height.

$\text{Height}=\frac{2(16)}{4}=\frac{32}{4}=8$

How to find the height of a right triangle

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