Home

Tutoring

Subjects

Live Classes

Study Coach

Essay Review

On-Demand Courses

Colleges

Games

Opening subject page...

Loading your content

  1. My Subjects
  3. AP Chemistry

  5. Flashcards

AP Chemistry Flashcards: Properties Of Photons

Study Properties Of Photons in AP Chemistry with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

← Back to flashcard decks

What this deck covers

This deck focuses on Properties Of Photons, giving you a quick way to review the definitions, rules, and examples that matter most for AP Chemistry.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

AP Chemistry Flashcards: Properties Of Photons

1

/ 30

0 reviewed

0% Complete

0 reviewing
QUESTION

Find the energy of a photon with frequency 5×10145 \times 10^{14}5×1014 Hz.

Tap or drag to reveal answer

ANSWER

E=3.31×10−19 JE = 3.31 \times 10^{-19} \text{ J}E=3.31×10−19 J. Using E=hfE = hfE=hf with h=6.626×10−34h = 6.626 \times 10^{-34}h=6.626×10−34 J·s.

Swipe Right = I Know It! 🎉

Swipe Left = Still Learning

All flashcards

Flashcard 1: Find the energy of a photon with frequency 5×10145 \times 10^{14}5×1014 Hz.

Answer: E=3.31×10−19 JE = 3.31 \times 10^{-19} \text{ J}E=3.31×10−19 J. Using E=hfE = hfE=hf with h=6.626×10−34h = 6.626 \times 10^{-34}h=6.626×10−34 J·s.

Flashcard 2: What is the relationship between photon momentum and wavelength?

Answer: p=hλp = \frac{h}{\lambda}p=λh​. Momentum inversely related to wavelength via Planck's constant.

Flashcard 3: Identify the constant used for the speed of light.

Answer: c=3.00×108 m/sc = 3.00 \times 10^8 \text{ m/s}c=3.00×108 m/s. Symbol ccc represents speed of light in equations.

Flashcard 4: Identify the formula for the momentum of a photon.

Answer: p=hwavelengthp = \frac{h}{\text{wavelength}}p=wavelengthh​. De Broglie relation for photon momentum using wavelength.

Flashcard 5: How do you express energy in electronvolts (eV)?

Answer: 1 eV = 1.602×10−191.602 \times 10^{-19}1.602×10−19 J. Conversion factor between joules and electronvolts.

Flashcard 6: What is the relationship between frequency and photon energy?

Answer: Directly proportional. Linear relationship from Planck's equation E=hfE = hfE=hf.

Flashcard 7: Determine the energy in eV for a photon with 3.2×10−193.2 \times 10^{-19}3.2×10−19 J.

Answer: 2 eV. Dividing energy by conversion factor 1.602×10−191.602 \times 10^{-19}1.602×10−19 J/eV.

Flashcard 8: Which fundamental constant is used in calculating photon's energy?

Answer: Planck's constant (hhh). Quantum constant linking energy and frequency in photon equations.

Flashcard 9: What is the inverse relationship of wavelength and frequency?

Answer: As wavelength increases, frequency decreases. Inverse relationship from c=νλc = \nu \lambdac=νλ equation.

Flashcard 10: Calculate energy of a photon with wavelength 400 nm400 \text{ nm}400 nm.

Answer: E=4.97×10−19 JE = 4.97 \times 10^{-19} \text{ J}E=4.97×10−19 J. Using E=hcλE = \frac{hc}{\lambda}E=λhc​ with 400400400 nm wavelength.

Flashcard 11: Calculate frequency for photon with energy 2.5×10−192.5 \times 10^{-19}2.5×10−19 J.

Answer: ν=3.77×1014 Hz\nu = 3.77 \times 10^{14} \text{ Hz}ν=3.77×1014 Hz. Using ν=Eh\nu = \frac{E}{h}ν=hE​ with given energy value.

Flashcard 12: What does the symbol λ\lambdaλ represent?

Answer: Wavelength. Lambda is the standard symbol for wavelength.

Flashcard 13: State the symbol for speed of light.

Answer: ccc. Standard symbol for speed of light constant.

Flashcard 14: Identify the constant used for the speed of light.

Answer: c=3.00×108 m/sc = 3.00 \times 10^8 \text{ m/s}c=3.00×108 m/s. Symbol ccc represents speed of light in equations.

Flashcard 15: Identify the formula for the momentum of a photon.

Answer: p=hwavelengthp = \frac{h}{\text{wavelength}}p=wavelengthh​. De Broglie relation for photon momentum using wavelength.

Flashcard 16: How do you express energy in electronvolts (eV)?

Answer: 1 eV = 1.602×10−191.602 \times 10^{-19}1.602×10−19 J. Conversion factor between joules and electronvolts.

Flashcard 17: Find the energy of a photon with frequency 5×10145 \times 10^{14}5×1014 Hz.

Answer: E=3.31×10−19 JE = 3.31 \times 10^{-19} \text{ J}E=3.31×10−19 J. Using E=hfE = hfE=hf with h=6.626×10−34h = 6.626 \times 10^{-34}h=6.626×10−34 J·s.

Flashcard 18: What is the relationship between photon momentum and wavelength?

Answer: p=hλp = \frac{h}{\lambda}p=λh​. Momentum inversely related to wavelength via Planck's constant.

Flashcard 19: What is the relationship between frequency and photon energy?

Answer: Directly proportional. Linear relationship from Planck's equation E=hfE = hfE=hf.

Flashcard 20: Determine the energy in eV for a photon with 3.2×10−193.2 \times 10^{-19}3.2×10−19 J.

Answer: 2 eV. Dividing energy by conversion factor 1.602×10−191.602 \times 10^{-19}1.602×10−19 J/eV.

Flashcard 21: Which fundamental constant is used in calculating photon's energy?

Answer: Planck's constant (hhh). Quantum constant linking energy and frequency in photon equations.

Flashcard 22: What is the inverse relationship of wavelength and frequency?

Answer: As wavelength increases, frequency decreases. Inverse relationship from c=νλc = \nu \lambdac=νλ equation.

Flashcard 23: Calculate energy of a photon with wavelength 400 nm400 \text{ nm}400 nm.

Answer: E=4.97×10−19 JE = 4.97 \times 10^{-19} \text{ J}E=4.97×10−19 J. Using E=hcλE = \frac{hc}{\lambda}E=λhc​ with 400400400 nm wavelength.

Flashcard 24: Calculate frequency for photon with energy 2.5×10−192.5 \times 10^{-19}2.5×10−19 J.

Answer: ν=3.77×1014 Hz\nu = 3.77 \times 10^{14} \text{ Hz}ν=3.77×1014 Hz. Using ν=Eh\nu = \frac{E}{h}ν=hE​ with given energy value.

Flashcard 25: What does the symbol λ\lambdaλ represent?

Answer: Wavelength. Lambda is the standard symbol for wavelength.

Flashcard 26: State the symbol for speed of light.

Answer: ccc. Standard symbol for speed of light constant.

Flashcard 27: What does the symbol λ\lambdaλ represent?

Answer: Wavelength. Lambda is the standard symbol for wavelength.

Flashcard 28: Find the energy of a photon with frequency 5×10145 \times 10^{14}5×1014 Hz.

Answer: E=3.31×10−19 JE = 3.31 \times 10^{-19} \text{ J}E=3.31×10−19 J. Using E=hfE = hfE=hf with h=6.626×10−34h = 6.626 \times 10^{-34}h=6.626×10−34 J·s.

Flashcard 29: What is the relationship between photon momentum and wavelength?

Answer: p=hλp = \frac{h}{\lambda}p=λh​. Momentum inversely related to wavelength via Planck's constant.

Flashcard 30: Identify the constant used for the speed of light.

Answer: c=3.00×108 m/sc = 3.00 \times 10^8 \text{ m/s}c=3.00×108 m/s. Symbol ccc represents speed of light in equations.