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This deck focuses on Ideal Gas Law, giving you a quick way to review the definitions, rules, and examples that matter most for AP Chemistry.
Study Ideal Gas Law in AP Chemistry with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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This deck focuses on Ideal Gas Law, giving you a quick way to review the definitions, rules, and examples that matter most for AP Chemistry.
Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
Answer: 298 K. Add 273.15 to convert Celsius to Kelvin.
Answer: A hypothetical gas with perfectly elastic collisions. Gas with no intermolecular forces and negligible particle volume.
Answer: Atmospheres (atm). Standard unit of pressure in gas law calculations.
Answer: Directly proportional. Higher temperature means faster-moving gas molecules.
Answer: Pressure. Force per unit area exerted by gas molecules on container walls.
Answer: P1V1=P2V2. Pressure-volume relationship at constant temperature and moles.
Answer: 1 mol. Using n=RTPV=298×0.08211×24.4.
Answer: Volume is directly proportional to temperature. At constant pressure, volume increases linearly with temperature.
Answer: PV=nRT. The fundamental relationship between pressure, volume, moles, and temperature for ideal gases.
Answer: Pressure doubles. More gas particles create greater pressure at constant volume and temperature.
Answer: PV=nRT. The fundamental relationship between pressure, volume, moles, and temperature for ideal gases.
Answer: Pressure is inversely proportional to volume. At constant temperature, decreasing volume increases pressure proportionally.
Answer: L atm mol−1 K−1. Combines units of pressure, volume, temperature, and moles.
Answer: Pressure doubles. More gas particles create greater pressure at constant volume and temperature.
Answer: 0.406 mol. Using n=RTPV=0.0821×3002×5.
Answer: 2.46 atm. Using P=VnRT=101×0.0821×300.
Answer: Pressure is inversely proportional to volume. At constant temperature, decreasing volume increases pressure proportionally.
Answer: Kelvin (K). Absolute temperature scale required for gas law calculations.
Answer: T1P1V1=T2P2V2. Relates initial and final states when moles remain constant.
Answer: Volume. Space occupied by the gas, typically measured in liters.
Answer: P1V1=P2V2. Pressure-volume relationship at constant temperature and moles.
Answer: 366 K. Using T=nRPV=0.5×0.08213×5.
Answer: Volume remains the same. Both pressure and temperature changes cancel out in the ideal gas law.
Answer: Pressure is inversely proportional to volume. At constant temperature, decreasing volume increases pressure proportionally.
Answer: Pressure doubles. Inverse relationship from Boyle's Law at constant temperature.
Answer: n1V1=n2V2. Volume-moles relationship at constant pressure and temperature.
Answer: 6 atm. Direct proportionality from Gay-Lussac's Law.
Answer: P1V1=P2V2. Pressure-volume relationship at constant temperature and moles.
Answer: Liters (L). Standard unit of volume in gas law calculations.
Answer: Ideal gas constant. Universal constant relating gas properties, equal to 0.0821 L atm mol−1 K−1.
Answer: Pressure doubles. Inverse relationship from Boyle's Law at constant temperature.
Answer: Low pressure and high temperature. Minimal intermolecular forces and particle volume for ideal behavior.
Answer: Pressure doubles. More gas particles create greater pressure at constant volume and temperature.
Answer: Low pressure and high temperature. Minimal intermolecular forces and particle volume for ideal behavior.
Answer: P1V1=P2V2. Pressure-volume relationship at constant temperature and moles.
Answer: T1P1=T2P2. Pressure-temperature relationship at constant volume and moles.
Answer: 4.92 atm. Using P=VnRT=102×0.0821×300.
Answer: 0.406 mol. Using n=RTPV=0.0821×3002×5.
Answer: T1V1=T2V2. Volume-temperature relationship at constant pressure and moles.
Answer: 0.0821 L atm mol−1 K−1. Standard value used in ideal gas calculations.
Answer: 2.46 atm. Using P=VnRT=101×0.0821×300.
Answer: Temperature in Kelvin. Absolute temperature scale where molecular motion ceases at 0 K.
Answer: Amount of substance in moles. Number of moles quantifies the amount of gas particles present.
Answer: 1 mol. Using n=RTPV=298×0.08211×24.4.
Answer: 273 K. Absolute zero on the Kelvin scale, equivalent to 0°C.
Answer: Volume remains the same. Both pressure and temperature changes cancel out in the ideal gas law.
Answer: Volume decreases to one-third. Inverse relationship from Boyle's Law.
Answer: 366 K. Using T=nRPV=0.5×0.08213×5.
Answer: Liters (L). Standard unit of volume in gas law calculations.
Answer: 298 K. Add 273.15 to convert Celsius to Kelvin.
Answer: Amount of substance in moles. Number of moles quantifies the amount of gas particles present.
Answer: L atm mol−1 K−1. Combines units of pressure, volume, temperature, and moles.
Answer: Ideal gas constant. Universal constant relating gas properties, equal to 0.0821 L atm mol−1 K−1.
Answer: Volume is directly proportional to temperature. At constant pressure, volume increases linearly with temperature.
Answer: L atm mol−1 K−1. Combines units of pressure, volume, temperature, and moles.
Answer: PV=nRT. The fundamental relationship between pressure, volume, moles, and temperature for ideal gases.
Answer: Pressure doubles. More gas particles create greater pressure at constant volume and temperature.
Answer: Volume doubles. Direct relationship from Charles's Law at constant pressure.
Answer: 22.4 L. Molar volume of an ideal gas at STP (standard temperature and pressure).
Answer: 0.0821 L atm mol−1 K−1. Standard value used in ideal gas calculations.
Answer: 27°C. Subtract 273.15 to convert Kelvin to Celsius.
Answer: Gay-Lussac's Law. Describes pressure-temperature relationship at constant volume.
Answer: PV=nRT. The fundamental relationship between pressure, volume, moles, and temperature for ideal gases.
Answer: Amount of substance in moles. Number of moles quantifies the amount of gas particles present.
Answer: Amount of substance in moles. Number of moles quantifies the amount of gas particles present.
Answer: Pressure is inversely proportional to volume. At constant temperature, decreasing volume increases pressure proportionally.
Answer: Volume is directly proportional to moles. At constant pressure and temperature, volume scales with particle number.
Answer: 273 K. Using T=nRPV=1×0.08211×22.4.
Answer: 6 atm. Direct proportionality from Gay-Lussac's Law.
Answer: L atm mol−1 K−1. Combines units of pressure, volume, temperature, and moles.