### All PSAT Math Resources

## Example Questions

### Example Question #1 : Permutation / Combination

Mark has 5 pants and 7 shirts in his closet. He wants to wear a different pant/shirt combination each day without buying new clothes for as long as he can. How many weeks can he do this for?

**Possible Answers:**

4

7

8

5

6

**Correct answer:**

5

The fundamental counting principle says that if you want to determine the number of ways that two independent events can happen, multiply the number of ways each event can happen together. In this case, there are 5 * 7, or 35 unique combinations of pants & shirts Mark can wear. If he wears one combination each day, he can last 35 days, or 5 weeks, without buying new clothes.

### Example Question #1 : Permutation / Combination

Twenty students enter a contest at school. The contest offers a first, second, and third prize. How many different combinations of 1st, 2^{nd}, and 3rd place winners can there be?

**Possible Answers:**

20

6840

4620

8000

400

**Correct answer:**

6840

This is a permutation problem, because we are looking for the number of groups of winners. Consider the three positions, and how many choices there are for each position: There are 20 choices for 1st place, 19 for 2nd place, and 18 for 3rd place.

20, 19, 18

Multiply to get 6840.

### Example Question #117 : Integers

A baker has four different types of frosting, three different kinds of sprinkles, and 8 different cookie cutters. How many different cookie combinations can the baker create if each cookie has one type of frosting and one type of sprinkle?

**Possible Answers:**

24

15

48

96

**Correct answer:**

96

Since this a combination problem and we want to know how many different ways the cookies can be created we can solve this using the Fundamental counting principle. 4 x 3 x 8 = 96

Multiplying each of the possible choices together.

### Example Question #1714 : Sat Mathematics

If a series of license plates is to be produced that all have the same pattern of three letters followed by three numbers, roughly how many alphanumeric combinations are possible?

**Possible Answers:**

18 million

1 thousand

180 million

18 thousand

11 million

**Correct answer:**

18 million

The total number of possible combinations of a series of items is the product of the total possibility for each of the items. Thus, for the letters, there are 26 possibilities for each of the 3 slots, and for the numbers, there are 10 possibilities for each of the 3 slots. The total number of combinations is then: 26 x 26 x 26 x 10 x 10 x 10 = 17,576,000 ≈ 18 million.

### Example Question #119 : Integers

If there are 8 points in a plane, and no 3 of the points lie along the same line, how many unique lines can be drawn between pairs of these 8 points?

**Possible Answers:**

28

27

29

30

**Correct answer:**

28

The formula for the number of lines determined by n points, no three of which are “collinear” (on the same line), is n(n-1)/2. To find the number of lines determined by 8 points, we use 8 in the formula to find 8(8-1)/2=8(7)/2=56/2=28. (The formula is derived from two facts: the fact that each point forms a line with each other point, hence n(n-1), and the fact that this relationship is symmetric (i.e. if a forms a line with b, then b forms a line with a), hence dividing by 2.)

### Example Question #1721 : Sat Mathematics

8 people locked in a room take turns holding hands with each person only once. How many hand holdings take place?

**Possible Answers:**

24

28

15

21

**Correct answer:**

28

The first person holds 7 hands. The second holds six by virtue of already having help the first person’s hand. This continues until through all 8 people. 7+6+5+4+3+2+1=28.

### Example Question #121 : Integers

At an ice cream store, there are 5 flavors of ice cream: strawberry, vanilla, chocolate, mint, and banana. How many different 3-flavor ice cream cones can be made?

**Possible Answers:**

5

30

60

20

10

**Correct answer:**

10

There are 5x4x3 ways to arrange 5 flavors in 3 ways. However, in this case, the order of the flavors does not matter (e.g., a cone with strawberry, mint, and banana is the same as a cone with mint, banana, and strawberry). So we have to divide 5x4x3 by the number of ways we can arrange 3 different things which is 3x2x1. So (5x4x3)/(3x2x1) is 10.

One can also use the combination formula for this problem: _{n}C_{r} = n! / (n-r)! r!

Therefore: _{5}C_{3} = 5! / 3! 2!

= 10

(Note: an example of a counting problem in which order would matter is a lock or passcode situation. The permutation 3-5-7 for a three number lock or passcode is a distinct outcome from 5-7-3, and thus both must be counted.)

### Example Question #3 : Permutation / Combination

At a deli you can choose from either Italian bread, whole wheat bread, or sourdough bread. You can choose turkey or roast beef as your meat and provolone or mozzarella as your cheese. If you have to choose a bread, a meat, and a cheese, how many possible sandwich combinations can you have?

**Possible Answers:**

12

8

14

7

10

**Correct answer:**

12

You have 3 possible types of bread, 2 possible types of meat, and 2 possible types of cheese. Multiplying them out you get 3*2*2, giving you 12 possible combinations.

### Example Question #1722 : Sat Mathematics

Shannon decided to go to nearby café for lunch. She can have a sandwich made on either wheat or white bread. The café offers cheddar, Swiss, and American for cheese choices. For meat, Shannon can choose ham, turkey, bologna, roast beef, or salami. How many cheese and meat sandwich options does Shannon have to choose from?

**Possible Answers:**

35

20

10

30

25

**Correct answer:**

30

2 bread choices * 3 cheese choices * 5 meat choices = 30 sandwich choices

### Example Question #124 : Integers

An ice cream parlor serves 36 ice cream flavors. You can order any flavor in a small, medium or large and can choose between a waffle cone and a cup. How many possible combinations could you possibly order?

**Possible Answers:**

72

144

172

108

216

**Correct answer:**

216

36 possible flavors * 3 possible sizes * 2 possible cones = 216 possible combinations.

Certified Tutor