What this deck covers
This deck focuses on Analyzing Decisions And Strategies With Probability, giving you a quick way to review the definitions, rules, and examples that matter most for Statistics.
Study Analyzing Decisions And Strategies With Probability in Statistics with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
0% Complete
What is sensitivity in terms of conditional probability?
Tap card or press Space to flip
sensitivity=P(+∣D). Sensitivity is probability of positive test given disease.
How well did you know it?
Card 1 / 34
Space to flip · ← / → to move · once flipped, → Got it · ← Still learning
This deck focuses on Analyzing Decisions And Strategies With Probability, giving you a quick way to review the definitions, rules, and examples that matter most for Statistics.
Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
Answer: sensitivity=P(+∣D). Sensitivity is probability of positive test given disease.
Answer: P(test−∣no disease). Probability of negative test given no disease.
Answer: P(Ac)=1−P(A). Complement probability is one minus the event's probability.
Answer: 0.90. Apply Bayes' theorem: 0.5(0.9)+0.5(0.1)0.5(0.9)=0.50.45.
Answer: A,B independent iff P(A∣B)=P(A). Independence means conditioning doesn't change the probability.
Answer: Test indicates no disease when the person actually has the disease. Negative result despite disease being present.
Answer: NPV=P(Dc∣−). NPV is probability of no disease given negative test.
Answer: -\3.E=0.02(100)+0.98(-5)=2-4.9=-2.9\approx-3$.
Answer: P(test+∣disease). Probability of positive test given disease is present.
Answer: P(A∣B)=P(B)P(A∩B). Conditional probability is joint probability divided by condition's probability.
Answer: Test indicates disease when the person is actually disease-free. Positive result despite no disease present.
Answer: PPV=P(D∣+). PPV is probability of disease given positive test.
Answer: Pull the goalie. Pulling doubles win probability from 6% to 12%.
Answer: 4136. Apply Bayes' theorem: 0.2(0.1)+0.8(0.9)0.8(0.9)=0.820.72.
Answer: 31. Apply Bayes' theorem: 0.1(0.9)+0.9(0.2)0.1(0.9)=0.270.09.
Answer: P(D∣+)<0.5. Low disease prevalence makes PPV small despite high sensitivity.
Answer: E(X)=∑xP(X=x). Expected value sums products of outcomes and their probabilities.
Answer: Test negative when the person actually has the disease. False negative occurs when diseased person tests negative.
Answer: P(B∣Ac)P(B∣A)⋅P(Ac)P(A). Likelihood ratio times prior odds equals posterior odds.
Answer: Option B. Option A: E=0.4(10)=4; Option B: E=0.7(6)=4.2.
Answer: P(disease∣test+). Probability of having disease given positive test.
Answer: Keep the goalie in. Pull: E=0.12−0.30=−0.18; Keep: E=0.05−0.10=−0.05.
Answer: P(no disease∣test−). Probability of being healthy given negative test.
Answer: Option A, since EA=100⋅0.3=30>20=EB. Expected value calculation favors risky option over sure $20.
Answer: E(X)=∑xipi. Weighted average of outcomes by their probabilities.
Answer: P(A∣B)=P(B)P(B∣A)P(A). Updates prior probability using new evidence.
Answer: Test positive when the person is actually disease-free. False positive occurs when healthy person tests positive.
Answer: P(A∪B)=P(A)+P(B)−P(A∩B). Union probability adds individual probabilities, subtracts overlap.
Answer: P(A∩B)=P(A)P(B). For independent events, joint probability equals product of individual probabilities.
Answer: P(A∩B)=P(A)P(B∣A). Joint probability equals first event's probability times conditional probability.
Answer: Choose the option with the higher expected value. Maximizes expected gain or minimizes expected loss.
Answer: P(A∩B)=P(A)P(B∣A). Joint probability equals marginal times conditional.
Answer: specificity=P(−∣Dc). Specificity is probability of negative test given no disease.
Answer: P(Ac)=1−P(A). Complement probability is one minus the event probability.