Distributive Property

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PSAT Math › Distributive Property

Questions 1 - 10
1

Given the equation above, what is the value of ?

Explanation

Use FOIL to expand the left side of the equation.

From this equation, we can solve for , , and .

Plug these values into to solve.

2

Given the equation above, what is the value of ?

Explanation

Use FOIL to expand the left side of the equation.

From this equation, we can solve for , , and .

Plug these values into to solve.

3

Expand the expression:

\dpi{100} \small (x^{3}-4x)(6 + 12x^{2})

\dpi{100} \small 12x^{5}-42x^{3}-24x

\dpi{100} \small 42x^{3}+12x^{5}-24x

\dpi{100} \small 6x^{3} + 12x^{5}-24x-48x^{3}

\dpi{100} \small 6x^{3} + 12x^{2}-24x-48

\dpi{100} \small 22x^{2}

Explanation

When using FOIL, multiply the first, outside, inside, then last expressions; then combine like terms.

\dpi{100} \small (x^{3}-4x)(6 + 12x^{2})

\dpi{100} \small 6x^{3}+12x^{5}-24x-48x^{3}

\dpi{100} \small -42x^{3}+12x^{5}-24x

\dpi{100} \small 12x^{5}-42x^{3}-24x

4

Expand the expression:

\dpi{100} \small (x^{3}-4x)(6 + 12x^{2})

\dpi{100} \small 12x^{5}-42x^{3}-24x

\dpi{100} \small 42x^{3}+12x^{5}-24x

\dpi{100} \small 6x^{3} + 12x^{5}-24x-48x^{3}

\dpi{100} \small 6x^{3} + 12x^{2}-24x-48

\dpi{100} \small 22x^{2}

Explanation

When using FOIL, multiply the first, outside, inside, then last expressions; then combine like terms.

\dpi{100} \small (x^{3}-4x)(6 + 12x^{2})

\dpi{100} \small 6x^{3}+12x^{5}-24x-48x^{3}

\dpi{100} \small -42x^{3}+12x^{5}-24x

\dpi{100} \small 12x^{5}-42x^{3}-24x

5

Expand and simplify the expression.

Explanation

We can solve by FOIL, then distribute the . Since all terms are being multiplied, you will get the same answer if you distribute the before using FOIL.

First:

Inside:

Outside:

Last:

Sum all of the terms and simplify. Do not forget the in front of the quadratic!

Finally, distribute the .

6

Expand and simplify the expression.

Explanation

We can solve by FOIL, then distribute the . Since all terms are being multiplied, you will get the same answer if you distribute the before using FOIL.

First:

Inside:

Outside:

Last:

Sum all of the terms and simplify. Do not forget the in front of the quadratic!

Finally, distribute the .

7

If , , and , then

Explanation

To find what equals, you must know how to multiply times , or, you must know how to multiply binomials. The best way to multiply monomials is the FOIL (first, outside, inside, last) method, as shown below:

Multiply the First terms

Multiply the Outside terms:

Multiply the Inside terms:

Note: this step yields a negative number because the product of the two terms is negative.

Multiply the Last terms:

Note: this step yields a negative number too!

Putting the results together, you get:

Finally, combine like terms, and you get:

8

If , , and , then

Explanation

To find what equals, you must know how to multiply times , or, you must know how to multiply binomials. The best way to multiply monomials is the FOIL (first, outside, inside, last) method, as shown below:

Multiply the First terms

Multiply the Outside terms:

Multiply the Inside terms:

Note: this step yields a negative number because the product of the two terms is negative.

Multiply the Last terms:

Note: this step yields a negative number too!

Putting the results together, you get:

Finally, combine like terms, and you get:

9

Simplify the expression.

None of the other answers

Explanation

Solve by applying FOIL:

First: 2x2 * 2y = 4x2y

Outer: 2x2 * a = 2ax2

Inner: –3x * 2y = –6xy

Last: –3x * a = –3ax

Add them together: 4x2y + 2ax2 – 6xy – 3ax

There are no common terms, so we are done.

10

Simplify the expression.

None of the other answers

Explanation

Solve by applying FOIL:

First: 2x2 * 2y = 4x2y

Outer: 2x2 * a = 2ax2

Inner: –3x * 2y = –6xy

Last: –3x * a = –3ax

Add them together: 4x2y + 2ax2 – 6xy – 3ax

There are no common terms, so we are done.

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