Study Systems Of Polynomial Equations in PSAT Math with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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Flashcard 1: What is the elimination step when two equations are equal to y, such as y=f(x) and y=g(x)?
Answer: Subtract to get f(x)−g(x)=0. This creates a single equation to find where curves intersect.
Flashcard 2: What should you do after finding possible x-values from substitution in a system?
Answer: Substitute back to find y and verify. Find corresponding y-values and check both equations are satisfied.
Flashcard 3: Identify the best first step to solve y=2x+1 and x2+y2=5 using substitution.
Answer: Substitute y=2x+1 into x2+y2=5. Replace y in the circle equation to get a quadratic in x.
Flashcard 4: Solve the system y=x2−1 and y=0; what are the solution points?
Answer: (1,0) and (−1,0). Set x2−1=0: (x−1)(x+1)=0, so x=pm1.
Flashcard 5: Solve the system y=x2 and x+y=6 for (x,y).
Answer: (2,4) and (−3,9). Substitute y=6−x into y=x2 to get x2+x−6=0.
Flashcard 6: What are the intersection points of y=x2+1 and y=2x+1?
Answer: (0,1) and (2,5). Set x2+1=2x+1, which gives same x-values as x2=2x.
Flashcard 7: Solve the system x2+y2=4 and x=0 for all solutions (x,y).
Answer: (0,−2) and (0,2). Substitute x=0 into circle equation: y2=4, so y=±2.
Flashcard 8: What substitution step is used if a system includes y=f(x) and another equation in x and y?
Answer: Replace y with f(x) in the other equation. This substitution eliminates y to solve for x first.
Flashcard 9: What is the substitution method for a system like y=f(x) and y=g(x)?
Answer: Set f(x)=g(x), solve for x, then find y. Since both equal y, set right sides equal to eliminate y.
Flashcard 10: Identify the intersection points of y=x2 and y=x+2.
Answer: (−1,1) and (2,4). Substitute to get x2=x+2; solve x2−x−2=0.
Flashcard 11: Solve the system y=x2+1 and y=2x; what are the solutions?
Answer: (1,2). x2+1=2x gives x2−2x+1=0, so (x−1)2=0.
Flashcard 12: Find k so the system y=x2 and y=2x+k has exactly one real solution.
Answer: k=−1. Line tangent to parabola when discriminant of x2−2x−k=0 equals zero.
Flashcard 13: Solve the system y=x2 and y=−x; what are the solutions?
Answer: (0,0) and (−1,1). x2=−x gives x2+x=0, so x(x+1)=0.
Flashcard 14: What does it mean if substitution gives a contradiction such as 0=5?
Answer: No solution. The equations contradict each other, so no point satisfies both.
Flashcard 15: What is the elimination method for a polynomial system when terms can be canceled by adding equations?
Answer: Multiply as needed, then add or subtract equations to eliminate a variable. Scale equations so matching terms cancel when combined.
Flashcard 16: What method solves a system by adding or subtracting equations to eliminate a variable?
Answer: Elimination. Add/subtract equations to cancel out a variable.
Flashcard 17: Find the solutions to the system y=x+1 and y2=4.
Answer: (−3,−2) and (1,2). From y2=4, y=pm2, then find x values.
Flashcard 18: Solve the system y=x2−4x+3 and y=0; what are the solutions?
Answer: (1,0) and (3,0). Factor: (x−1)(x−3)=0 gives x=1,3 with y=0.
Flashcard 19: Identify the intersection points of y=x2 and y=4.
Answer: (2,4) and (−2,4). Set x2=4, so x=pm2 with y=4 for both.
Flashcard 20: What is the solution to the system x2+y2=25 and y=0?
Answer: (−5,0) and (5,0). Circle intersects x-axis where x2+02=25.
Flashcard 21: What equation represents the x-coordinates of intersection points of y=f(x) and y=g(x)?
Answer: Solve f(x)−g(x)=0 for x. Rearranging gives the equation whose roots are x-coordinates.
Flashcard 22: What does it mean if two polynomial equations have no real solution as a system?
Answer: Their graphs have no real intersection points. The curves don't touch or cross in the real coordinate plane.
Flashcard 23: What is the standard elimination step if you have p(x,y)=0 and q(x,y)=0 and one equation is linear in y?
Answer: Solve the linear equation for y and substitute into the other. This reduces the system to a single-variable equation.
Flashcard 24: Solve the system x2+y2=25 and y=0; what are the solution points?
Answer: (−5,0) and (5,0). Circle intersects x-axis where x2+02=25.
Flashcard 25: What are the x-values of intersection for y=x2 and y=4?
Answer: x=−2 and x=2. Solve x2=4 to get x=pm2.
Flashcard 26: What does each solution (x,y) of a polynomial system represent on a graph?
Answer: An intersection point of the graphs. Solutions occur where the curves meet.
Flashcard 27: What is the degree of the equation formed by substituting a linear equation into a cubic?
Answer: Degree 3 (a cubic in one variable). Linear substituted into cubic yields cubic.
Flashcard 28: What is the first step to solve y=x2+1 and y=2x+1 by substitution?
Answer: Set x2+1=2x+1. Since both equal y, set the right sides equal.
Flashcard 29: Identify the solution set of {y=2x+1y=x2+1.
Answer: {(0,1),(2,5)}. Set 2x+1=x2+1: x2−2x=0, factor to x(x−2)=0.
Flashcard 30: What is the standard substitution step after solving one equation for y in a system?
Answer: Replace y in the other equation with that expression, then solve for x. Substitution eliminates one variable by replacement.
Flashcard 31: What is the result of substituting y=2x−3 into x2+y2=13 (single equation in x)?
Answer: x2+(2x−3)2=13. Direct substitution expands to x2+4x2−12x+9=13.
Flashcard 32: What is the discriminant condition for exactly one intersection of y=ax2+bx+c and y=mx+n?
Answer: After setting equal, discriminant Δ=0. One solution means the resulting quadratic has discriminant zero.
Flashcard 33: What is the solution to the system y=x2−4 and y=0?
Answer: (−2,0) and (2,0). Find where parabola crosses x-axis by solving x2−4=0.
Flashcard 34: Identify the solution set of {y=x2y=x+2.
Answer: {(−1,1),(2,4)}. Set x2=x+2: x2−x−2=0, factor to (x−2)(x+1)=0.
Flashcard 35: Find the solutions to the system x+y=5 and xy=6.
Answer: (2,3) and (3,2). Solve quadratic x2−5x+6=0 from substitution.
Flashcard 36: What is the degree of the equation formed by eliminating y between a line and a parabola?
Answer: Degree 2. Line has degree 1, parabola has degree 2; product is 2.
Flashcard 37: What are the intersection points of y=x2 and y=4?
Answer: (−2,4) and (2,4). Substitute x=pm2 into either equation to get y=4.
Flashcard 38: What are the intersection points of y=x2 and y=x2+1?
Answer: No solution (it would require 0=1). Parallel parabolas never intersect.
Flashcard 39: What is the maximum possible number of real intersections of a line and a quadratic?
Answer: At most 2 real intersection points. A line crosses a parabola at most twice.
Flashcard 40: What do you do after finding an x-value from f(x)=g(x) in a system y=f(x), y=g(x)?
Answer: Substitute x into either equation to find the matching y. Use the x-value in either original equation to get y.
Flashcard 41: Solve the system x2+y2=1 and y=0 for all solutions (x,y).
Answer: (−1,0) and (1,0). Substitute y=0 into circle equation: x2=1, so x=±1.
Flashcard 42: What method solves a system by adding multiples of equations to eliminate a variable?
Answer: Elimination (linear combination). Add/subtract equations to cancel out a variable term.
Flashcard 43: Identify the maximum number of real intersection points of a line and a parabola.
Answer: 2. A line can intersect a parabola at most twice.
Flashcard 44: What are the solution points to y=x2 and y=−1?
Answer: No real solutions. Since x2≥0, it can never equal −1.
Flashcard 45: Identify the solution set of {y=x2−4y=0.
Answer: {(−2,0),(2,0)}. Set x2−4=0: x2=4, so x=±2.
Flashcard 46: Solve the system y=x2 and y=x2+1; how many solutions are there?
Answer: 0 solutions. Parallel parabolas (same shape, shifted vertically) never intersect.
Flashcard 47: What is the first step to solve the system y=x2 and y=2x+3 algebraically?
Answer: Set x2=2x+3. Since both equal y, equate the right-hand sides.
Flashcard 48: What are the solutions to the system y=x2 and y=2x?
Answer: (0,0) and (2,4). Substitute x=0 and x=2 into either equation for y.
Flashcard 49: What are the solution points to y=x2+1 and y=1?
Answer: (0,1). Solve x2+1=1: only x=0 works.
Flashcard 50: What does it mean if f(x)−g(x) has no real roots when solving f(x)=g(x)?
Answer: No real intersection points; the system has no real solutions. The curves never meet in the real plane.
Flashcard 51: What are the intersection points of y=x2 and y=−x?
Answer: (0,0) and (−1,1). Solve x2=−x to get x2+x=0, so x(x+1)=0.
Flashcard 52: What method solves a system by replacing one variable using an equation like y=x2?
Answer: Substitution. Replace one variable with its expression from another equation.
Flashcard 53: What are the intersection points of y=x2 and y=2x?
Answer: (0,0) and (2,4). Substitute x=0 and x=2 into either equation to find y.
Flashcard 54: Solve the system y=(x−1)2 and y=x+1 for (x,y).
Answer: (1,2) and (4,5). Expand and set (x−1)2=x+1; solve x2−3x=0.
Flashcard 55: Solve the system y=x2−1 and y=0; what are the solutions?
Answer: (1,0) and (−1,0). x2−1=0 gives x=±1, then y=0 for both.
Flashcard 56: Solve the system y=x2 and y=x for all solutions (x,y).
Answer: (0,0) and (1,1). Set x2=x to get x(x−1)=0, so x=0 or x=1.
Flashcard 57: Solve the system y=2x and y=x2 for all real solutions.
Answer: (0,0) and (2,4). Set 2x=x2: x2−2x=x(x−2)=0, so x=0 or x=2.
Flashcard 58: Find the solution points to y=x2 and y=2x.
Answer: (0,0) and (2,4). Solve x2=2x: x(x−2)=0, giving x=0,2.
Flashcard 59: What does it mean if f(x)−g(x) is the zero polynomial when solving f(x)=g(x)?
Answer: Infinitely many solutions; the equations represent the same curve. The two equations describe identical curves.
Flashcard 60: Find the solutions to the system x−y=1 and x2−y2=5.
Answer: (3,2). Factor as (x+y)(x−y)=5 with x−y=1.
Flashcard 61: Solve the system y=x2+2 and y=2x+2 for all solutions (x,y).
Answer: (0,2) and (2,6). Set x2+2=2x+2 to get x2−2x=0, so x=0 or x=2.
Flashcard 62: What does it mean if f(x)−g(x) factors as (x−a)2 when solving f(x)=g(x)?
Answer: x=a is a double root; the graphs are tangent there. The curves touch but don't cross at x=a.
Flashcard 63: What do the real solutions of a system f(x)=g(x) represent on a graph?
Answer: The x-coordinates of intersection points. Where the graphs intersect, their x-values are the solutions.
Flashcard 64: Solve the system y=x2 and x+y=0; what are the solution points?
Answer: (0,0) and (−1,1). Substitute y=−x into y=x2: −x=x2, so x2+x=0.
Flashcard 65: Solve the system y=x2−2 and y=x; what are the solutions?
Answer: (−1,−1) and (2,2). x2−2=x gives x2−x−2=0, factoring to (x+1)(x−2)=0.
Flashcard 66: Solve the system y=x2 and y=2x; what are the solution points?
Answer: (0,0) and (2,4). From x2=2x: x(x−2)=0, so x=0 or x=2.
Flashcard 67: What does a solution (x,y) to a system of two polynomial equations represent on a graph?
Answer: An intersection point of the two graphs. Solutions occur where both curves meet.
Flashcard 68: Solve the system x+y=5 and x2+y2=13; what are the solution points?
Answer: (2,3) and (3,2). Substitute y=5−x into circle equation and solve quadratic.
Flashcard 69: What is the maximum possible number of real solutions to a system of two quadratic equations?
Answer: 4. Two parabolas can intersect at most 4 times.
Flashcard 70: Solve the system y=x2+2 and y=x; how many real solutions are there?
Answer: 0 real solutions. x2+2=x gives x2−x+2=0; discriminant is negative.
Flashcard 71: What is the elimination step if you have y=f(x) and y=g(x) in a system?
Answer: Set f(x)=g(x). Since both equal y, set the expressions equal to each other.
Flashcard 72: Identify the first step to solve y=x2 and y=2x using substitution.
Answer: Set x2=2x. Since both equal y, equate the right sides.
Flashcard 73: Identify the number of real solutions to x2+y2=1 and y=2.
Answer: 0. Line y=2 is outside unit circle centered at origin.
Flashcard 74: What does it mean if a system has exactly one real solution?
Answer: The graphs intersect at exactly one real point. This is the unique solution to the system.
Flashcard 75: Identify the polynomial equation in x after eliminating y: y=x2+1 and y=3x−2.
Answer: x2+1=3x−2. Set the two y-expressions equal to eliminate y.
Flashcard 76: What are the solution points to y=x2 and y=x2?
Answer: Infinitely many solutions: all points on y=x2. Identical equations mean every point on the curve satisfies both.
Flashcard 77: What is the maximum number of real intersection points between a line and a parabola?
Answer: At most 2. A quadratic equation has at most 2 real roots.
Flashcard 78: What are the solutions to the system x2+y2=25 and y=0?
Answer: (−5,0) and (5,0). Circle intersects x-axis where x2=25.
Flashcard 79: What method solves a system by setting y=f(x) from both equations and equating them?
Answer: Substitution: set f(x)=g(x) after isolating the same variable. Both equations express y in terms of x, so equate the expressions.
Flashcard 80: What is the maximum number of real intersection points of y=x2 and y=ax+b?
Answer: 2. A parabola and line can intersect at most twice.
Flashcard 81: What is the maximum possible number of real intersection points of y= quadratic and y= cubic?
Answer: At most 3 real intersection points. A cubic minus a quadratic yields a cubic with at most 3 roots.
Flashcard 82: What is the maximum possible number of real intersections of y=x3 and y=mx+b?
Answer: 3. A cubic and line can intersect at most three times.
Flashcard 83: What is the substitution step if you have y=x2 and y=2x+3?
Answer: Set x2=2x+3. Substitute to eliminate y since both expressions equal y.
Flashcard 84: What are the x-values solving the system y=x2 and y=2x?
Answer: x=0 or x=2. Solve x2=2x: x(x−2)=0.
Flashcard 85: Solve the system x2+y2=25 and y=4 for (x,y).
Answer: (3,4) and (−3,4). Substitute y=4 into the circle equation: x2+16=25.
Flashcard 86: What are the x-values of solutions to y=x2 and y=x?
Answer: x=0 or x=1. Solve x2=x: x(x−1)=0.
Flashcard 87: What does it mean if two polynomial equations have infinitely many solutions as a system?
Answer: The equations define the same curve (are equivalent). One equation is a multiple of the other, so they're the same curve.
Flashcard 88: Identify the solutions to x2+y2=25 and y=0.
Answer: (5,0) and (−5,0). Circle intersects x-axis where x2=25.
Flashcard 89: Solve the system y=x2+1 and y=x2+1; how many solutions are there?
Answer: Infinitely many solutions. Identical equations represent the same curve.
Flashcard 90: Identify the number of real intersections if x2+1=x.
Answer: 0 real intersections. Rearranging gives x2−x+1=0 with negative discriminant.
Flashcard 91: What is the solution set to the system y=x2 and y=x2?
Answer: Infinitely many solutions: all points on y=x2. Same equation twice means every point on curve satisfies both.
Flashcard 92: What are the solutions to the system x2+y2=1 and y=0?
Answer: (1,0) and (−1,0). Substitute y=0 into circle equation: x2=1.
Flashcard 93: Identify the system's solutions in the coordinate plane when y=f(x) and y=g(x) are given.
Answer: All intersection points (x,y) of the two graphs. Solutions occur where the curves meet in the plane.
Flashcard 94: Identify the best first step to solve the system y=x2+1 and y=3x+1.
Answer: Set x2+1=3x+1. Since both equal y, set the expressions equal.
Flashcard 95: Solve the system x2+y2=25 and y=3; what are the solution points?
Answer: (4,3) and (−4,3). Substitute y=3: x2+9=25, so x2=16, x=±4.
Flashcard 96: What are the solution points to y=x2 and y=−x?
Answer: (0,0) and (−1,1). Solve x2=−x: x(x+1)=0, so x=0 or x=−1.
Flashcard 97: Identify the number of solutions if the system is y=x2+2x+1 and y=(x+1)2.
Answer: Infinitely many solutions. Both equations represent the same parabola: (x+1)2=x2+2x+1.
Flashcard 98: Identify the degree of the equation formed after substitution: y=x2 into y=3x+1.
Answer: 2 (it becomes x2=3x+1). Substituting gives x2=3x+1, which has degree 2.
Flashcard 99: Which equation in x results from eliminating y in x+y=5 and xy=6?
Answer: x(5−x)=6. Substitute y=5−x from first equation into second equation xy=6.
Flashcard 100: Identify the number of real solutions to y=x2 and y=1.
Answer: 2. Solve x2=1 to get x=pm1.