Rates
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PSAT Math › Rates
A student types 540 words in 12 minutes at a constant rate. At this rate, how many words will the student type in 25 minutes?
$900\text{ words}$
$1125\text{ words}$
$1350\text{ words}$
$1620\text{ words}$
Explanation
We need to find how many words the student types in 25 minutes when typing 540 words in 12 minutes. First, find the typing rate: 540 words ÷ 12 minutes = 45 words per minute. Then multiply by 25 minutes: 45 words/minute × 25 minutes = 1125 words. The key is maintaining consistent units throughout the calculation. A common error is trying to set up a proportion without first finding the unit rate, which can lead to inverted fractions.
A hose fills a tank at a constant rate. It takes 18 minutes to fill 45 gallons. At this same rate, how many gallons will the hose fill in 26 minutes? Be careful not to divide 26 by 45 or to treat 45 as gallons per minute without dividing by 18.
$65\text{ gallons}$
$50\text{ gallons}$
$78\text{ gallons}$
$117\text{ gallons}$
Explanation
We need to find how many gallons the hose fills in 26 minutes at a constant rate. First, calculate the filling rate: 45 gallons ÷ 18 minutes = 2.5 gallons per minute. Then multiply by the new time: 2.5 gallons/minute × 26 minutes = 65 gallons. Common errors include dividing 26 by 45 (which gives a meaningless ratio) or treating 45 as the rate without dividing by 18. Always set up rates as quantity per unit time, then multiply by the desired time.
A cyclist rides 18 miles in 1.5 hours at a constant speed. If the cyclist keeps the same speed, how long will it take to ride 30 miles? Give your answer in hours.
$1.67\text{ hours}$
$2.0\text{ hours}$
$3.33\text{ hours}$
$2.5\text{ hours}$
Explanation
We need to find how long it takes to ride 30 miles at the same speed the cyclist used to ride 18 miles in 1.5 hours. First, calculate the cyclist's rate: rate = 18 miles ÷ 1.5 hours = 12 miles per hour. To find the time for 30 miles, use time = distance ÷ rate: time = 30 miles ÷ 12 miles/hour = 2.5 hours. A common error is to set up a proportion incorrectly or forget to find the rate first. When dealing with rate problems, always identify what quantity per what unit you're working with.
A grocery store sells almonds for $\$7.80$ for 3 pounds. What is the unit rate, in dollars per pound, for the almonds?
$\$10.80$ per lb
$\$2.60$ per lb
$\$3.90$ per lb
$\$2.00$ per lb
Explanation
The question asks for the unit rate of almonds in dollars per pound. The rate is cost per pound, specifically dollars per pound. Calculate the unit rate by dividing total cost by total pounds: $7.80 / 3 pounds = $2.60 per pound. Here, the units work out as dollars divided by pounds, directly giving dollars per pound. Emphasizing unit analysis helps confirm you're finding the cost for one pound correctly. A key error might be dividing pounds by cost instead, yielding pounds per dollar, which is the inverse rate, like 3/7.80 ≈ 0.385 pounds per dollar. For rate problems, double-check if the question asks for 'per unit' to ensure you have the correct numerator and denominator.
A runner completes 5 kilometers in 24 minutes at a constant pace. At this pace, how many minutes will it take to run 8 kilometers? (Round to the nearest whole minute.)
41 minutes
30 minutes
46 minutes
38 minutes
Explanation
The question asks how many minutes it will take to run 8 kilometers at the same constant pace, rounded to the nearest whole minute. The rate is pace, in minutes per kilometer or equivalently kilometers per minute. First, find the pace: 24 minutes / 5 kilometers = 4.8 minutes per kilometer. Then, for 8 kilometers: 8 km * 4.8 min/km = 38.4 minutes, which rounds to 38 minutes since 0.4 is less than 0.5. Unit analysis shows kilometers cancel, leaving minutes, emphasizing the importance of consistent units. A key error is setting up the proportion backwards, like using kilometers per minute incorrectly, leading to times like 15 minutes. For rounding in rate problems, always apply standard rules after calculating to ensure accuracy.
A water pump drains a tank at a constant rate. It removes 18 gallons every 4 minutes. At this rate, how many minutes will it take to drain 63 gallons?
$14\text{ min}$
$28\text{ min}$
$10.5\text{ min}$
$12\text{ min}$
Explanation
We need to find how long it takes to drain 63 gallons when the pump removes 18 gallons every 4 minutes. First, find the drainage rate: 18 gallons ÷ 4 minutes = 4.5 gallons per minute. Then find the time: 63 gallons ÷ 4.5 gallons/minute = 14 minutes. The key is recognizing this as a rate problem where we need gallons per minute first. A common mistake is setting up the proportion backwards, which would give minutes per gallon instead.
A recipe uses 2.5 cups of flour to make 20 muffins. At this rate, how many cups of flour are needed to make 32 muffins?
$8.0\text{ cups}$
$4.0\text{ cups}$
$3.2\text{ cups}$
$6.25\text{ cups}$
Explanation
We need to find how much flour is needed for 32 muffins when 2.5 cups make 20 muffins. First, find the rate of flour per muffin: 2.5 cups ÷ 20 muffins = 0.125 cups per muffin. Then multiply by 32 muffins: 0.125 cups/muffin × 32 muffins = 4.0 cups. This is a scaling problem where we find the unit rate first. Watch out for the temptation to use mental math shortcuts that might introduce rounding errors.
A job is completed at a constant rate. Worker A can paint a room in 6 hours, and Worker B can paint the same room in 8 hours. If they work together at their constant rates, how long will it take them to paint 1 room?
$3\tfrac{3}{7}$ hr
7 hr
$\tfrac{7}{24}$ hr
$\tfrac{24}{7}$ hr
Explanation
The question asks for the time to paint 1 room when two workers collaborate. Worker A's rate is 1/6 room per hour, and Worker B's rate is 1/8 room per hour. When working together, add their rates: 1/6 + 1/8 = 4/24 + 3/24 = 7/24 rooms per hour. To find time for 1 room, divide: 1 room ÷ (7/24 rooms/hour) = 1 × 24/7 = 24/7 hours. This equals 3 3/7 hours. The key insight is that rates add when workers collaborate, not times. Always work with rates (rooms per hour) rather than times (hours per room) when combining efforts.
A rideshare driver earns a base fee plus a constant amount per mile. On Monday, a 6-mile trip cost $14.50, and a 10-mile trip cost $22.50. Assuming the pricing is linear, what is the driver's charge per mile (the unit rate for miles) in dollars per mile?
$3.75 per mile
$2.00 per mile
$1.25 per mile
$0.50 per mile
Explanation
This question asks for the driver's charge per mile in dollars per mile, given a base fee and total costs for 6-mile and 10-mile trips in dollars. The total cost follows a linear relationship: cost = base fee + (miles) × (rate in dollars per mile). To find the rate, set up the equations base + 6m = 14.50 and base + 10m = 22.50, then subtract to eliminate the base: 4m = 8, so m = 2 dollars per mile. Unit analysis confirms dollars divided by miles yields dollars per mile, ensuring the rate is properly set up. A common error is dividing total cost by miles without accounting for the base fee, such as 14.50 / 6 ≈ 2.42, which ignores the fixed component. For linear rate problems with a y-intercept, always use the difference in costs over difference in miles to find the slope accurately.
A cyclist travels at a constant speed. In 18 minutes, the cyclist goes 4.5 miles. At this same rate, how many miles will the cyclist travel in 1 hour?
12 mi
15 mi
18 mi
9 mi
Explanation
This question asks how many miles a cyclist will travel in 1 hour (60 minutes) at a constant speed, given 4.5 miles in 18 minutes. The speed is constant, so distance = rate (in miles per minute) × time. First, find the rate: 4.5 miles / 18 minutes = 0.25 miles per minute; then for 60 minutes, distance = 0.25 miles/min × 60 min = 15 miles. Unit analysis: (miles per minute) × minutes cancels to miles, stressing proper rate and unit setup. A key error is forgetting to convert hours to minutes, like treating 1 hour as 1 unit without adjustment. For time unit mismatches in rates, convert everything to consistent units like minutes to avoid calculation errors.