Proportionality>Solving Problems with Similar Shapes and Scale Drawings(TEKS.Math.7.5.C)

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Texas 7th Grade Math › Proportionality>Solving Problems with Similar Shapes and Scale Drawings(TEKS.Math.7.5.C)

Questions 1 - 3
1

On a blueprint with scale 1:50, a room measures 6 cm by 8 cm. What are the actual room dimensions?

0.12 m × 0.16 m

3 m × 4 m

30 m × 40 m

3.6 m × 4.8 m

Explanation

The linear scale factor is $k=50$. Actual lengths: 6×50=300 cm=3 m and 8×50=400 cm=4 m. So 3 m × 4 m. Distractors divide by 50, confuse cm-to-m conversion, or use the wrong factor.

2

A model car is built at a scale of 1:24. If the actual car is 4.8 m long, what is the length of the model?

20 cm

24 cm

2 m

4.8 cm

Explanation

For model:actual, the linear scale factor is $k=\tfrac{1}{24}$. Model length = 4.8×(1/24) = 0.2 m = 20 cm. Distractors multiply by 24, ignore unit conversion, or use an incorrect factor.

3

Two similar pentagons have perimeters 30 cm (smaller) and 45 cm (larger). What is the scale factor from the smaller to the larger pentagon?

1

2

2

15

Explanation

Perimeters scale linearly with $k$. So $k=\dfrac{45}{30}=1.5$. Choosing 0.67 reverses the ratio, 2.25 uses an area-type factor ($k^2$), and 15 confuses a length with a scale factor.