PSAT Math Flashcards: Polynomial Equations

Study Polynomial Equations in PSAT Math with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

PSAT Math

Polynomial Equations

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What does the discriminant value b24ac>0b^2-4ac>0 imply about real solutions?

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ANSWER

Two distinct real solutions. Positive discriminant yields two different real roots.

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This deck focuses on Polynomial Equations, giving you a quick way to review the definitions, rules, and examples that matter most for PSAT Math.

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Flashcard 1: What does the discriminant value b24ac>0b^2-4ac>0 imply about real solutions?

Answer: Two distinct real solutions. Positive discriminant yields two different real roots.

Flashcard 2: What is the sum of the roots of x27x+10=0x^2-7x+10=0?

Answer: 77. For ax2+bx+c=0ax^2+bx+c=0, sum of roots equals ba-\frac{b}{a}.

Flashcard 3: Evaluate P(2)P(2) for P(x)=x34xP(x)=x^3-4x: what is P(2)P(2)?

Answer: 00. P(2)=234(2)=88=0P(2)=2^3-4(2)=8-8=0.

Flashcard 4: What is the factored form of x29x^2-9?

Answer: (x3)(x+3)(x-3)(x+3). Difference of squares: a2b2=(ab)(a+b)a^2-b^2=(a-b)(a+b).

Flashcard 5: Factor completely: x2+6x+9x^2+6x+9.

Answer: (x+3)2(x+3)^2. Perfect square trinomial: a2+2ab+b2=(a+b)2a^2+2ab+b^2=(a+b)^2.

Flashcard 6: Identify the solutions of x29=0x^2-9=0.

Answer: x=±3x=\pm 3. Factor as (x3)(x+3)=0(x-3)(x+3)=0, giving x=3x=3 or x=3x=-3.

Flashcard 7: What is the discriminant of ax2+bx+c=0ax^2+bx+c=0?

Answer: b24acb^2-4ac. Determines the nature and number of solutions.

Flashcard 8: What is the factorization of x210x+25x^2-10x+25?

Answer: (x5)2(x-5)^2. Recognize pattern: (5)2=25(-5)^2 = 25 and 2(5)=102(-5) = -10.

Flashcard 9: Solve x34x2+4x=0x^3-4x^2+4x=0.

Answer: x=0x=0 or x=2x=2. Factor out xx: x(x24x+4)=x(x2)2=0x(x^2-4x+4)=x(x-2)^2=0.

Flashcard 10: What is the zero-product property used to solve (x3)(x+5)=0(x-3)(x+5)=0?

Answer: If ab=0ab=0, then a=0a=0 or b=0b=0. A product equals zero only if at least one factor is zero.

Flashcard 11: What is the discriminant of ax2+bx+c=0ax^2+bx+c=0, and what does it determine?

Answer: b24acb^2-4ac; it determines the number of real solutions. Positive discriminant means 2 real solutions, zero means 1, negative means 0.

Flashcard 12: What is the discriminant for ax2+bx+c=0ax^2+bx+c=0, and what does it determine?

Answer: Discriminant b24acb^2-4ac; it determines the number of real solutions. Positive means 2 real roots, zero means 1, negative means 0.

Flashcard 13: What are the solutions of (x3)(x+5)=0(x-3)(x+5)=0?

Answer: x=3x=3 or x=5x=-5. Apply zero-product property: set each factor to zero.

Flashcard 14: Identify the solutions of (x3)(x+5)=0(x-3)(x+5)=0.

Answer: x=3x=3 or x=5x=-5. Set each factor to zero: x3=0x-3=0 gives x=3x=3, x+5=0x+5=0 gives x=5x=-5.

Flashcard 15: What is the factorization pattern for a perfect square trinomial a2+2ab+b2a^2+2ab+b^2?

Answer: a2+2ab+b2=(a+b)2a^2+2ab+b^2=(a+b)^2. Perfect square trinomial factors to squared binomial.

Flashcard 16: Identify the number of real solutions to x26x+9=0x^2-6x+9=0.

Answer: 11 real solution. (x3)2=0(x-3)^2=0 has repeated root.

Flashcard 17: What is the maximum number of real solutions a degree nn polynomial equation can have?

Answer: At most nn real solutions. By the Fundamental Theorem of Algebra, counting multiplicities.

Flashcard 18: Factor completely: x25x6x^2-5x-6.

Answer: (x6)(x+1)(x-6)(x+1). Find two numbers that multiply to 6-6 and add to 5-5.

Flashcard 19: What is the Factor Theorem stated using f(r)f(r) and (xr)(x-r)?

Answer: f(r)=0f(r)=0 if and only if (xr)(x-r) is a factor of f(x)f(x). Root rr means (xr)(x-r) divides f(x)f(x).

Flashcard 20: What is the factorization pattern for a perfect square trinomial a22ab+b2a^2-2ab+b^2?

Answer: a22ab+b2=(ab)2a^2-2ab+b^2=(a-b)^2. Perfect square with subtraction factors to squared difference.

Flashcard 21: How many real solutions does x2+4x+5=0x^2+4x+5=0 have?

Answer: 00 real solutions. Discriminant =1620=4<0=16-20=-4<0, so no real solutions exist.

Flashcard 22: What is the standard form of a polynomial equation in xx of degree nn?

Answer: anxn+an1xn1++a1x+a0=0a_nx^n+a_{n-1}x^{n-1}+\cdots+a_1x+a_0=0, an0a_n\neq 0. Standard form has terms in descending degree order with leading coefficient non-zero.

Flashcard 23: What is the degree of the polynomial 7x43x2+x97x^4-3x^2+x-9?

Answer: Degree 44. The degree is the highest exponent of the variable.

Flashcard 24: Solve the equation (x3)(x+5)=0(x-3)(x+5)=0.

Answer: x=3x=3 or x=5x=-5. Apply zero-product property: set each factor equal to zero.

Flashcard 25: Identify the remainder when p(x)=x34x+1p(x)=x^3-4x+1 is divided by (x2)(x-2).

Answer: 11. By Remainder Theorem: p(2)=234(2)+1=88+1=1p(2)=2^3-4(2)+1=8-8+1=1.

Flashcard 26: Identify the solutions of x2=49x^2=49.

Answer: x=7x=7 and x=7x=-7. Take square root of both sides.

Flashcard 27: How many real solutions does x2+4x+10=0x^2+4x+10=0 have?

Answer: 00 real solutions. Discriminant =1640=24<0=16-40=-24<0, so no real solutions.

Flashcard 28: What is the leading coefficient of 5x3+2x1-5x^3+2x-1?

Answer: 5-5. The leading coefficient is the coefficient of the highest degree term.

Flashcard 29: What is the relationship between a factor and a root (Factor Theorem)?

Answer: (xr)(x-r) is a factor iff f(r)=0f(r)=0. A polynomial has factor (xr)(x-r) exactly when rr is a root.

Flashcard 30: What is the factored form of the difference of squares a2b2a^2-b^2?

Answer: (ab)(a+b)(a-b)(a+b). This is the difference of squares factorization pattern.

Flashcard 31: If x=3x=3 is a solution of P(x)=0P(x)=0, what factor must P(x)P(x) have?

Answer: Factor (x3)(x-3). By the Factor Theorem, if P(3)=0P(3)=0, then (x3)(x-3) divides P(x)P(x).

Flashcard 32: What does the Remainder Theorem say is the remainder when dividing f(x)f(x) by (xc)(x-c)?

Answer: Remainder =f(c)=f(c). When dividing f(x)f(x) by (xc)(x-c), the remainder equals f(c)f(c).

Flashcard 33: Solve for xx: x34x2=0x^3-4x^2=0.

Answer: x=0x=0 or x=4x=4. Factor out x2x^2: x2(x4)=0x^2(x-4)=0, so x=0x=0 (double root) or x=4x=4.

Flashcard 34: What is the factored form of the perfect square trinomial a22ab+b2a^2-2ab+b^2?

Answer: (ab)2(a-b)^2. Perfect square with negative middle term factors as (ab)(a-b) squared.

Flashcard 35: What is the zero-product property used to solve factored equations?

Answer: If ab=0ab=0, then a=0a=0 or b=0b=0. At least one factor must equal zero for the product to be zero.

Flashcard 36: Identify the solutions of (x4)(x+1)=0(x-4)(x+1)=0.

Answer: x=4x=4 and x=1x=-1. Set each factor to zero: x4=0x-4=0 gives x=4x=4, x+1=0x+1=0 gives x=1x=-1.

Flashcard 37: What is the standard form of a polynomial in descending powers of xx?

Answer: anxn+an1xn1++a1x+a0a_nx^n+a_{n-1}x^{n-1}+\cdots+a_1x+a_0. Terms arranged from highest to lowest degree.

Flashcard 38: Solve x25x+6=0x^2-5x+6=0.

Answer: x=2x=2 or x=3x=3. Factor as (x2)(x3)=0(x-2)(x-3)=0, then apply zero-product property.

Flashcard 39: Identify the solutions of x2+2x3=0x^2+2x-3=0.

Answer: x=1x=1 and x=3x=-3. Factor as (x1)(x+3)=0(x-1)(x+3)=0.

Flashcard 40: What is the product of the roots of 3x2+6x9=03x^2+6x-9=0?

Answer: ca=93=3\frac{c}{a}=\frac{-9}{3}=-3. For ax2+bx+c=0ax^2+bx+c=0, product of roots equals ca\frac{c}{a}.

Flashcard 41: What is the degree of the polynomial 7x53x2+97x^5-3x^2+9?

Answer: 55. The degree is the highest power of xx in the polynomial.

Flashcard 42: Solve for xx: x25x+6=0x^2-5x+6=0.

Answer: x=2x=2 or x=3x=3. Factors to (x2)(x3)=0(x-2)(x-3)=0, giving these two solutions.

Flashcard 43: State the quadratic formula for solutions to ax2+bx+c=0ax^2+bx+c=0.

Answer: x=b±b24ac2ax=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Formula gives solutions to any quadratic equation ax2+bx+c=0ax^2+bx+c=0.

Flashcard 44: What is the definition of a polynomial in xx?

Answer: An expression anxn++a1x+a0a_nx^n+\cdots+a_1x+a_0 with nn a nonnegative integer. Each term has form aixia_ix^i where ii ranges from 0 to nn.

Flashcard 45: Use the Factor Theorem: if P(2)=0P(2)=0, what factor divides P(x)P(x)?

Answer: (x2)(x-2). By Factor Theorem, P(2)=0P(2)=0 means (x2)(x-2) is a factor.

Flashcard 46: Identify the zeros of f(x)=(x2)(x+5)f(x)=(x-2)(x+5).

Answer: x=2x=2 and x=5x=-5. Set each factor equal to zero: (x2)=0(x-2)=0 and (x+5)=0(x+5)=0.

Flashcard 47: What does it mean for rr to be a solution (root) of p(x)=0p(x)=0?

Answer: p(r)=0p(r)=0. When rr is substituted for xx, the polynomial equals zero.

Flashcard 48: Factor completely: x29x^2-9.

Answer: (x3)(x+3)(x-3)(x+3). Difference of squares: a2b2=(ab)(a+b)a^2-b^2=(a-b)(a+b).

Flashcard 49: Find the sum of the solutions of x27x+10=0x^2-7x+10=0 without solving fully.

Answer: 77. By Vieta's formulas, sum of roots equals negative coefficient of xx divided by leading coefficient.

Flashcard 50: How many real solutions does x2+4x+8=0x^2+4x+8=0 have?

Answer: 00 real solutions. Discriminant =1632=16<0=16-32=-16<0, so no real solutions.

Flashcard 51: Solve x25x+6=0x^2-5x+6=0.

Answer: x=2x=2 or x=3x=3. Factor as (x2)(x3)=0(x-2)(x-3)=0, then solve each factor.

Flashcard 52: What is the factored form of x2+6x+9x^2+6x+9?

Answer: (x+3)2(x+3)^2. Perfect square trinomial: a2+2ab+b2=(a+b)2a^2+2ab+b^2=(a+b)^2.

Flashcard 53: Solve for xx: x34x=0x^3-4x=0.

Answer: x=2x=-2, x=0x=0, or x=2x=2. Factor as x(x24)=x(x2)(x+2)=0x(x^2-4)=x(x-2)(x+2)=0.

Flashcard 54: State the zero-product property used to solve factored equations.

Answer: If ab=0ab=0, then a=0a=0 or b=0b=0. A product equals zero only if at least one factor is zero.

Flashcard 55: What is the factored form of x2+6x+9x^2+6x+9?

Answer: (x+3)2(x+3)^2. Perfect square trinomial: a2+2ab+b2=(a+b)2a^2+2ab+b^2=(a+b)^2.

Flashcard 56: What is the factored form of the perfect square trinomial a2+2ab+b2a^2+2ab+b^2?

Answer: (a+b)2(a+b)^2. Perfect square trinomial: first term squared plus twice the product plus last squared.

Flashcard 57: What is P(2)P(2) for P(x)=x34xP(x)=x^3-4x?

Answer: 00. Substitute: P(2)=234(2)=88=0P(2) = 2^3 - 4(2) = 8 - 8 = 0.

Flashcard 58: What does a discriminant b24ac<0b^2-4ac<0 imply about real solutions?

Answer: No real solutions. Negative discriminant means no real square roots exist.

Flashcard 59: What is the quadratic formula for ax2+bx+c=0ax^2+bx+c=0?

Answer: x=b±b24ac2ax=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Solves any quadratic equation when factoring is difficult.

Flashcard 60: What is f(2)f(2) for f(x)=x34x2+x+6f(x)=x^3-4x^2+x+6?

Answer: 00. f(2)=816+2+6=0f(2) = 8-16+2+6 = 0, confirming (x2)(x-2) is a factor.

Flashcard 61: What are the solutions of x2=49x^2=49?

Answer: x=7x=7 or x=7x=-7. Take square root of both sides: x=±49x=\pm\sqrt{49}.

Flashcard 62: Factor completely: x216x^2-16.

Answer: (x4)(x+4)(x-4)(x+4). Difference of squares: x242=(x4)(x+4)x^2-4^2=(x-4)(x+4).

Flashcard 63: What is the difference of squares factoring pattern?

Answer: a2b2=(ab)(a+b)a^2-b^2=(a-b)(a+b). Factors any expression of form a2b2a^2-b^2.

Flashcard 64: What are the solutions of x25x+6=0x^2-5x+6=0?

Answer: x=2x=2 or x=3x=3. Factor as (x2)(x3)=0(x-2)(x-3)=0 or use quadratic formula.

Flashcard 65: Which value is a root of f(x)=x34x2x+4f(x)=x^3-4x^2-x+4: x=1x=1 or x=2x=2?

Answer: x=1x=1. f(1)=141+4=0f(1)=1-4-1+4=0, so x=1x=1 is a root.

Flashcard 66: State the quadratic formula for solving ax2+bx+c=0ax^2+bx+c=0.

Answer: x=b±b24ac2ax=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Solves ax2+bx+c=0ax^2+bx+c=0 when factoring is difficult.

Flashcard 67: What is the definition of a polynomial equation in xx?

Answer: An equation setting a polynomial in xx equal to 00. A polynomial expression set equal to zero forms a polynomial equation.

Flashcard 68: How many real solutions does x2+4x+5=0x^2+4x+5=0 have?

Answer: 00. Discriminant =1620=4<0= 16-20 = -4 < 0, so no real solutions exist.

Flashcard 69: What is the leading coefficient of 4x3+2x1-4x^3+2x-1?

Answer: 4-4. The leading coefficient is the coefficient of the highest degree term.

Flashcard 70: Factor the trinomial x2+7x+12x^2+7x+12.

Answer: (x+3)(x+4)(x+3)(x+4). Find two numbers that multiply to 1212 and add to 77: 33 and 44.

Flashcard 71: What is the degree of the polynomial 7x43x2+x97x^4-3x^2+x-9?

Answer: 44. The degree is the highest exponent of the variable.

Flashcard 72: Solve x29=0x^2-9=0.

Answer: x=3x=3 or x=3x=-3. Factor as (x3)(x+3)=0(x-3)(x+3)=0, then apply zero product property.

Flashcard 73: What is the result of factoring x2+7x+12x^2+7x+12 completely?

Answer: (x+3)(x+4)(x+3)(x+4). Find two numbers that multiply to 1212 and add to 77: 33 and 44.

Flashcard 74: What is the constant term of 3x4x+83x^4-x+8?

Answer: 88. The constant term is the term without any variable.

Flashcard 75: What is the maximum possible number of real solutions to a degree nn polynomial equation?

Answer: At most nn real solutions. Fundamental Theorem: degree nn polynomial has at most nn roots.

Flashcard 76: Solve the polynomial equation (x4)(x+1)=0(x-4)(x+1)=0.

Answer: x=4x=4 or x=1x=-1. Set each factor to zero: x4=0x-4=0 or x+1=0x+1=0.

Flashcard 77: What is the leading coefficient of 5x3+2x1-5x^3+2x-1?

Answer: 5-5. The leading coefficient is the coefficient of the highest degree term.

Flashcard 78: Solve for xx: x26x+5=0x^2-6x+5=0.

Answer: x=1x=1 or x=5x=5. Factor as (x1)(x5)=0(x-1)(x-5)=0, then apply zero-product property.

Flashcard 79: What is the factorization pattern for a difference of squares a2b2a^2-b^2?

Answer: a2b2=(ab)(a+b)a^2-b^2=(a-b)(a+b). Difference of squares factors into sum times difference.

Flashcard 80: What is the Remainder Theorem for dividing f(x)f(x) by (xr)(x-r)?

Answer: The remainder equals f(r)f(r). Substitute rr into f(x)f(x) to get remainder.

Flashcard 81: How many real solutions does x2+4x+5=0x^2+4x+5=0 have?

Answer: 00 real solutions. Discriminant =1620=4<0=16-20=-4<0, so no real solutions.

Flashcard 82: What is the perfect square trinomial pattern for a2+2ab+b2a^2+2ab+b^2?

Answer: (a+b)2(a+b)^2. Recognizes when a trinomial is a perfect square.

Flashcard 83: Solve for xx: x2=16x^2=16.

Answer: x=±4x=\pm^4. Take square root of both sides: x=±16=±4x=\pm\sqrt{16}=\pm^4.

Flashcard 84: State the quadratic formula for solving ax2+bx+c=0ax^2+bx+c=0.

Answer: x=b±b24ac2ax=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Formula solves any quadratic equation.

Flashcard 85: What is the factored form of the difference of squares a2b2a^2-b^2?

Answer: (ab)(a+b)(a-b)(a+b). Difference of squares factors as product of sum and difference.

Flashcard 86: What is the quadratic formula for solutions of ax2+bx+c=0ax^2+bx+c=0?

Answer: x=b±b24ac2ax=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. General formula for solving any quadratic equation.

Flashcard 87: What is the discriminant of ax2+bx+c=0ax^2+bx+c=0, and what does it determine?

Answer: Discriminant b24acb^2-4ac; it determines the number of real solutions. Positive gives 2 real roots, zero gives 1, negative gives 0.

Flashcard 88: What is the sum of the solutions of x26x+11=0x^2-6x+11=0 using ba-\frac{b}{a}?

Answer: 66. For ax2+bx+c=0ax^2+bx+c=0, sum of roots equals ba=61=6-\frac{b}{a} = -\frac{-6}{1} = 6.

Flashcard 89: What is the discriminant of 2x23x+5=02x^2-3x+5=0?

Answer: 31-31. Calculate b24ac=(3)24(2)(5)=940b^2-4ac = (-3)^2-4(2)(5) = 9-40.

Flashcard 90: What does the Zero Product Property state for ab=0ab=0?

Answer: If ab=0ab=0, then a=0a=0 or b=0b=0. At least one factor must be zero.

Flashcard 91: State the zero-product property for ab=0ab=0.

Answer: If ab=0ab=0, then a=0a=0 or b=0b=0. A product equals zero only if at least one factor equals zero.

Flashcard 92: Identify the solutions of x25x+6=0x^2-5x+6=0.

Answer: x=2x=2 and x=3x=3. Factor as (x2)(x3)=0(x-2)(x-3)=0.

Flashcard 93: What is the complete factorization of x249x^2-49 over the integers?

Answer: (x7)(x+7)(x-7)(x+7). 49=7249 = 7^2, so apply difference of squares pattern.

Flashcard 94: Factor completely: x2+6x+9x^2+6x+9.

Answer: (x+3)2(x+3)^2. Recognizes as (x)2+2(x)(3)+(3)2(x)^2+2(x)(3)+(3)^2, a perfect square trinomial.

Flashcard 95: What is the degree of the polynomial 7x43x2+97x^4-3x^2+9?

Answer: 44. The degree is the highest power of the variable.

Flashcard 96: What is the product of the solutions of 2x2+3x5=02x^2+3x-5=0 using ca\frac{c}{a}?

Answer: 52-\frac{5}{2}. For ax2+bx+c=0ax^2+bx+c=0, product of roots equals ca=52\frac{c}{a} = \frac{-5}{2}.

Flashcard 97: What does a discriminant value b24ac<0b^2-4ac<0 imply about real solutions?

Answer: No real solutions. Negative discriminant means no real roots exist.

Flashcard 98: Identify the number of real solutions to x2+4x+5=0x^2+4x+5=0.

Answer: 00 real solutions. Discriminant 1620=4<016-20=-4<0.

Flashcard 99: What is the discriminant of ax2+bx+c=0ax^2+bx+c=0?

Answer: b24acb^2-4ac. Determines the nature and number of roots for quadratics.

Flashcard 100: State the quadratic formula for solutions of ax2+bx+c=0ax^2+bx+c=0.

Answer: x=b±b24ac2ax=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Solves any quadratic equation when a0a\neq 0.