AP Chemistry Flashcards: Deviation From Ideal Gas Law

Study Deviation From Ideal Gas Law in AP Chemistry with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

AP Chemistry

Deviation From Ideal Gas Law

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QUESTION
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Identify a gas that behaves nearly ideally under ordinary conditions.

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ANSWER

Helium. Small, light atoms with weak intermolecular forces.

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Flashcard 1: Identify a gas that behaves nearly ideally under ordinary conditions.

Answer: Helium. Small, light atoms with weak intermolecular forces.

Flashcard 2: Find the pressure correction in Van der Waals equation for 1mol1 \text{mol} of gas.

Answer: aV2\frac{a}{V^2}. For 1 mole, n=1n = 1, so the correction becomes aV2\frac{a}{V^2}.

Flashcard 3: What is the Van der Waals equation?

Answer: (P+an2V2)(Vnb)=nRT(P + \frac{an^2}{V^2})(V - nb) = nRT. Modified ideal gas law accounting for real gas behavior.

Flashcard 4: What does a high value of 'a' indicate in Van der Waals equation?

Answer: Strong intermolecular forces. Large 'a' means strong attractive forces between molecules.

Flashcard 5: Provide the value of the universal gas constant 'R'.

Answer: R=0.0821L×atmmol×KR = 0.0821 \frac{L \times atm}{mol \times K}. The standard value used in gas law calculations.

Flashcard 6: How does Van der Waals equation modify the Ideal Gas Law?

Answer: Corrects for volume and pressure deviations. Adds corrections for molecular size and intermolecular forces.

Flashcard 7: State the definition of an ideal gas.

Answer: An ideal gas perfectly follows the Ideal Gas Law. A theoretical gas that obeys all gas law assumptions perfectly.

Flashcard 8: What is the primary cause of deviation at low temperatures?

Answer: Increased intermolecular attractions. Lower temperatures enhance attractive forces between gas molecules.

Flashcard 9: Name another condition for deviation from ideal behavior.

Answer: Low temperature. Reduces kinetic energy, allowing intermolecular forces to dominate.

Flashcard 10: What is the Ideal Gas Law equation?

Answer: PV=nRTPV = nRT. The fundamental relationship between pressure, volume, moles, and temperature.

Flashcard 11: What is the primary focus of the Van der Waals equation?

Answer: Correcting Ideal Gas Law for real gases. Modifies ideal gas law to account for real gas behavior.

Flashcard 12: What is the significance of 'R' in the Ideal Gas Law?

Answer: 'R' is the universal gas constant. A proportionality constant linking pressure, volume, moles, and temperature.

Flashcard 13: Calculate pressure deviation using P=4atmP = 4 \text{atm}, a=0.8a = 0.8, V=20LV = 20 \text{L}.

Answer: Deviation=0.8202\text{Deviation} = \frac{0.8}{20^2}. Pressure correction term: aV2\frac{a}{V^2} for 1 mole of gas.

Flashcard 14: What does 'a' in Van der Waals equation account for?

Answer: Intermolecular attraction forces. Parameter representing strength of intermolecular attractive forces.

Flashcard 15: Identify another assumption of the Ideal Gas Law.

Answer: Gas particles exert no intermolecular forces. Assumes no attractive or repulsive forces between particles.

Flashcard 16: What is the effect of molecular size on gas deviation?

Answer: Larger size increases deviation. Larger molecules occupy more space, increasing deviation from ideality.

Flashcard 17: Identify a situation where Ideal Gas Law fails.

Answer: At very high pressures. Extreme pressure makes particle volume and forces significant.

Flashcard 18: What is the effect of intermolecular forces on gas pressure?

Answer: Decreases observed pressure. Attractive forces reduce pressure exerted on container walls.

Flashcard 19: What does the term nbnb in Van der Waals equation represent?

Answer: Volume occupied by gas particles. Total volume excluded due to finite molecular size.

Flashcard 20: What is the main limitation of the Ideal Gas Law?

Answer: Assumes no volume and no interactions between particles. Ignores real effects: molecular size and intermolecular forces.

Flashcard 21: Name a condition under which real gases deviate from ideal behavior.

Answer: High pressure. Forces particles closer, making volume and intermolecular forces significant.

Flashcard 22: Calculate nn if P=3atmP = 3 \text{atm}, V=10LV = 10 \text{L}, T=400KT = 400 \text{K}, R=0.0821R = 0.0821.

Answer: n=PVRT=0.914moln = \frac{PV}{RT} = 0.914 \text{mol}. Using n=PVRTn = \frac{PV}{RT} with given values yields 0.914 mol.

Flashcard 23: What effect does increasing pressure have on gas behavior?

Answer: Gases deviate more from ideal behavior. Higher pressure compresses gas, making particle volume more significant.

Flashcard 24: Calculate corrected pressure using P=3atmP = 3 \text{atm}, a=0.5a = 0.5, V=10LV = 10 \text{L}.

Answer: P=3+0.5102=3.005atmP' = 3 + \frac{0.5}{10^2} = 3.005 \text{atm}. Adding pressure correction: P+an2V2P + \frac{an^2}{V^2} for n=1n=1.

Flashcard 25: What correction does bb account for in the Van der Waals equation?

Answer: Volume of gas particles. The finite size of gas molecules reduces available volume.

Flashcard 26: Calculate TT if P=2atmP = 2 \text{atm}, V=5LV = 5 \text{L}, n=1moln = 1 \text{mol}, R=0.0821R = 0.0821.

Answer: T=PVnR=121.95KT = \frac{PV}{nR} = 121.95 \text{K}. Rearranging ideal gas law: T=PVnRT = \frac{PV}{nR} gives 121.95 K.

Flashcard 27: Identify the correction factor for intermolecular forces in Van der Waals.

Answer: an2V2\frac{an^2}{V^2}. Accounts for attractive forces reducing observed pressure.

Flashcard 28: Calculate PP if V=10LV = 10 \text{L}, n=1moln = 1 \text{mol}, T=300KT = 300 \text{K}, R=0.0821R = 0.0821.

Answer: P=nRTV=2.463atmP = \frac{nRT}{V} = 2.463 \text{atm}. Using P=nRTVP = \frac{nRT}{V} with given values yields 2.463 atm.

Flashcard 29: Which gas law relates pressure and volume at constant temperature?

Answer: Boyle's Law. States that PVPV is constant at fixed temperature.

Flashcard 30: What happens to PV/nRTPV/nRT for an ideal gas?

Answer: Equals 1. Compressibility factor equals 1 for perfect ideal behavior.

Flashcard 31: Name one assumption of the Ideal Gas Law.

Answer: Gas particles have no volume. Assumes particles are point masses with negligible size.

Flashcard 32: What modification do real gases have compared to ideal gases?

Answer: Non-zero volume and intermolecular forces. Real gases have finite size and experience intermolecular attractions.

Flashcard 33: Which real gas behavior is corrected by the term (P+an2V2)(P + \frac{an^2}{V^2})?

Answer: Pressure correction for intermolecular forces. Accounts for reduced pressure due to intermolecular attractions.

Flashcard 34: Identify the term for the effective volume in Van der Waals equation.

Answer: VnbV - nb. Available volume after subtracting space occupied by gas particles.

Flashcard 35: What effect does increasing pressure have on gas behavior?

Answer: Gases deviate more from ideal behavior. Higher pressure compresses gas, making particle volume more significant.

Flashcard 36: What happens to gas particles at low temperatures?

Answer: Intermolecular forces become significant. Reduced kinetic energy allows attractive forces to affect behavior.

Flashcard 37: Which gas law relates volume and temperature at constant pressure?

Answer: Charles's Law. States that V/TV/T is constant at fixed pressure.

Flashcard 38: State the critical temperature's influence on gas behavior.

Answer: Above it, gases behave more ideally. Higher temperatures overcome intermolecular forces, approaching ideal behavior.

Flashcard 39: Calculate volume if P=1atmP = 1 \text{atm}, n=1moln = 1 \text{mol}, T=273KT = 273 \text{K}, R=0.0821R = 0.0821.

Answer: V=nRTP=22.414LV = \frac{nRT}{P} = 22.414 \text{L}. Standard molar volume calculation at STP conditions.

Flashcard 40: What causes real gases to deviate from ideal behavior at high pressures?

Answer: Finite volume of gas particles. Molecular volume becomes significant fraction of container volume.