### All AP Physics C: Mechanics Resources

## Example Questions

### Example Question #1 : Electric Circuits

A parallel plate capacitor has a capacitance of . If the plates are apart, what is the area of the plates?

**Possible Answers:**

**Correct answer:**

The relationship between capacitance, distance, and area is . We can rearrange this equation to solve for area.

Now, we can use the values given in teh question to solve.

### Example Question #1 : Electric Circuits

Charge is distributed uniformly over the area of the two plates of a parallel plate capacitor, resulting in a surface area charge density of ** **on the plates (the top plate is positive and the bottom is negative, as shown below). Each plate has area and are separated by distance . A material of dielectric constant has been placed between the two plates.

Which of the following would not result in an increase in the measure of electric potential difference between the two plates?

**Possible Answers:**

Replace the material between the two plates with one of a lower dielectric constant,

Increase the area, , of the plates

Increase the distance, , between the plates

Increase the value of the surface charge density, , on each plate

**Correct answer:**

Increase the area, , of the plates

The electric potential difference created between the plates of a parallel plate capactor is given by the equation:

The charge can be calculated by using the equation:

The value of the capacitance is related to the dimensions of the capacitor with the equation:

Combining these equations yields:

The area becomes inconsequential, while the potential is directly proportional to the surface charge density and the distance between the plates, and inversely proportional to the dielectric of the material between the plates. Changing the area does not cause any change in the potential difference measured between the plates, and changing any of the other variables would cause a resultant change in the potential difference.

### Example Question #1 : Capacitors

You are hired to make a capacitor out of two parallel metal sheets. If someone wanted you to make a thin capacitor of out of those metal sheets, and the sheets needed to be apart, what area do the two metal plates need to be?

**Possible Answers:**

**Correct answer:**

For parallel plate capacitors, the equation is .

Solve for .

Now we can plug in our given values.

### Example Question #1 : Capacitors

The plates of a parallel plate capacitor are apart and in area. A potential difference of is applied across the capacitor. Find the capacitance.

**Possible Answers:**

**Correct answer:**

Capacitance is related to plate area and distance by the equation .

Given the area and distance, we can solve for capacitance. The voltage, in this case, is irrelevant.

### Example Question #2 : Capacitors

The plates of a parallel plate capacitor are apart and in area. A potential difference of is applied across the capacitor. Compute the charge on each plate.

**Possible Answers:**

**Correct answer:**

Charge on a capacitor is given by the equation . We know that the voltage is , but we need to determine the capacitance based off of the area and distance between the plates.

We can plug this value into the equation for charge.

### Example Question #1 : Electric Circuits

The plates of a parallel plate capacitor are apart. A potential difference of is applied across the capacitor. Compute the magnitude of the generated electric field.

**Possible Answers:**

**Correct answer:**

The electric field given by a capacitor is given by the formula . We do not have these variables, so we will have to adjust the equation.

The capacitance can be determined by the area of the plates and the distance between them.

This equation simplifies to , allowing us to solve using the values given in the question.

### Example Question #1 : Using Capacitor Equations

If two identical parallel plate capacitors of capacitance are connected in series, which is true of the equivalent capacitance, ?

**Possible Answers:**

**Correct answer:**

Relevant equations:

Use the series equation, replacing C1 and C2 with the given constant C:

This agrees with the general rule that the equivalent capacitance in series is less than the capacitance of any of the individual capacitors.

### Example Question #1 : Capacitors

Two parallel conducting plates each have an area of and are separated by a distance, . One plate has a charge evenly distributed across it, and the other has a charge of . A proton (charge ) is initially held near the positive plate, then released such that it accelerates towards the negative plate. How much kinetic energy has the proton gained in this process?

**Possible Answers:**

**Correct answer:**

Relevant equations:

According to the work-energy theorem, work done on the proton is equal to its change in kinetic energy.

1. Find an expression for potential difference, , in terms of and , by setting the two capacitance equations equal to each other:

2. Multiply the potential difference times the proton charge to find work (and thus kinetic energy):

### Example Question #61 : Electricity And Magnetism Exam

A and capacitor are connected in series with a battery. What is the magnitude of the charge on one plate of the capacitor?

**Possible Answers:**

**Correct answer:**

Relevant equations:

First, find the equivalent capacitance of the whole circuit:

Use this equivalent capacitance to find the total charge:

Capacitors in series always have the same charge on each unit, so the charge on the capacitor is also .

### Example Question #3 : Electric Circuits

Resistors are one of the most important basic components of a circuit. With very few exceptions, all circuits have at least one kind of resistor component. An ammeter is a device that measures current flowing through a circuit. Ammeters are always connected to a circuit in series.

Which of the following accurately explains why ammeters must be connected in series within a circuit, and never in parallel?

**Possible Answers:**

An ammeter connected in parallel would give very low readings of current because current would be flowing through both the regular current path and the ammeter, but disproportionately through the regular path

An ammeter connected in parallel would give readings of half the current flowing through the circuit because current would flow evenly between the ammeter and the circuit's regular pathway

An ammeter connected in parallel would give the current flowing through the circuit a pathway with minimal resistance, creating a very large current that could harm the ammeter

An ammeter connected in parallel would not read any current because the current would have no driving force through the ammeter

An ammeter connected in parallel would give high readings of current because the current would be flowing through both the regular current path and the ammeter, but disproportionately through the ammeter

**Correct answer:**

An ammeter connected in parallel would give the current flowing through the circuit a pathway with minimal resistance, creating a very large current that could harm the ammeter

In order to give accurate readings of current, ammeters have very low resistances. If connected in parallel, the voltage pushing current through the circuit would push a very strong current through the ammeter and virtually no current through the circuit's regular path. This would not only lead to a bad reading of current, but more often than not a broken ammeter. This phenomenon is an indication of why resistors are so important: they limit the current such that a circuit does not exceed its current-carrying capacity.

Certified Tutor