Trigonometric Ratios from Right Triangle Similarity

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Geometry › Trigonometric Ratios from Right Triangle Similarity

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1

Two right triangles $\triangle ABC$ and $\triangle A'B'C'$ are shown with right angles at $C$ and $C'$ and the same acute angle $\theta$ at $A$ and $A'$. Which relationship depends only on the angle $\theta$ (and not on the triangle size)?

$\dfrac{AB}{A'B'}=\dfrac{AC}{A'C'}$

$AB-A'B'=AC-A'C'$

$AB=2\cdot A'B'$

$\dfrac{BC}{AB}=\dfrac{B'C'}{A'B'}$

Explanation

This problem explores which relationships remain invariant under similarity for right triangles. When right triangles share the same acute angle θ, they are similar because they have two equal angles (θ and 90°), making all angles equal. For triangles ABC and A'B'C' with right angles at C and C' and angle θ at A and A', the ratio BC/AB equals B'C'/A'B' because both represent sin(θ). This ratio depends only on angle θ, not on triangle size, due to the proportionality of corresponding sides in similar triangles. Option A shows general proportionality but doesn't isolate an angle-dependent ratio, while options C and D involve specific size relationships that change with scaling. The key insight is that ratios within each triangle (like BC/AB) are angle-dependent, while ratios between triangles reflect size differences.

2

A right triangle $\triangle LMN$ is drawn with the right angle marked at $M$. The hypotenuse is explicitly identified as $\overline{LN}$. The acute angles at $L$ and $N$ are labeled $\alpha$ and $\beta$, respectively. No side lengths are given, and the diagram is not drawn to scale. Which ratio represents $\sin(\beta)$?

Question graphic

$\dfrac{LM}{LN}$

$\dfrac{MN}{LN}$

$\dfrac{LN}{MN}$

$\dfrac{LM}{MN}$

Explanation

The skill involves defining trigonometric ratios using the similarity of right triangles. Right triangles that share an acute angle $\theta$ are similar because they both have angles $\theta$, $90^\circ$, and $90^\circ - \theta$, satisfying the AA similarity criterion. In triangle LMN with right angle at M and $\beta$ at N, the side opposite $\beta$ is LM, the adjacent side is MN, and the hypotenuse is LN. The sine of $\beta$ is defined as the ratio of the opposite side to the hypotenuse, which is $\dfrac{\text{LM}}{\text{LN}}$. This ratio depends only on the measure of $\beta$, as similar right triangles have corresponding sides in proportion, making the ratio constant for a given $\beta$. A common misconception is to choose $\dfrac{\text{MN}}{\text{LN}}$ for sine, which uses adjacent instead of opposite and actually defines cosine. To apply this in any right triangle, first label the sides as opposite, adjacent, and hypotenuse relative to the given angle.

3

A right triangle $\triangle RST$ is shown with the right angle marked at $S$. The hypotenuse is explicitly identified as $\overline{RT}$. The acute angle at $T$ is labeled $\theta$. No numeric lengths are given, and the diagram is not drawn to scale. Which ratio represents $\sin(\theta)$?

Question graphic

$\dfrac{RS}{ST}$

$\dfrac{RT}{ST}$

$\dfrac{ST}{RT}$

$\dfrac{RS}{RT}$

Explanation

The skill involves defining trigonometric ratios using the similarity of right triangles. Right triangles that share an acute angle $\theta$ are similar because they both have angles $\theta$, $90^\circ$, and $90^\circ - \theta$, satisfying the AA similarity criterion. In triangle RST with right angle at S and $\theta$ at T, the side opposite $\theta$ is RS, the adjacent side is ST, and the hypotenuse is RT. The sine of $\theta$ is defined as the ratio of the opposite side to the hypotenuse, which is $\frac{RS}{RT}$. This ratio depends only on the measure of $\theta$, as similar right triangles have corresponding sides in proportion, making the ratio constant for a given $\theta$. A common misconception is to choose $\frac{ST}{RT}$ for sine, which uses adjacent instead of opposite and actually defines cosine. To apply this in any right triangle, first label the sides as opposite, adjacent, and hypotenuse relative to the given angle.

4

In right triangle $\triangle ABC$ (right angle marked at $C$), the acute angles at $A$ and $B$ are labeled $\alpha$ and $\beta$. The hypotenuse is explicitly identified as $\overline{AB}$. No side lengths are given, and the diagram is not drawn to scale. Which statement correctly defines a trigonometric ratio?

Question graphic

$\cos(\alpha)=\dfrac{AC}{AB}$

$\sin(\alpha)=\dfrac{AC}{BC}$

$\sin(\alpha)=\dfrac{AB}{BC}$

$\tan(\alpha)=\dfrac{AB}{AC}$

Explanation

The skill involves defining trigonometric ratios using the similarity of right triangles. Right triangles that share an acute angle θ are similar because they both have angles θ, 90°, and 90°-θ, satisfying the AA similarity criterion. In triangle ABC with right angle at C and α at A, the side opposite α is BC, the adjacent side is AC, and the hypotenuse is AB. The cosine of α is defined as the ratio of the adjacent side to the hypotenuse, which is AC/AB. This ratio depends only on the measure of α, as similar right triangles have corresponding sides in proportion, making the ratio constant for a given α. A common misconception is to choose AC/BC for sine of α, which mixes adjacent and opposite sides and actually represents cotangent. To apply this in any right triangle, first label the sides as opposite, adjacent, and hypotenuse relative to the given angle.

5

A right triangle $\triangle DEF$ is drawn in the plane with the right angle marked at $E$. The hypotenuse is explicitly identified as $\overline{DF}$. The acute angle at $D$ is labeled $\theta$. No side lengths are shown, and the diagram is not drawn to scale. Which expression defines $\cos(\theta)$?

Question graphic

$\dfrac{EF}{DF}$

$\dfrac{EF}{DE}$

$\dfrac{DE}{DF}$

$\dfrac{DF}{DE}$

Explanation

The skill involves defining trigonometric ratios using the similarity of right triangles. Right triangles that share an acute angle $\theta$ are similar because they both have angles $\theta$, $90^\circ$, and $90^\circ - \theta$, satisfying the AA similarity criterion. In triangle DEF with right angle at E and $\theta$ at D, the side opposite $\theta$ is EF, the adjacent side is DE, and the hypotenuse is DF. The cosine of $\theta$ is defined as the ratio of the adjacent side to the hypotenuse, which is $\frac{\text{DE}}{\text{DF}}$. This ratio depends only on the measure of $\theta$, as similar right triangles have corresponding sides in proportion, making the ratio constant for a given $\theta$. A common misconception is to choose EF/DF for cosine, which mistakes adjacent for opposite and actually represents sine. To apply this in any right triangle, first label the sides as opposite, adjacent, and hypotenuse relative to the given angle.

6

A right triangle $\triangle STU$ is drawn with $\angle T$ marked as a right angle. The acute angle at $S$ is labeled $\theta$. A student says, “$\sin(\theta)$ is the ratio of the longer leg to the shorter leg.” Which claim about the ratio is NOT justified by right-triangle similarity and the definition of sine?

$\sin(\theta)$ is the same for all right triangles with angle $\theta$

$\sin(\theta)=\dfrac{TU}{SU}$

$\sin(\theta)$ depends on which leg is longer

$\sin(\theta)$ equals a ratio of two sides

Explanation

The skill involves defining trigonometric ratios using the similarity of right triangles. Right triangles with the same acute angle are similar because they each have a 90-degree angle and share one acute angle, making the third angles equal by the angle sum in a triangle. In triangle STU with right angle at T and angle θ at S, the side opposite θ is TU, the adjacent side is ST, and the hypotenuse is SU. The sine of θ is defined as the ratio of the opposite side to the hypotenuse, which is TU/SU. This ratio depends only on the measure of θ and is constant across similar triangles. A common misconception is to claim sine depends on which leg is longer, but it is fixed for the angle regardless of leg lengths. To apply this to other problems, always start by labeling the sides as opposite, adjacent, and hypotenuse relative to the given angle.

7

In right triangle $\triangle VWX$, $\angle W$ is marked as a right angle. The acute angles at $V$ and $X$ are labeled $\theta$ and $\phi$, respectively. (The diagram is not drawn to scale.) Which ratio represents $\cos(\theta)$?

Question graphic

$\dfrac{VW}{VX}$

$\dfrac{VX}{VW}$

$\dfrac{WX}{VW}$

$\dfrac{WX}{VX}$

Explanation

The skill involves defining trigonometric ratios using the similarity of right triangles. Right triangles with the same acute angle are similar because they each have a 90-degree angle and share one acute angle, making the third angles equal by the angle sum in a triangle. In triangle VWX with right angle at W and angle $\theta$ at V, the side opposite $\theta$ is $WX$, the adjacent side is $VW$, and the hypotenuse is $VX$. The cosine of $\theta$ is defined as the ratio of the adjacent side to the hypotenuse, which is $\dfrac{VW}{VX}$. This ratio depends only on the measure of $\theta$ and is constant across similar triangles. A common misconception is to select $\dfrac{VX}{VW}$, which is the secant of $\theta$ rather than cosine. To apply this to other problems, always start by labeling the sides as opposite, adjacent, and hypotenuse relative to the given angle.

8

In the coordinate plane, right triangle $\triangle ABC$ is shown with $\angle C$ marked as a right angle. Point $A$ is to the left of $C$, and point $B$ is above $C$, so $\overline{AC}$ is horizontal and $\overline{BC}$ is vertical. The acute angle at $A$ is labeled $\theta$. (The diagram is not drawn to scale.) Which ratio represents $\sin(\theta)$?

Question graphic

$\dfrac{AC}{AB}$

$\dfrac{AB}{BC}$

$\dfrac{BC}{AB}$

$\dfrac{BC}{AC}$

Explanation

The skill involves defining trigonometric ratios using the similarity of right triangles. Right triangles with the same acute angle are similar because they each have a 90-degree angle and share one acute angle, making the third angles equal by the angle sum in a triangle. In triangle ABC with right angle at C and angle θ at A, the side opposite θ is BC, the adjacent side is AC, and the hypotenuse is AB. The sine of θ is defined as the ratio of the opposite side to the hypotenuse, which is BC/AB. This ratio depends only on the measure of θ and is constant across similar triangles. A common misconception is to select BC/AC, which represents the tangent of θ instead of sine. To apply this to other problems, always start by labeling the sides as opposite, adjacent, and hypotenuse relative to the given angle.

9

A right triangle $\triangle GHI$ is shown with $\angle H$ marked as a right angle. The acute angle at $I$ is labeled $\theta$. (The diagram is not drawn to scale.) Which ratio represents $\sin(\theta)$?

Question graphic

$\dfrac{HI}{GH}$

$\dfrac{GH}{GI}$

$\dfrac{HI}{GI}$

$\dfrac{GI}{GH}$

Explanation

The skill involves defining trigonometric ratios using the similarity of right triangles. Right triangles with the same acute angle are similar because they each have a 90-degree angle and share one acute angle, making the third angles equal by the angle sum in a triangle. In $\triangle GHI$ with right angle at H and angle $\theta$ at I, the side opposite $\theta$ is GH, the adjacent side is HI, and the hypotenuse is GI. The sine of $\theta$ is defined as the ratio of the opposite side to the hypotenuse, which is $\frac{\mathrm{GH}}{\mathrm{GI}}$. This ratio depends only on the measure of $\theta$ and is constant across similar triangles. A common misconception is to select $\frac{\mathrm{HI}}{\mathrm{GH}}$, which is the tangent of $\theta$ rather than sine. To apply this to other problems, always start by labeling the sides as opposite, adjacent, and hypotenuse relative to the given angle.

10

In right triangle $\triangle JKL$, $\angle K$ is marked as a right angle, and the acute angle at $J$ is labeled $\theta$. (The diagram is not drawn to scale.) Which statement correctly defines a trigonometric ratio for $\theta$?

Question graphic

$\sin(\theta)=\dfrac{JK}{KL}$

$\sin(\theta)=\dfrac{KL}{JL}$

$\tan(\theta)=\dfrac{JL}{JK}$

$\cos(\theta)=\dfrac{JL}{JK}$

Explanation

The skill involves defining trigonometric ratios using the similarity of right triangles. Right triangles with the same acute angle are similar because they each have a 90-degree angle and share one acute angle, making the third angles equal by the angle sum in a triangle. In triangle JKL with right angle at K and angle θ at J, the side opposite θ is KL, the adjacent side is JK, and the hypotenuse is JL. The sine of θ is defined as the ratio of the opposite side to the hypotenuse, which is KL/JL. This ratio depends only on the measure of θ and is constant across similar triangles. A common misconception is to define cosine as JL/JK, which is actually the secant of θ. To apply this to other problems, always start by labeling the sides as opposite, adjacent, and hypotenuse relative to the given angle.

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